1. Introduction
A Novikov algebra is a vector space
A with a binary operation that satisfies
for all
a,
b,
. Denote it by
. Novikov algebras appeared in connection with the Poisson brackets of hydrodynamic type [
1] and Hamiltonian operators in the formal variational calculus [
2,
3]. As a special class of pre-Lie algebras, they are closely related to many fields in mathematics and physics, such as Lie groups, Lie algebras, affine manifolds, vertex algebras, Lie conformal algebras, quantum field theory and so on.
A Novikov–Poisson algebra
is a vector space with a Novikov algebra structure
and a commutative associative algebra structure
satisfying some compatibility conditions. Novikov–Poisson algebras were introduced by Xu in [
4] in order to establish the tensor theory of Novikov algebras. Moreover, Xu in [
5] classified Novikov–Poisson algebras whose Novikov algebras are simple with an idempotent element and a class of simple Novikov algebras without non-zero idempotent elements were constructed through Novikov–Poisson algebras. In addition, Novikov–Poisson algebras are closely related to a class of Novikov conformal algebras called quadratic Novikov conformal algebras [
6], higher-dimensional Lie conformal algebras [
7], transposed Poisson algebras [
8] and so on. There have been many other works on Novikov–Poisson algebras. For example, the classifications of Novikov–Poisson algebras of low dimensions were carried out in [
9,
10,
11], the relationships between Novikov–Poisson algebras and Jordan algebras were investigated in [
12,
13], embedding of Novikov–Poisson algebras in Novikov–Poisson algebras of vector type was studied in [
14] and free Novikov–Poisson algebras were investigated in [
15].
Since Novikov–Poisson algebras are related to kinds of other algebra structures, the constructions and classifications of Novikov–Poisson algebras become important. Based on this, we plan to study the following problem of Novikov–Poisson algebras:
Extending structures problem: Let be a Novikov–Poisson algebra and E a vector space containing A as a subspace. Describe and classify all Novikov–Poisson algebra structures on E, such that is a subalgebra of E up to isomorphism whose restriction on A is the identity map.
From the perspective of algebraic theory, this problem is natural, important and worth investigating, since it will tell us how to construct a larger algebra from a given algebra. Extending structures problems for groups, Lie algebras, associative algebras, Hopf algebras, and left-symmetric algebra were investigated in [
16,
17,
18,
19,
20], respectively. In particular, the theories of extending structures for Novikov algebras and commutative associative algebras have been developed in [
18,
20], respectively. Motivated by these results, we introduce the definition of a unified product for Novikov–Poisson algebras and then construct an object
to give a theoretical answer for the extending structures problem of Novikov–Poisson algebras, where
V is a complement of
A in
E. Furthermore, when
, we calculate
and give a specific example. These results will be useful for studying the structure theory of Novikov–Poisson algebras and classifying low-dimensional Novikov–Poisson algebras.
This paper is organized as follows. In
Section 2, we recall some definitions about Novikov–Poisson algebras and some results about extending structures for Novikov algebras and commutative associative algebras. In
Section 3, we introduce the definition of a unified product for Novikov–Poisson algebras and construct an object
to give a theoretical answer for the extending structures problem. In
Section 4, we investigate the unified products
in detail when
, and finally provide an example to compute
.
Throughout this paper, is an arbitrary field and is the field of complex numbers. We also denote the set of non-zero elements in by . All vector spaces, Novikov algebras, commutative associative algebras, Novikov–Poisson algebras, linear or bilinear maps are over .
2. Preliminaries
In this section, we recall some definitions of Novikov–Poisson algebras, and some results about extending structures for Novikov algebras and commutative associative algebras.
Firstly, we recall some basic facts about Novikov algebras [
20].
Let
be a Novikov algebra. Then, there is a natural Lie algebra structure on
A:
Denote this Lie algebra by .
Definition 1. Let be a Novikov algebra, V be a vector space and , be two linear maps. If it satisfiesfor all a, and , then is called a bimoduleof . Definition 2 ([
20], Definition 3.1, Theorem 3.2 and Corollary 3.5]).
