The analysis of optical cable winch systems involves a multi-physics field coupling problem. Theoretical and control equations of the electromagnetic thermal field are described during numerical simulation.
2.1. Electromagnetic Field Analysis of NAOCWS
When the NAOC is supplied with alternating current, the metal part of the cable generates eddy current loss due to the cable core and metal shield being subjected to an alternating magnetic field. On a macroscopic level, electromagnetic phenomena can be explained by the system of Maxwell’s equations [
23]. Its essential variables include magnetic field strength
H, electric field strength
E, magnetic field density
B and electric displacement vector
D. The source variables include current density
J and charge density
ρ. As a result, Equation (1) represents Maxwell’s differential form for the electromagnetic field of the optoelectronic cable. In this article, we use bold letters for vectors.
where
is vector differential operator,
Je is the eddy current density and
Js is current density. To characterize the macroscopic electromagnetic properties, one can express the parameters of Maxwell’s equations and the relationship between the relevant field quantities as shown in Equation (2):
where
ε is the dielectric constant,
μ is the magnetic permeability and
σ is the conductivity. Combining Maxwell equations in a frequency domain, magnetic field intensity vectors can be defined as Equation (3) [
24,
25]:
where
A represents the vector magnetic potential. Based on Maxwell’s equations, the vector magnetic potential equations for each layer of the cable are derived as shown in Equation (4) [
26]:
where
represent the vector magnetic potentials of the cable’s core, insulation, metal shield, aramid and outer sheath, respectively, as shown in
Figure 2.
The electro-magnetic-thermal multi-physics coupling model for an NAOCWS begins with the identification of the total heat source. In the process of heating and heat dissipation to equilibrium, control equations are used to describe the loading current in the conductor, heat transfer in fluids and solids, and electro-thermal coupling. The total heat sources of an NAOCWS include copper conductor current losses, metal shielding losses and insulation dielectric losses.
According to the international standard IEC 60287, the formula for copper core loss per unit length is shown in Equation (5) [
27]:
where
W1 is the resistance loss per unit length of the copper conductor, W/m;
I is the load current of the copper conductor, A;
R is the AC resistance per unit length at a given temperature, Ω/m;
r is the DC resistance of the conductor core at a given temperature, Ω/m;
ys is the skin effect coefficient; and
yp is the proximity effect coefficient.
The DC resistance
r of the conductor core is shown in Equation (6):
where
r indicates the DC resistance per unit length of NAOC at
T0 °C, Ω/m;
r20 is the DC resistance of a copper conductor at 20 °C, Ω/m; and
α is the temperature coefficient of resistance of the copper conductor; it is 0.37% here [
28]. The conductivity of the copper conductor is shown in Equation (7):
where
is the conductivity of copper, S/m;
L is the length of the NAOC, m; and
s is the cross-sectional area of the copper conductor, m
2.
The skin effect coefficient and the proximity effect coefficient of the NAOC relationship are shown in Equations (8) and (9), respectively:
where
f is the AC power supply frequency, Hz; and
Ks is a constant, determined by the structure of the cable core; it is 1 here.
where
dc is the outside diameter of the cable core;
s is the distance between the centre axes of each cable core, m; and
Kp is a constant, determined by the core structure of the cable; it is 0.8 here.
The currents in the three copper cores are shown in Equation (10):
where
Ia,
Ib and
Ic represent the currents in the three conductors, respectively;
I0 indicates the given current; and
j is the imaginary unit.
Losses in the metal shield of the NAOC consist mainly of circulating current losses and eddy current losses. The metallic shield loss is obtained by calculating the ratio of the metallic sheath loss to the conductor loss of the NAOC, i.e., the metallic sheath loss factor
λ1.
