*4.3. Mass Transfer Rate*

Sherwood number *Shx* is defined as

$$S\_{hx} = \frac{xh\_W}{D\_B(C\_w - C\_\infty)}\tag{24}$$

$$h\_w = \left. -D\_B \mathbb{C}\_y \right|\_{y=0} \tag{25}$$

$$\text{Re}\_x^{-1/2} \text{Sh}\_x = -\text{g}'(0) \tag{26}$$
