**Appendix B. The Number of TEA Droplets in 1 cm<sup>3</sup>**

The number of droplets, *N*, is determined by the ratio

$$N = \frac{\mathfrak{n}\_{\rm TEA}}{\mathfrak{n}\_{\rm TEA,d}} , \text{ cm}^{-1}$$

where *n*TEA is the number of TEA molecules in 1 cm<sup>3</sup> ; *n*TEA,d is the number of such molecules in one droplet. Considering that the number *n*TEA is 10.5 times less than the number of oxygen molecules in air, *n*O<sup>2</sup> = 0.21*NA*/22, 400 cm−<sup>3</sup> , one obtains *n*TEA = *n*O<sup>2</sup> /10.5. The number *n*TEA,d is equal to the ratio of the droplet mass, 4*πr* 3 *d ρd*/3, to the mass of one TEA molecule, equal to *<sup>W</sup>*TEA/*NA*, where *<sup>ρ</sup><sup>d</sup>* <sup>≈</sup> 0.83 g/cm<sup>3</sup> [1] is the drop density, and *W*TEA = 114 g is the molecular mass of TEA. Substitution of all indicated quantities and *<sup>r</sup><sup>d</sup>* <sup>=</sup> <sup>5</sup> <sup>×</sup> <sup>10</sup>−<sup>3</sup> cm into the equation for *N* gives *N* = 210 cm−<sup>3</sup> .

#### **References**