where
represents the circulating current loss factor and
represents the eddy current loss factor. Metal shield grounding inside an NAOC shows negligible loop current losses. The eddy current loss factor is shown in Equation (12) [
29]:
where
is the resistance of the metal shield at operating temperature, Ω/m;
X is the reactance per unit length of the metal shield, Ω/m;
s is the distance between the axes of the conductors, mm;
d is the average diameter of the metal shield, mm;
is the resistivity of the metal sheath, S/m;
T′ is the working temperature of the shield, °C;
AS is the ratio of shield temperature to conductor temperature;
αs is the temperature coefficient of resistance of the shield, because the shield of a non-metallic armoured cable is copper,
αs = α. Therefore, the metal shield loss is as shown in Equation (13):
The dielectric loss of NAOC insulation is shown in Equation (14) [
30]:
where
W3 is the dielectric loss power, W;
ω = 2
πf;
f = 50 Hz;
C0 is the capacitance of the NAOC per unit length, F/m;
U0 is the phase voltage of the conductor, V; tan
δ is the loss factor of insulation;
is the dielectric constant of the insulating material;
Di is the diameter of the insulating material, mm; and
d1 is the diameter of the copper conductor, mm.
2.2. Heat Transfer Method for NAOCWS
When the NAOC is wound in multiple layers on a winch, heat primarily transfers through conduction between the cable and the winch. According to the law of conservation of energy, thermal energy is transported in non-metallic armoured cables between the inflow and outflow of a medium. This energy is transferred to the layers of the cable sequentially, achieving a balance within the cable’s medium, as shown in Equation (15):
where
is the heat inflow from the system,
is the heat outflow from the system,
is the heat generated by the system and
U is the increment of internal energy.
There are three basic modes of heat transfer in an NAOCWS: heat conduction, heat convection and heat radiation. This transfer occurs in the form of heat conduction, where thermal conductivity is dominated by heat transfer between solids. In these situations, the temperature field and current-carrying capability of the cable must be determined by coupling the two physical fields, the electromagnetic field and the temperature field. The process of heat conduction in a solid can be described by Fourier’s law, which applies to its microscopic elements. Additionally, it can be expressed by the law of conservation of energy and its continuity control equation. Heat conduction is the process by which heat moves through a medium from a hot spot to a cold spot as a result of a temperature differential. It is a fundamental heat transfer phenomenon [
31]. According to Fourier’s law, the heat flow density
q is directly proportional to the temperature change rate in that direction, as demonstrated in Equation (16):
where
q is the heat flow density, W/m
2;
is the heat flux through area
A′, W; and λ is the coefficient of thermal conductivity, W/(m∙K). The formula, also known as Fourier’s law, shows that the larger the
λ, the better its thermal conductivity.
Thermal convection is the process of heat transfer between fluids or between the fluid and the solid when the fluid is in motion, and it is caused by a temperature difference between them. In the two-dimensional plane, the heat convection between air and the NAOCWS can be regarded as convection in a circular heat dissipation region. In order to determine the convection heat transfer coefficient, it is necessary to determine the state of the air flow. According to the Reynolds number, the state of air flow can be divided into three categories: laminar flow, transitional state and turbulent flow [
32]. The Reynolds number
Re for convective heat transfer in air is given by Equation (17):
where
v,
ρ′ and
μ′ are the flow rate, density and viscosity coefficient of the air, respectively, and
d is the characteristic length of the heat dissipation region. Because the heat dissipation area is circular,
d is the diameter of the heat dissipation area.
If the air is turbulent, the process can be modelled through uniform out-of-plane convective losses
[
32].
where
is the air’s mass flow rate;
;
ρ is the density of air;
v is the velocity of the air;
A″ is the area of the heat dissipation area;
is the air’s specific heat capacity;
is the air’s intake temperature;
T is the temperature of the system;
V is the air’s volume,
; and
r1 is the radius of the heat dissipation area.
Thermal radiation manifests as electromagnetic waves, which propagate through space. The quantity of heat emitted increases with the internal energy generated by higher temperatures. Unlike heat conduction and convection, thermal radiation transfers heat in the form of electromagnetic waves, even in a vacuum, without necessitating a medium [
33]. The radiant energy that an idealized blackbody can absorb per unit time is shown in Equation (19):
where
is the object’s area,
β is the Stefan–Boltzmann constant and
T′ is the object’s temperature. According to the formula, an object’s radiative capacity is directly related to the product of its temperature and surface area. When the temperature of a non-metallic armoured cable’s surface is
and the surrounding air temperature is
, heat is radiated between the cable and the air, as shown in Equation (20). The equation demonstrates the relationship between the two temperatures.
where
is the emissivity of air and does not exceed 1.
The initial ambient temperature is set to 90 °C.