*3.3. Stick Close to the Best Solution*

The search agent could even establish its position as the leading search agent.

$$\stackrel{\rightarrow}{P}\_p(\propto) = \begin{cases} \stackrel{\rightarrow}{FS} + \stackrel{\rightarrow}{A} \times \stackrel{\rightarrow}{PD}, \text{ if } rand \ge 0.5\\ \stackrel{\rightarrow}{FS} - \stackrel{\rightarrow}{A} \times \stackrel{\rightarrow}{PD}, \text{ if } rand < 0.5 \end{cases} \tag{9}$$

The position of all the tunicates is updated with respect to the position of the first two tunicates as follows:

$$
\stackrel{\rightarrow}{P}\_p(\mathbf{x} + \mathbf{1}) = \frac{\stackrel{\rightarrow}{P}\_p(\mathbf{x}) + \stackrel{\rightarrow}{P}\_p(\mathbf{x} + \mathbf{1})}{2 + c\_1} \tag{10}
$$

where → *Pp*(*x* + 1) represents the updated position of the tunicates.
