Abstract
In this study, we establish the existence and uniqueness theorems of the best proximity points for Geraghty type 𝒵-proximal contractions defined on a complete metric space. The presented results improve and generalize some recent results in the literature. An example, as well as an application to a variational inequality problem are also given in order to illustrate the effectiveness of our generalizations.
Keywords:
best proximity point; Ƶ-contraction; geraghty type contraction; simulation function; admissible mapping; variational inequality MSC:
47H10; 54H25
1. Introduction
Numerous problems in science and engineering defined by nonlinear functional equations can be solved by reducing them to an equivalent fixed-point problem. In fact, an operator equation
may be expressed as a fixed-point equation Accordingly, the Equation (1) has a solution if the self-mapping has a fixed point. However, for a non-self mapping the equation does not necessarily admit a solution. Here, it is quite natural to find an approximate solution such that the distance is minimum, in which case and are in close proximity to each other. Herein, the optimal approximate solution for which , is called a best proximity point of The main aim of the best proximity point theory is to give sufficient conditions for finding the existence of a solution to the nonlinear programming problem,
Moreover, a best proximity point generates to a fixed point if the mapping under consideration is a self-mapping. For more details on this research subject, see [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15].
In 2015, Khojasteh et al. [16] presented the notion of -contraction involving a new class of mappings—namely, simulation functions, and proved new fixed-point theorems via different methods to others in the literature. For more details, see [17,18,19,20].
Definition 1
([16]). A simulation function is a mapping so that:
- ;
- for all ;
- If are sequences in so that then
Theorem 1
([16]). Let be a complete metric space and be a -contraction with respect to —that is,
Then, admits a unique fixed point (say ) and, for each , the Picard sequence is convergent to τ.
In this study, we will consider simulation functions satisfying only the condition For the sake of convenience, we identify the set of all simulation functions satisfying only the condition by .
The main concern of the paper is to establish theorems on the existence and uniqueness of best proximity points for Geraghty type -proximal contractions in complete metric spaces. The obtained results complement and extend some known results from the literature. An example, as well as an application to a variational inequality problem, is also given in order to illustrate the effectiveness of our generalizations.
2. Preliminaries
Let P and Q be two non-empty subsets of a metric space, Consider:
Denote by
the set of all best proximity points of a non-self-mapping . In the study [5], Caballero et al. familiarized the notion of Geraghty contraction for non-self-mappings as follows:
Definition 2
([5]). Let be two non-empty subsets of a metric space, A mapping is called a Geraghty contraction if there is , so that for all
where the class Σ is the set of functions , satisfying
In the paper [10], Jleli and Samet initiated the concepts of --proximal contractive and -proximal admissible mappings. They provided related best-proximity-point results. Subsequently, Hussain et al. [7] modified the aforesaid notions and substantiated certain best-proximity-point theorems.
Definition 3
([10]). Let and be given mappings. Then, is called α-proximal admissible if
for all
Definition 4
([7]). Let and be given mappings. Such is said to be -proximal admissible if
for all
Note that if for all then Definition 4 corresponds to Definition 3.
Very recently, Tchier et al. in [14] initiated the concept of -proximal contractions.
Definition 5
([14]). Let P and Q be two non-empty subsets of a metric space, A non-self-mapping is called a -proximal contraction if there is a simulation function ζ so that
for all
Now, we introduce a new concept which will be efficiently used in our results.
Definition 6.
Let and be given mappings. Then, is said to be triangular -proximal admissible, if
- (1)
- is -proximal admissible;
- (2)
- for all
Now, we describe a new class of contractions for non-self-mappings which generalize the concept of Geraghty-contractions.
Definition 7.
Let P and Q be two non-empty subsets of a metric space and and A non-self-mapping is said to be a Geraghty type -proximal contraction, if for all , the following implication holds:
Remark 1.
