**A. An Overlap Value.**

$$c = -30 \text{ mm},$$

$$\begin{array}{l} q = \left(c + \frac{h\_0}{2}\right) \frac{\sin\left(\theta\_1 + \theta\_2\right)}{\sin\theta\_1 \sin\theta\_2} - \frac{h\_1}{2 \sin\theta\_1} - \frac{h\_2}{2 \sin\theta\_2} = \\ \left(-30 + \frac{120}{2}\right) \frac{1.0}{0.7698 \cdot 0.6431} - \frac{60}{2 \cdot 0.7698} - \frac{80}{2 \cdot 0.6431} = -40.6 \text{ mm}, \end{array}$$

$$p = h\_1 / \sin\theta\_1 = 60 / 0.7698 = 77.9 \text{ mm},$$

$$\lambda\_{0\upsilon} = (q/p) \cdot 100\% = (40.6 / 77.9) \cdot 100\% = 52.1 \text{ }\% < \lambda\_{0\upsilon, \text{lim}} = 80\%.$$

### **B. The Design Conditions.**

 $\frac{h\_1}{t\_1} = \frac{60}{3} = 20.0 < 35, \frac{b\_1}{t\_1} = \frac{50}{3} = 16.7 < 35, \frac{h\_2}{t\_2} = \frac{80}{4} = 20.0 < 35,$ 
$$\frac{b\_2}{t\_2} = \frac{60}{4} = 15.0 < 35,$$

$$\frac{h\_1}{b\_1} = \frac{60}{50} = 1.2 > 1.0, \frac{h\_2}{b\_2} = \frac{80}{60} = 1.33 > 1.0.$$
