Ftabular = F0.05 =Ftabular < Fcalculated

The significance of partial regression coefficients was assessed using t-criteria (Student's) for the first coefficient (Formula (22)),

$$t\_{a\_1} = \frac{a\_1}{\mu\_{a\_1}} = \frac{0.33}{0.019} = 17.83\tag{22}$$

$$\mu\_{a\_1} = \frac{\delta\_{\text{general}}}{\delta\_{\text{x\_1}} \times \sqrt{n}} = \frac{\delta\_y \times \sqrt{1 - R^2}}{\delta\_{\text{x\_1}} \times \sqrt{n}} = 0.019$$

$$t\_{a\_1} = \frac{a\_1}{\mu\_{a\_1}} = \frac{0.33}{0.019} = 17.83$$

$$\mu\_{\mathfrak{a}\_1} = \frac{\delta\_{\text{general}}}{\delta\_{\mathfrak{x}\_1} \times \sqrt{n}} = \frac{\delta\_{\mathfrak{y}} \times \sqrt{1 - R^2}}{\delta\_{\mathfrak{x}\_1} \times \sqrt{n}} = 0.0191$$

and for the second coefficient (Formula (23)),

$$t\_{a\_2} = \frac{a\_2}{\mu\_{a\_2}} = \frac{1.13}{0.024} = 47.28\tag{23}$$

$$\mu\_{a\_2} = \frac{\delta\_{\text{general}}}{\delta\_{\text{x\_2}}} = \frac{\delta\_y \times \sqrt{1 - R^2}}{\delta\_{\text{x\_2}} \times \sqrt{n}} = 0.024$$

To assess the degree of influence of factors on the result, in addition to the correlation coefficient, we calculated it using the multiple correlation index (Formula (24)):

$$\eta\_{yx\_1x\_2} = \sqrt{\frac{\delta\_{reconstruction}^2}{\delta\_y^2}} = \sqrt{\frac{148400.01}{149529.13}} = 0.966\tag{24}$$

$$\delta\_{reconstruction}^2 = \frac{\sum (\circ - \overline{\circ})^2}{n} = \frac{2226000.2}{15} = 148400.01$$

$$\delta\_y^2 = \overline{\jmath}^2 - \overline{\jmath}^2 = 149529.13$$