If is a Geraghty type -proximal contraction, then by and Definition 7, the following implication holds for all with :
3. Main Results
Our first result is as follows.
Theorem 2.
Let be a pair of non-empty subsets of a complete metric space so that is non-empty, and be given mappings. Suppose that:
- (i)
- P is closed and ;
- (ii)
- is triangular -proximal admissible;
- (iii)
- There are so that and ;
- (iv)
- is a continuous Geraghty type -proximal contraction.
Then, has a best proximity point in If for all then has a unique best proximity point Moreover, for every .
Proof.
From the condition there are so that
Since , there is so that
Thus, we get
Since is -proximal admissible, we get Now, we have
Again, since , there exists such that
and thus,
Since is -proximal admissible, this implies that Thus, we have
By repeating this process, we build a sequence in so that
for all If there is so that then
That is, is a best proximity point of . We should suppose that for all
From (8), for all we get
On the grounds that is a Geraghty type -proximal contraction, by utilizing Remark 1, we deduce that
which requires that for all Therefore, the sequence is decreasing, and so there is so that Now, we shall show that On the contrary, assume that Then, taking into account (9), for any
This yields, for any
Taking , we find that
and since This contradicts our assumption Therefore, we get
We shall prove that is Cauchy in P. By contradiction, suppose that is not a Cauchy sequence, so there is an for which we can find and of such that is the smallest index for which and
We have
Taking , by (10), we get
By triangular inequality,
which yields that
Since is triangular -proximal admissible, by using (8), we infer
Regarding the fact that is a Geraghty type -proximal contraction, from Remark 1, we deduce that
Taking the limit as k tends to ∞ on both sides of the last inequality, and using the Equations (12) and (13), we get
which implies that and so which contradicts Hence, is a Cauchy sequence in P. Since P is a closed subset of the complete metric space , there is so that
Since is continuous, we have
Therefore, is a best proximity point of Finally, we shall show that the set is a singleton. Suppose that r is another best proximity point of that is, Then, by the hypothesis, we have —that is,
Then, from Remark 1, we deduce
which is a contradiction. Hence, we have a unique best proximity point of . □
Let us consider the following assertion in order to remove the continuity on the operator in the next theorem.
- (C)
- If a sequence in P is convergent to so that , then for all
Theorem 3.
Let be a pair of non-empty subsets of a complete metric space so that is non-empty, and be given mappings. Suppose that:
- (i)
- P is closed and ;
- (ii)
- is triangular -proximal admissible;
- (iii)
- there are so that and ;
- (iv)
- the condition holds and is a Geraghty type -proximal contraction.
Then, has a best proximity point in If for all then has a unique best proximity point Moreover, for each we have .
Proof.
Following the proof of Theorem 2, there exists a Cauchy sequence satisfying (8) and On account of (i), is closed, and so Also, since there is so that
Taking and (8) into account, we infer
Since is -proximal admissible and
so, we conclude that
Example 1.
Let be endowed with the Euclidian metric, and . Note that and Let
Then, Define and by
and
Choose for all . Let be such that
Then, or .
. Here, and . Also,
that is, and . So, Moreover,
If , then and the right-hand side of the above inequality is equal to 0.
If , we have
. Here, and . Similarly, we get that . So,
Also, .
In each case, we get that is an -proximal admissible. It is also easy to see that is triangular -proximal admissible. Also, is a Geraghty type -proximal contraction. Also, if is a sequence in P such that for all n and as then . We have or . We get that or . This implies that for all
Moreover, there is so that
Consequently, all conditions of Theorem 3 are satisfied. Therefore, has a unique best proximity point in P, which is On the other side, we indicate that (4) is not satisfied. In fact, for we have
Corollary 1.
Let be a pair of non-empty subsets of a complete metric space , such that is non-empty. Suppose that is a Geraghty-proximal contraction—that is, the following implication holds for all :
Also, assume that P is closed and Then, has a unique best proximity point Moreover, for each we have .
