1. Introduction
Fixed point theory is an important branch of non-linear analysis. After the celebrated Banach contraction principle [
1], a number of authors have been working in this area of research. Fixed point theorems (FPTs) are important instruments for proving the existence and uniqueness of solutions to variational inequalities. Metric FPTs expanded after the well-known Banach contraction theorem was established. From this point forward, there have been numerous results related to maps fulfilling various contractive conditions and many types of metric spaces (see, for example, [
2,
3,
4,
5,
6,
7,
8,
9]).
The authors of [
10,
11] presented a novel extension of the b-metric space known as controlled metric spaces (CMSs) and demonstrated the FPTs on the CMSs, providing an example by employing a control function
in the triangle inequality.
Serge [
12] made a pioneering attempt at developing special algebra. He conceptualized commutative generalizations of complex numbers as briefly bicomplex numbers (BCN), briefly tricomplex numbers (tcn), etc., as elements of an infinite set of algebra. Subsequently, many researchers contributed in this area, (see, for example, [
13,
14,
15,
16,
17,
18,
19]).
In 2021, the authors of [
20] proved a common fixed point for a pair of contractive-type maps in bicomplex-valued metric spaces. Later, several authors discussed their results using this concept, see [
21,
22,
23,
24]. Guechi [
25] introduced the concept of optimal control of
-Hilfer fractional equations and proved the fixed point results. For details, see [
26,
27,
28] and the references therein.
In this paper, we introduce the notion of bicomplex-valued CMSs (BVCMSs) and prove FPT under Banach, Kannan and Fisher contractions on BVCMSs. Then, we give an application to solve a fractional differential equation (FDE) and show that this extension is different from bicomplex-valued metric spaces in terms of Beg, Kumar Datta and Pal [
20].
2. Preliminaries
We use standard notations throughout this paper: The real, complex, and bicomplex number sets are represented by
,
and
, respectively. The following complex numbers were described by Segre [
12].
where
,
. We represent
as:
Let
, then
. Every element in
with a positive real-valued norm function
is defined by
Segre [
12] described the bicomplex number (BCN) as:
where
, and the independent units
satisfy
and
. We represent the BCN set
as:
that is,
where
and
. If
and
are any two BCNs, then their sum is
There are four idempotent elements in
. They are
of which
and
are non-trivial, such that
and
. Every BCN
can be uniquely expressed as a combination of
and
, namely,
This representation of is known as the idempotent representation of a BCN, and the complex coefficients and are known as the idempotent components of the BCN .
Each element in
with a positive real-valued norm function
is defined by
where
.
The linear space with respect to a defined norm is a normed linear space, and is complete. Therefore, is a Banach space. If , then holds instead of , and therefore is not a Banach algebra. For any two BCN , then
- 1.
;
- 2.
;
- 3.
, where is in ;
- 4.
, and holds when only one of or is degenerated;
- 5.
, if is degenerated with ;
- 6.
, if is a degenerated BCN.
The relation (partial order) is defined on as given below. Let be a set of BCNs and and . Then, if and only if and , i.e., , if one of the following conditions is fulfilled:
- 1.
, ;
- 2.
, ;
- 3.
, ;
- 4.
, .
Clearly, we can write if and , i.e., if 2, 3 or 4 are satisfied, and we will write if only 4 is satisfied.
Definition 1 ([
10]).
Let and . The functional is called the briefly controlled-type metric CMT if(CMT1) ,
(CMT2) ,
(CMT3) ,
for all. Then, the doubletis called a CMT space.
Several researchers have proven FPTs using this notion (see [
3,
4,
6,
11]).
Definition 2. Let and consider . The functional is said to be a BVCMS if
(BCCMS1) ,
(BCCMS2) ,
(BCCMS3) ,
for all , Then, the pair is known as a BVCMS.
Example 1. Let and be defined asand be defined as followsThen is a bvcms. Remark 1. If we take , for all , then is a bicomplex-valued b-metric space, that is, every bicomplex-valued b-metric space is a BVCMS.
