Proof. Before stating the proof of Theorem 1, we introduce the notion of a contact Hamiltonian function. Let
M be a smooth manifold without boundary and let
be a contact form on
M (
). A Reeb vector field
is the unique vector field which satisfies
For any smooth function
, there exists only one contact vector field
which satisfies
In fact,
is a contact vector field if and only if
holds (
is the Lie derivative). So,
holds for any
. Because
is non-degenerate on
, above equation determines
uniquely.
is the contact vector field associated to the contact Hamiltonian function
h. We denote the time
t flow of
by
and time 1 flow of
by
.
Let
be a contact manifold without boundary. We fix a point
and a sufficiently small open neighborhood
of
p. Let
be a coordinate of
. Let
be a contact form
on
. By using the famous Moser’s arguments, we can assume that there exists an open neighborhood of the origin
and a diffeomorphism
which satisfies
So, we first prove the theorem for and apply this to .
We fix
and
so that
holds. Let
be a contact Hamiltonian function. Then its contact Hamiltonian vector field
can be written in the following form
Let
be a quadric function
We define a contact Hamiltonian function
h on
V by
Here, and are smooth functions which satisfy the following five conditions.
,
There exists an unique
which satisfies the following conditions
,
Then, we can prove the following lemma.
Lemma. 1. Let be a contact Hamiltonian function as above. Then,holds if and only ifholds. Proof of Lemma 1. In order to prove this lemma, we first calculate the behavior of the function
for a fixed
(Here,
z is the
-th coordinate of
).
In the last inequality, we used the condition 2. So, this inequality implies that
holds.
Next, we study the behavior of
and
. Let
be the projection
Then,
can be decomposed into the angular component
and the radius component
as follows
Let
be the complex coordinate of
(
). Then, the angular component causes the following rotation on
, if we ignore the
z-coordinate,
By conditions 2, 3, and 5 in the definition of and , is at most and the equality holds if and only if holds. On the circle , is the -rotation of the circle . This implies that Lemma 1 holds. □
Next, we perturb the contactomorphism
. Let
be a coordinate of
as follows
We fix
. Then
is a contact Hamiltonian function on
and its contact Hamiltonian vector field can be written in the following form
So
only changes the
r of
-coordinate and
z-coordinate as follows
We fix two small open neighborhoods of the circle
as follows
We also fix a cut-off function
which satisfies the following conditions
We will use the last condition in the proof of Lemma 2. Then, is defined on . We denote this contact Hamiltonian function by . We define by the composition .
Lemma. 2. We take sufficiently small. We define points by Then has only one point .
Proof of Lemma 2. The proof of this lemma is as follows. On
,
only changes the
r-coordinate of
and
z-coordinate. So,
increases the angle of each
coordinate at most
and the equality holds on only
. On the circle
, the fixed points of
are 2
k points
. From the arguments in the proof of Lemma 1, this implies that
holds and this is the only element of
on
. So, it suffices to prove that this is the only element in
if
is sufficiently small. We prove this by contradiction. Let
be a sequence which satisfies
. We assume that there exists a sequence
We may assume without loss of generality that
holds because
holds. We may assume that
converges to a point
. Then,
holds. If
,
increases the angle of every
coordinate less than
and this contradicts
. Thus
holds. Because we assumed
on
,
implies that
holds. Let
be a large integer so that
holds. Then,
implies that
holds for
and
holds. This contradicts Lemma 1 because
. So, we proved Lemma 2. □
We assume that is sufficiently small so that the conclusion of Lemma 2 holds and we define by . Thus, we have constructed which does not admit a square root for each . Without loss of generality, we may assume that holds. Then converges to .
Finally, we prove Theorem 1. We define
for
as follows. Recall that
F is a diffeomorphism which was defined in Equation
.
Lemma 2 implies that
holds. Proposition 1 implies that
does not admit a square root. Because
is any point and
U is any small open neighborhood of
p, we proved Theorem 1. □