Let be a Novikov algebra and V be a vector space. A Novikov extending datum of through V is a system consisting of four linear maps: , , and two bilinear maps: , satisfying the following conditions:
for all a, , x, y, .Let be a Novikov extending datum of through V and be the vector space with the bilinear map “∘ " defined by:for all a, , x, . Then, is a Novikov algebra by [20] (Theorem 3.2), which is called theunified productof and . Next, we recall the definition of a unified product for commutative associative algebras.
Definition 3 ([
18], Definition 3.11, Theorem 2.2).
Let be a commutative associative algebra and V be a vector space. A commutative associative extending datum of through V is a system consisting of four bilinear maps: , such that g and • are symmetric and the following conditions hold:for all a, , x, y, .Let be a commutative associative extending datum of through V and let be the vector space with the linear map “· " defined by:for all a, , x, . Then, is a commutative associative algebra by [18] (Theorem 2.2), which is called theunified productof and . Remark 1. Note that means that is a right module of .
Finally, we recall the definition of Novikov–Poisson algebra.
Definition 4 ([
4]).
A Novikov–Poisson algebra is a vector space A with two operations , , such that forms a Novikov algebra, forms a commutative associative algebra and they satisfyfor all a, b and . Let and be two Novikov–Poisson algebras. If a linear map is both a homomorphism of Novikov algebras and a homomorphism of commutative associative algebras, then is called a homomorphism of Novikov–Poisson algebras.
Let be a subspace of A. If is a Novikov subalgebra (a two-sided ideal) of and is a subalgebra (an ideal) of , then is called a subalgebra (an ideal) of Novikov–Poisson algebra .
Definition 5. Let be a Novikov–Poisson algebra. If is a bimodule of , is a left module of and they satisfyfor all a, and , then is called a left moduleof . Similarly, is called a right moduleof , if is a bimodule of , is a right module of , and they satisfyfor all a, and . Finally, we introduce the following definition, which is important for studying the extending structures problem.
Definition 6. Let be a Novikov–Poisson algebra and let E be a vector space containing A as a subspace. Let and be two Novikov–Poisson algebra structures on E, such that is a subalgebra of them. If there is an isomorphism of Novikov–Poisson algebras whose restriction on A is the identity map, then we say that and areequivalent. We denote it by .
Let S be the set of all Novikov–Poisson algebra structures on E which contain as a subalgebra. Obviously, is an equivalence relation on S. Denote the set of all equivalence classes via by . Therefore, to study the extending structures problem, we only need to characterize .
3. Unified Products for Novikov–Poisson Algebras
In this section, we will introduce a notion of unified product for Novikov–Poisson algebras. Through this, we can characterize to answer the extending structures problem.
Definition 7. Let be a Novikov–Poisson algebra and V a vector space. Anextending datumof through V is a system consisting of four linear maps and six bilinear maps, as follows:Let be an extending datum of a Novikov–Poisson algebra through V. Denote the vector space by . Define two bilinear operations and on as follows:for all a, , x, . If is a Novikov–Poisson algebra, then we call that is aunified productof and . Definition 8. Let be a Novikov–Poisson algebra, V be a vector space and be an extending datum of through V. If satisfies the following compatibility conditions:
for all a, b, , x, y, , we say that is aNovikov–Poisson extending datum ofthroughV. We denote the set of all Novikov–Poisson extending data of through V by . Theorem 1. Let be a Novikov–Poisson algebra, V be a vector space and be an extending datum of through V. Then, is a unified product with the operations defined by (14) and (15) if and only if is a Novikov–Poisson extending datum of through V. Proof. According to [
20] (Theorem 3.2) , [
18] (Theorem 2.2) and [
18] (Definition 3.11),
is a Novikov algebra if and only if
is a Novikov extending datum of
through
V, and
is a commutative associative algebra if and only if
is a commutative associative extending datum of
through
V. Then, we only need to check that
for all
a,
b,
,
x,
y,
if and only if
-
hold.