Example 2. Let with is the set of all positive integers and is defined for all aswhere and defined as followswhere . Now, the conditions (BCCMS1) and (BCCMS2) hold. Furthermore, (BCCMS3) holds under the following cases.
Case 1. If and ;
Case 2. If or if or if or if ;
SubCase 1. If and ;
SubCase 2. If and ;
SubCase 3. If and ;
SubCase 4. If and ;
SubCase 5. If and ;
SubCase 6. If and ;
SubCase 7. If ;
SubCase 8. If .
Then is a BVCMS.
Remark 2. If (as in the above example) for all , then is a bicomplex-valued extended b-metric space. We can conclude that every bicomplex-valued extended b-metric space is a BVCMS. However, the converse may not true in general.
Example 3. Let and be defined asand be defined asClearly, the conditions (BCCMS1) and (BCCMS2) hold. Now, Case 1. If the condition (BCCMS3) holds.
Case 2. If and (same as and ) and Case 3. If and (same as and ) and Case 4. If and (same as and ) and Then, is a BVCMS.
Definition 3. Let be a BVCMS with a sequence in ζ and . Then,
- (i)
A sequence in ζ is convergent to if , ∃ a natural number so that for each . Then, or as .
- (ii)
If, for each where , ∃ a natural number so that for each and . Then, is called a Cauchy sequence in .
- (iii)
BVCMS is termed complete if every Cauchy sequence is convergent.
Lemma 1. Let be a BVCMS. Then a sequence in ζ is a Cauchy sequence, such that , with . Then, converges to one point at most.
Proof. Let
and
be two limits of the sequence
and
. Since
is a Cauchy sequence, from (
BCCMS3), for
, whenever
, we can write
We obtain , i.e., . Thus, converges to one point at most. □
Lemma 2. For a given BVCMS , the tricomplex-valued controlled metric map is continuous with respect to “”.
Proof. Let
, such that
, then we show that the set
given by
is open in the product topology on
. Then, let
. We choose
. Then, for
we obtain
and
Then, . □
Defining will be the set of fixed points.
In this paper, we introduce the notion of BVCMS and FPT in the context of BVCMSs.
3. Main Results
Now, we prove the Banach-type contraction principle.
Theorem 1. Let be a complete BVCMS and a continuous map, such thatfor all , where . For , we denote . Suppose that Moreover, for every the limits Then η has a unique fixed point (UFP).
Proof. Let
. By (
1), we obtain
For all
, where
, we have
Furthermore, using
. Let
Applying the ratio test and (
2), we obtain
exists and the sequence
is a real Cauchy sequence. Letting
, we have
Then,
is a Cauchy sequence in a BVCMSs
; then
converges to
. By the definition of continuity, we obtain
Let
fix
η. Then,
Therefore, ; so . Hence, η has a UFP. □
Theorem 2. Let be a complete BVCMS and a map, such thatfor all , where . For we denote . Suppose that In addition, for each , Then, η has a UFP.
Proof. Using the proof of Theorem 1 and Lemma 2, we obtain a Cauchy sequence
in a complete BVCMS
. Then, the sequence
converges to
. Therefore,
Using (
7), (
8) and (
18), we obtain
Using the triangular inequality and (
6),
Taking the limit
from (
8) and (
19), we find that
. By Lemma 1, the sequence
uniquely converges at
. □
Example 4. Let and be a symmetrical metric given byand Define by Hence, it is a BVCMS.
Consider a map is defined by .
Letting . Then,
Therefore, all axioms of Theorem 2 are fulfilled. Hence, η has a UFP, which is .
Next, we show a Kannan-type contraction map.
