4.1. Properties of Topological NHC Measures
There is a relationship between the k-hyperconvex topological subspaces and the first-countable property of a Hausdorff topological space. This interrelationship is presented in the following theorem.
Theorem 5. In a topological space if is a finite hyperconvex neighborhood system at then it is a Noetherian hyperconvex class if is a first-countable non-compact topological space.
Proof. Let be a first-countable topological space, where is an arbitrary point. A local hyperconvex neighborhood system at is given by such that one can find a bijection . The corresponding Noetherian hyperconvex class is at . If we consider that then we can find a corresponding such that if, and only if, is non-compact and is open. Moreover, according to the definition such that in . Inductively, it can be concluded that and such that in non-compact . Hence, the local neighborhood system is a Noetherian hyperconvex class where and is finitely countable. □
Remark 4. Note that a first-countable topological space may admit a k-finite k-hyperconvex class. It is important to note that a non-convex Hausdorff topological space need not always admit a Noetherian hyperconvex class of for at any arbitrary within the space irrespective of the compactness of . The reason is that if is not a convex neighborhood of in the compact non-convex then ; otherwise if is non-convex as well as non-compact, then . This results in the following corollary, which is a stronger property.
Corollary 1. A Noetherian admits hyperconvex in a compact Hausdorff and first-countable if, and only if, is a countable finite cover of , where each is a convex subcover of .
The topological ordering relation between the two spaces maintains the respective NHC structures. However, the relation also preserves the hyperconvexity in the NHC in the codomain of continuous . The following theorem presents this property.
Theorem 6. If and are first-countable topological spaces with hyperconvex and , then is also hyperconvex in .
Proof. Let and be two first-countable topological spaces such that . Suppose is an arbitrary point with the corresponding hyperconvex neighborhood basis . If is a NHC in such that then within the topological space, maintaining the property that in . If we consider a continuous function , then such that . However, if topological ordering is preserved by in the two respective topological spaces, then where and . Hence, it can be concluded that where such that . As a result, is also hyperconvex under . □
Note that the converse of Theorem 6 may not always be satisfied under the anti-symmetric topological ordering relation, and additional conditions are required. The following lemma is a natural extension of the topological ordering property.
Lemma 1. The topological ordering preserves homeomorphism of .
There is an interplay between the isomorphisms of the two topological subspaces, topological ordering between the respective NHCs and the corresponding topological measures of the NHCs. The topological ordering in the two NHCs induces an algebraic order between the topological measures in the corresponding NHCs. This property is presented in the following theorem.
Theorem 7. If is preserved in topological spaces then where and .
Proof. Let and be two first-countable Hausdorff topological spaces with respective NHCs . Note that the topological spaces are separated as . Suppose we consider and preserving , which results in . If the topological measure is an almost-everywhere variety and then the condition is maintained. However, due to the topological ordering between and one can conclude that . □
The above theorem influences the Baire categorization of topological subspaces as illustrated in the following corollary.
Corollary 2. In and if then and need not be locally dense in and .
Proof. The proof is relatively straightforward because is a measure consistently maintaining algebraic ordering under topological ordering even if and . □
There is an interplay between the topological ordering and pushforward measure in the two NHCs. Suppose the function is a uniformly measurable function in two isomorphic topological measure spaces. It is interesting to note that the topological ordering does not preserve the pushforward measure in NHC under composition with the measurable function . This property is presented in the following theorem, where is the inverse of the corresponding function under the topological ordering relation.
Theorem 8. If is uniformly measurable in then is not a pushforward measure in .
Proof. Let be two measure spaces in respective topological spaces, where the condition is maintained between two NHCs. Suppose is a uniformly measurable function with such that . However, the topological ordering induces an inequality in measures under composition which is given by . Hence, the condition of the pushforward measure is not preserved by under between the two NHCs. □
Although the pushforward measure is not preserved by topological ordering between multiple NHCs, the hyperconvex neighborhood system is finitely measurable in each topological measure space, and the topological ordering induces an order in the corresponding measures. This observation is illustrated in the following lemma.
Lemma 2. In every first-countable the topological measure space admits finite measures of hyperconvex neighborhood basis and the topological ordering between NHCs induces a corresponding order in the neighborhood measures.
Proof. Let be a first-countable topological space, where is an open hyperconvex neighborhood basis. Clearly, is countable under the bijection where . As a result, the measure is finite in the corresponding measure space where by the definition of topological NHC measure. Moreover, if is another first-countable topological space with for some then under between the topological measure spaces . □
4.2. Topological Separation of Sigma-Semiring and Measurability
It is noted earlier in this paper that the increasing convex functional can be formulated in a linear function space , where is convex. However, the measure of the convex bounded measurable functions in a linear function space is finitely additive with the assumption that the sequential semicontinuity of Borel measurable functions is preserved. Note that the convex functional measure can be extended to be infinite. The relationship between the measures and the hyperconvex topological space presented in this paper consider finite measures under the topological decomposition and separation of measure spaces while at least preserving subadditivity. The Hausdorff topological measure space admitting a NHC is considered to be continuous and simply connected in nature.
Let be the and subspaces, respectively, in a NHC in . Suppose we consider such that where and . If we take the collection such that , then a topological separation of the corresponding is given by the following equation.
This immediately leads to the following lemma.
Lemma 3. A subspace is locally dense in the respective component in
if, and only if, .
The proof of the lemma is directly derivable from the structure of the topologically separated . However, it further results in the following theorem.
Theorem 9. A topologically separated is functionally separable by such that and every is inner-measurable.
Proof. Let a topologically separated be in and a set of real-valued functions be given by such that . Suppose that the functions in the set maintain the property of local continuity in the topological space by open mapping as such that and with . As a result, it can be concluded that . Moreover, as and , every is pushforward inner-measurable due to . □
Example 1. Let us consider a topological space in 1D such that where . In this case, the topological separation of the is given by As a result, the topological separation is also separated by if, and only if, the open neighborhoods under locally continuous mappings are disjoint as where the condition is preserved. Moreover, every topological separation in is inner-measurable because where is a finite positive measure in reals.