Note that (
16) holds for all
a,
b,
,
x,
y,
if and only if it holds for all triples:
,
,
,
,
,
,
and
, where
a,
b,
,
x,
y,
. Since
is a Novikov–Poisson algebra, (
16) holds for the triple
. Since
we have that (
16) holds for the triple
⇔
and
hold. Similarly, we can prove the following: (
16) holds for the triple
⇔
and
hold; (
16) holds for the triple
⇔
and
hold; (
16) holds for the triple
⇔
and
hold; (
16) holds for the triple
⇔
and
hold; (
16) holds for the triple
⇔
and
hold; (
16) holds for the triple
⇔
and
hold.
As for (
17), it also holds if
is changed to
. Thus, (
17) holds for all
a,
b,
,
x,
y,
if and only if it holds for all triples
,
,
,
,
, and
, where
a,
b,
,
x,
y,
. Obviously, (
17) holds for the triple
, since
is a Novikov–Poisson algebra. Similarly, we can obtain: (
17) holds for the triple
⇔
and
hold; (
17) holds for the triple
⇔
and
hold; (
17) holds for the triple
⇔
and
hold; (
17) holds for the triple
⇔
and
hold; (
17) holds for the triple
⇔
and
hold.
Then, the proof is finished. □
Remark 2., , , , and mean that is a right module of .
Example 1. Let be an extending datum of through a vector space V, where , and ◃ are trivial maps. We can simplify the extending datum into . Then, is a Novikov–Poisson extending datum of through V if and only if is a Novikov extending datum of through V, is a commutative associative extending datum of through V, is a Novikov–Poisson algebra, and the following conditions hold:for all a, , x, y, . We denote the associated unified product in this case by , which is called thecrossed productof and . The crossed product associated with satisfying the compatibility conditions above, is the Novikov–Poisson algebra, defined as follows:for all a, , x, . Note that is an ideal of . Example 2. Let be an extending datum of through a vector space V, where f and g are trivial maps. We also simplify the extending datum into . Then, is a Novikov–Poisson extending datum of through V if and only if is a Novikov extending datum of through V, is a commutative associative extending datum of through V, is a Novikov–Poisson algebra, is a right module of , is a left module of , and they satisfy , , , , , , , , and . In this case, the associated unified product denoted by is called thebicrossed productof Novikov–Poisson algebras and associated with the matched pair . The bicrossed product associated with satisfying the compatibility conditions above is the Novikov–Poisson algebra defined as follows:for all a, , x, . Note that and are both subalgebras of . Theorem 2. Let be a Novikov–Poisson algebra and be a Novikov–Poisson algebra containing as a subalgebra. Then, there exists a Novikov–Poisson extending datum of , such that as Novikov–Poisson algebras whose restriction on A is the identity map.
Proof. Let
be the natural linear map such that
for all
. Let
, which is a complement of
A in
E as a vector space. Then, we define the extending datum of
through
V as follows:
for all
,
. According to the proof of Theorem 3.9 in [
20] and the proof of Theorem 2.4 in [
18], it is easy to prove that
is a Novikov–Poisson extending datum of
through
V and the linear map
, where
is an isomorphism of Novikov–Poisson algebras whose restriction on
A is the identity map. □
Remark 3. According to Theorem 2 and Example 1, any Novikov–Poisson algebra structure on the vector space , such that is an ideal of E is isomorphic to a crossed product for some Novikov–Poisson algebra .
Let and be two Novikov–Poisson algebras. By Theorem 2 and Example 2, any Novikov–Poisson algebra structure on the vector space such that and are two subalgebras is isomorphic to a bicrossed product .
Definition 9. Let be a Novikov–Poisson algebra and V a vector space. If there is a pair of linear maps in which is a linear map, such that the Novikov–Poisson extending datum can be obtained from another Novikov–Poisson extending datum through as follows:for all , x, , then and are calledequivalent, which is denoted by . Lemma 1. Let be a Novikov–Poisson algebra, V a vector space, and , be two Novikov–Poisson extending datums of through V. Let and be the corresponding unified products, respectively. Then, if and only if .