Proof.
We take in the proof of Theorem 2 (resp. Theorem 3). □
4. Some Consequences
In this section we give new fixed-point results on a metric space endowed with a partial ordering/graph by using the results provided in the previous section. Define
Definition 8.
Let be a partially ordered metric space, be a pair of non-empty subsets of M, and be a given mapping. Such is said to be ⪯-proximal increasing if
for all
Then, the following result is a direct consequence of Theorem 2 (resp. Theorem 3).
Theorem 4.
Let be a pair of non-empty subsets of a complete ordered metric space so that is non-empty and be a given non-self-mapping. Suppose that:
- (i)
- P is closed and ;
- (ii)
- is ⪯-proximal increasing;
- (iii)
- There are so that and ;
- (iv)
- is continuous or, for every sequence in P is convergent to so that , we have for all
- (v)
- There exist and , such that for all
Then, has a best proximity point in If for all then has a unique best proximity point Moreover, for every .
Now, we present the existence of the best proximity point for non-self mappings from a metric space M, endowed with a graph, into the space of non-empty closed and bounded subsets of the metric space. Consider a graph G, such that the set of its vertices coincides with M and the set of its edges contains all loops; that is, where . We assume G has no parallel edges, so we can identify G with the pair .
Define
Definition 9.
Let be a complete metric space endowed with a graph G and be a pair of non-empty subsets of M and be a given mapping. Such is said to be triangular G-proximal, if
- (1)
- for all ,
- (2)
- for all
for all
The following result is a direct consequence of Theorem 2 (resp. Theorem 3).
Theorem 5.
Let be a complete metric space endowed with a graph G and be a pair of non-empty subsets of M so that is non-empty and be a given non-self mapping. Suppose that:
- (i)
- P is closed and ;
- (ii)
- is triangular G-proximal;
- (iii)
- There are so that and ;
- (iv)
- is continuous or, for every sequence in P is convergent to so that , we have for all
- (v)
- There exist and such that for all
Then, has a best proximity point in If for all then has a unique best proximity point Moreover, for every .
5. A Variational Inequality Problem
Let C be a non-empty, closed, and convex subset of a real Hilbert space H, with inner product and a norm . A variational inequality problem is given in the following:
where is a given operator. The above problem can be seen in operations research, economics, and mathematical physics, especially in calculus of variations associated with the minimization of infinite-dimensional functionals. See [21] and the references therein. It appears in variant problems of nonlinear analysis, such as complementarity and equilibrium problems, optimization, and finding fixed points; see [21,22,23]. To solve problem (22), we define the metric projection operator . Note that for every , there is a unique nearest point so that
The two lemmas below correlate the solvability of a variational inequality problem to the solvability of a special fixed-point problem.
Lemma 1
([24]). Let . Then, is such that , for all iff .
Lemma 2
([24]). Let . Then, is a solution of , for all , if , with .
The main theorem of this section is:
Theorem 6.
Let C be a non-empty, closed, and convex subset of a real Hilbert space H. Assume that is such that is a Geraghty-proximal contraction. Then, there is a unique element , such that for all . Also, for any the sequence given as where and , is convergent to .
Proof.
We consider the operator defined by for all . By Lemma 2, is a solution of for all , if . Now, verifies all the hypotheses of Corollary 1 with Now, from Corollary 1, the fixed-point problem possesses a unique solution □
Author Contributions
H.I. analyzed and prepared/edited the manuscript, H.A. analyzed and prepared/edited the manuscript, N.M. analyzed and prepared the manuscript, S.R. analyzed and prepared the manuscript.
Funding
This research received no external funding.
Acknowledgments
The third author would like to thank Prince Sultan University for funding this work through the research group Nonlinear Analysis Methods in Applied Mathematics (NAMAM) group number RG-DES-2017-01-17.
Conflicts of Interest
The authors declare that they have no competing interests regarding the publication of this paper.
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