Theorem 3. Let be a complete BVCMS and a continuous map, such thatfor all , where . For we denote . Suppose that Moreover, for each ,exists and is finite. Then, η has a UFP. Proof. For
, consider a sequence
. If
for which
, then
. Thus, there is nothing to prove. Now we assume that
for all
. By using (
1) we obtain
Continuing in the same way, we have
Thus,
for all
. For all
, where υ and ς are natural numbers, we have
Furthermore, using
. Let
By applying the ratio test, we obtain
exists and so the sequence
is a Cauchy sequence. Letting
, we have
Then
is a Cauchy sequence in a complete BVCMS
. This means the sequence
converges to some
. By the definition of continuity, we obtain
Let
fix η. Then,
Therefore, , then . Hence, η has a UFP. □
Theorem 4. Letbe a complete BVCMS and a map, such thatfor all where . For we denote . Suppose that Moreover, for each , exists and is finite. Then η has a UFP.
Proof. By proving Theorem 3 and using Lemma 2, we show a Cauchy sequence
in a complete BVCMS
. Then the sequence
converges to a
. Then,
Using (
2), (
3) and (
18), we deduce
Using the triangular inequality and (
1), we obtain
As
from (
3) and (
19), we conclude that
. From Lemma 1, the sequence
uniquely converges at
. □
Example 5. Let and be a symmetrical metric as followsand Define by A self-map η on ζ can be defined by .
Taking ; then,
Case 1. If , then the result is obvious.
Case 2. If , we obtain
.
Case 3. If , we have
.
Case 4. If , we have
.
Then, all hypothesis of Theorem 4 are fulfilled. Hence, has a UFP, which is .
Finally, we show that FPT in a Fisher-type contraction map.
Theorem 5. Let be a complete BVCMS and a continuous map, such thatfor all , where , such that . For we denote . Suppose that Moreover, suppose that for every we haveexist and are finite. Then η has a UFP. Proof. For
. Let
. If
for which
, then
. Thus, there is nothing to prove. Now we assume that
for all
. By using (
1), we obtain
which implies
In the same way
which implies
Continuing in the same way, we have
Thus, for all . For all , where υ and ς are natural numbers, giving
Furthermore, using
. Let
By using the ratio test, ensuring that
exists, the sequence
is a real Cauchy sequence. As
, we conclude that
Then, is a Cauchy sequence in the complete BVCMS . Therefore, the sequence converges to .
By the definition of continuity, we obtain
Let
fix
η as two fixed points of
η. Then,
Therefore, ; then . Hence, η has a UFP. □
If we drop the continuous condition, we obtain
Theorem 6. Let be a complete BVCMS and a map, such thatfor all , where , such that . For we denote . Suppose that In addition, assume that for every we have Therefore, it is finite. Then η has a UFP.
Proof. By proving Theorem 5 and using Lemma 2, we obtain a Cauchy sequence
which converges to
. Then,
Using (
2), (
3) and (
23), we deduce that
Using the triangular inequality and (
1),
As
in (
3) and (
24), we find that
. From Lemma 1, the sequence
uniquely converge at
. □
Example 6. Let and be a symmetrical metric defined asand Defining by Clearly, is a BVCMS. A self-map η on ζ defined by .
If we assume that , we obtain
Case 1. If we have .
Case 2. If , we obtained
Case 3. If , we have
Case 4. If , we have
Therefore, all axioms of Theorem 6 are fulfilled. Hence, η has a UFP, which is .
Application
Now, we see some basic definitions from the fractional calculus.
Let
be a function, the Rieman–Liouville fractional derivatives of order
are defined as:
presenting that the right-hand side is point-wise on
, where
is the Euler
function and
is the integer part of
.
Consider the following FDE
where
represents the order of
as the Caputo fractional derivatives and
as a continuous map defined by
The given FDE (
25) is equivalent to
for all
and
, where
Consider
as the space of the continuous map described by
, and
a bicomplex-valued controlled metric, such that
for all
. Let
be defined by
for all
. Then,
is a complete BVCMS.
Theorem 7. Consider the non-linear FDE (25). Suppose that the following assertions are satisfied: - (i)
There exists and , such that - (ii)
Then, FDE (25) has a unique solution in ζ.
Proof. Consider the map
defined by
Now, for all
, we deduce
Taking the supreme, we obtain
Therefore, all conditions of Theorem 1 are fulfilled and the operator η has a UFP. □