Proof. Let
be an isomorphism of Novikov–Poisson algebras whose restriction on
A is the identity map. Since
is the identity map, we assume that
, where
and
are two linear maps. Note that a homomorphism of Novikov–Poisson algebras is also a homomorphism of Novikov algebras and a homomorphism of commutative associative algebras. By Lemma 3.12 in [
20] and Lemma 2.5 in [
18], we get that
is an isomorphism of Novikov–Poisson algebras whose restriction on
A is the identity map if and only if
and
-
hold. Then, this conclusion follows via Definition 9. □
Theorem 3. Let be a Novikov–Poisson algebra and E a vector space which contains A as a subspace and V a complement of A in E as a vector space. Denote . Then, the mapis bijective, where is the equivalence class of via ≡. Proof. This conclusion follows directly from Theorem 1, Theorem 2 and Lemma 1. □
Remark 4. By Theorem 3, describes and classifies all Novikov–Poisson algebra structures on such that is a subalgebra up to isomorphism whose restriction on A is the identity map, i.e., it gives a theoretical answer to the extending structures problem for Novikov–Poisson algebras.
Remark 5. Note that unified product is a very general construction which includes bicrossed product, crossed product and so on. Therefore, from Theorem 3, we can also obtain many interesting results in some special cases. We also give an example which corresponds to a crossed product as follows.
According to Theorem 3, Example 1 and Remark 3, , where , and ⊲ are trivial in these Novikov–Poisson extending datums, describes and classifies all Novikov–Poisson algebra structures on , such that is an ideal up to isomorphism whose restriction on A is the identity map.
4. Unified Products When
In this section, we consider the unified product when in detail.
Definition 10 ([
20], Definition 4.3).
Let be a Novikov algebra. A Novikov flag datum of is a 6-tuple consisting of four linear maps: h, , D, and two elements , satisfying the following conditions:for all a, .
Definition 11 ([
20], Definition 2.5).
Let be a Novikov algebra. If a linear map satisfiesthen the linear map T is called a quasicentroid.
Remark 6. For any , there is a quasicentroid associated to it defined by for all . We call aninner quasicentroidof .
Definition 12 ([
18], Definition 4.2).
Let be a commutative associative algebra. A commutative associative flag datum of is a 4-tuple consisting of two linear maps: , and two elements: , satisfying the following conditions:for all a, . Definition 13. Let be a Novikov–Poisson algebra. ANovikov–Poisson flag datumof is a 10-tuple consisting of six linear maps: h, k, , D, T, and four elements , satisfying the following conditions:for all a, . We denote the set of all flag datums of by . Proposition 1. Let be a Novikov–Poisson algebra and V a vector space of dimension 1 with a basis . Then, there exists a bijection between the set of all Novikov–Poisson extending datums of through V and of all Novikov–Poisson flag datums of .
Proof. Let
be a Novikov–Poisson extending datum of
through
V. Since
, we can set
where
,
, and
h,
k,
,
D,
T,
are six linear maps. Take them into
–
. [
20] (Proposition 4.4) and [
18] (Proposition 4.3) we get that
is equivalent to
. Let
in
. Since
,
,
and
, one can directly obtain that
is equivalent to
. Similarly, we can get that
–
are equivalent to
–
. Then, the proof is finished. □
In the sequel, we denote the unified product associated with the Novikov–Poisson extending datum corresponding to a Novikov–Poisson flag datum by .
Theorem 4. Let be a Novikov–Poisson algebra of codimension 1 in the vector space E. Then, there exists a bijectionwhere ≡ is the equivalence relation on the set of all Novikov–Poisson flag data of defined as follows: if and only if , , and there exists a pair , such that the following conditions hold:for all . The bijection between and Extd is given bywhere is the equivalence class of by ≡. Proof. Let
,
and
,
be the corresponding Novikov–Poisson-extending data, respectively. Assume that
x is a basis of
V. Then, we can set
,
in Lemma 1 as follows:
where
and
. Then, the desired conclusion follows directly from Lemma 1, Theorem 3 and Proposition 1. □
If
, where
h,
k,
T and ∧ are trivial, then we denote the flag datum as
. We denote the set of all such flag data of
as
. According to Theorem 4,
if and only if there exists a pair
, such that the following conditions hold:
for all
. Particularly, when
, we denote such flag datum of
by
. Denote the set of all such flag data of
by
. Define
if there exists
, such that the following conditions hold:
for all
.
If
, where
h,
T are trivial and
, then we denote such flag data of
by
. Denote the set of all such flag data of
, where
by
. Using Theorem 4,
if and only if
,
and there is a pair
, such that the following conditions hold:
for all
. Furthermore, we define that
if
,
and there exists
, such that the following conditions hold:
for all
.
Corollary 1. Let be a Novikov–Poisson algebra, its sub-adjacent Lie algebra is perfect, i.e., , and all quasicentroids of are inner. Then,In particular, if , then Proof. Since
, using the proof of Corollary 4.6 in [
20], we obtain the following two cases:
- (1)
h, k and T are trivial,
- (2)
h, T are trivial, and k is non-trivial.
In Case (1), by , we get for all a, . Note that due to . Therefore, . Thus, in this case, we only need to consider those flag data in . Similarly, in Case (2), we only need to compute those flag data in . Next, we consider both cases, when . Using , we get . Moreover, using , we obtain for all . Therefore, . Then, this corollary follows directly from Theorem 4. □
Finally, we present an example to compute .
Example 3. Let and be a two-dimensional Novikov–Poisson algebra with a basis and the products given by:This is one of the classifications of two-dimensional Novikov–Poisson algebras studied in [9]. Using a long but straightforward calculation, the following flag data satisfying - are as follows.
There are five cases in total.
This tells us that any three-dimensional Novikov–Poisson algebra that contains as a subalgebra is isomorphic to the following Novikov–Poisson algebra denoted by with the basis and the products given by (21) and Two such Novikov–Poisson algebras and are equivalent if and only if there is u, and such that , , and . Then, is equivalent to by setting , and . Furthermore, is equivalent to if and only if there exists , such that and .
This tell us that any three-dimensional Novikov–Poisson algebra that contains as a subalgebra is isomorphic to the following Novikov–Poisson algebra denoted by with the basis and the products given by (21) and Two such Novikov–Poisson algebras and are equivalent if and only if and , such that and . Then, is equivalent to and , setting and . Therefore, in this case, there are only two equivalence classes, i.e., and .
This tells us that any three-dimensional Novikov–Poisson algebra that contains as a subalgebra is isomorphic to the following Novikov–Poisson algebra denoted by , with the basis and the products given by (21) and Two such Novikov–Poisson algebras and are equivalent if and only if there is u, and , such that , and . Then, is equivalent to either or . Therefore, in this case, there are only two equivalence classes, i.e., and .
This tells us that any three-dimensional Novikov–Poisson algebra that contains as a subalgebra is isomorphic to the following Novikov–Poisson algebra denoted by , with the basis and the products given by (21) and Two such Novikov–Poisson algebras and are equivalent if and only if u, and , such that , , and . Then, is equivalent to by letting , and . Moreover, is equivalent to if and only if and , such that and .
This tells us that any three-dimensional Novikov–Poisson algebra that contains as a subalgebra is isomorphic to the following Novikov–Poisson algebra denoted by , with the basis and the products given by (21) and Two such Novikov–Poisson algebras and are equivalent if and only if u, and , such that , and . Then, is equivalent to , or , where , and . Therefore, in this case, there are three equivalence classes, i.e., and , where , and .
Therefore, according to the discussion above and Theorem 4, can be described by the disjointed union of the equivalence classes of , , , and , the equivalence classes of and and , where , and .