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Article

Global Properties of HIV-1 Dynamics Models with CTL Immune Impairment and Latent Cell-to-Cell Spread

1
Department of Mathematics, Faculty of Science, University of Jeddah, P.O. Box 80327, Jeddah 21589, Saudi Arabia
2
Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia
*
Author to whom correspondence should be addressed.
Mathematics 2023, 11(17), 3743; https://doi.org/10.3390/math11173743
Submission received: 18 July 2023 / Revised: 22 August 2023 / Accepted: 23 August 2023 / Published: 31 August 2023

Abstract

:
This paper presents and analyzes two mathematical models for the human immunodeficiency virus type-1 (HIV-1) infection with Cytotoxic T Lymphocyte cell (CTL) immune impairment. These models describe the interactions between healthy CD 4 + T cells, latently and actively infected cells, HIV-1 particles, and CTLs. The healthy CD 4 + T cells might be infected when they make contact with: (i) HIV-1 particles due to virus-to-cell (VTC) contact; (ii) latently infected cells due to latent cell-to-cell (CTC) contact; and (iii) actively infected cells due to active CTC contact. Distributed time delays are considered in the second model. We show the nonnegativity and boundedness of the solutions of the systems. Further, we derive basic reproduction numbers 0 and ˜ 0 , that determine the existence and stability of equilibria of our proposed systems. We establish the global asymptotic stability of all equilibria by using the Lyapunov method together with LaSalle’s invariance principle. We confirm the theoretical results by numerical simulations. The effect of immune impairment, time delay and CTC transmission on the HIV-1 dynamics are discussed. It is found that weak immunity contributes significantly to the development of the disease. Further, we have established that the presence of time delay can significantly decrease the basic reproduction number and then suppress the HIV-1 replication. On the other hand, the presence of latent CTC spread increases the basic reproduction number and then enhances the viral progression. Thus, neglecting the latent CTC spread in the HIV-1 infection model will lead to an underestimation of the basic reproduction number. Consequently, the designed drug therapies will not be accurate or sufficient to eradicate the viruses from the body. These findings may help to improve the understanding of the dynamics of HIV-1 within a host.

1. Introduction

Human immunodeficiency virus type-1 (HIV-1) is one of the chronic viruses that infects humans and causes Acquired Immune Deficiency Syndrome (AIDS). HIV-1 attacks the CD4 + T cells which are essential in the immune system. Adaptive immune responses play pivotal roles in HIV infection. B cells and cytotoxic T lymphocytes (CTLs) are two potential components of the adaptive immune response. B cells produce antibodies to neutralize the HIV-1 particles, while CTLs kill cells infected by HIV-1. Evaluating interactions between HIV-1 and target cells as well as immune cells can be experimentally expensive. Thus, mathematical modeling of HIV-1 infection has become an important tool for understanding the dynamical behavior of the viruses and their interactions with target cells and immune cells. Nowak and Bangham [1] presented the primary HIV-1 dynamics model which involve three components: healthy CD4 + T cells (H), infected CD4 + T cells (Y) and free HIV-1 particles (V). In the same paper, the CTL immune response was modeled as:
Healthy CD 4 + T cells : H ˙ ( t ) = α Production of healthy CD 4 + T cells η H t Natural death ρ 1 H t V t Infectious transmission , Actively infected CD 4 + T cells : Y ˙ ( t ) = ρ 1 H t V t Infectious transmission τ Y t Natural death γ I t Y t Killing of infected cells by CTLs , HIV - 1 particles : V ˙ ( t ) = ε Y t Burst size θ V t Natural death ,
CTLs : I ˙ ( t ) = ν Y ( t ) I ( t ) CTLs stimulation π I t Natural death ,
where I ( t ) is the concentration of the CTLs at time t. After introducing this model, several virus dynamics models were developed and studied. Let us write the population dynamics of the CTLs as:
I ˙ ( t ) = Θ ( Y ( t ) , I ( t ) ) π I t ,
where Θ ( Y , I ) is the stimulation rate of CTLs. It has taken many shapes in the literature:
S1. 
Self-regulating CTL, Θ ( Y , I ) = ω , where ω > 0 [2],
S2. 
Linear CTL response, Θ ( Y , I ) = λ Y , where λ > 0 [3,4,5,6],
S3. 
Predator-prey-like CTL, Θ ( Y , I ) = ν Y I , where ν > 0 [1,2,7],
S4. 
Combination of shapes S1–S3, Θ ( Y , I ) = ω + λ Y + ν Y I [2],
S5. 
Combination of predator-prey-like CTL and self-proliferation CTL: Θ ( Y , I ) = ν Y I + ς I 1 I I max , where ς , I max > 0 [8].
S6. 
Saturated CTL response: Θ ( Y , I ) = ν Y I ϑ + I , ϑ > 0 [9,10,11,12].
Some important biological factors were not included in models (1) and (2), such as:
Latently infected cells: these cells are considered one of the main obstacles for eliminating the HIV-1 by current antiviral drug therapies. Such cells contain the HIV-1 virions but do not generate them until they are activated. HIV-1 infection models with CTL immunity and latently infected cells were introduced in other research papers (see, e.g., [7,13]).
Time delay: in [14], it was estimated that the time between the HIV-1 entering a CD 4 + T cell until generating new HIV-1 particles is about 0.9 days. Viral infection models with both CTL immunity and time delays were introduced in several works (see, e.g., [15,16,17,18]).
Cell-to-cell (CTC) transmission: the above model assumes that the infection occurs via virus-to-cell (VTC) contact. However, several research works reported that HIV-1 can be directly transferred from an infected CD 4 + T cell to a healthy CD 4 + T cell through the formation of virological synapses (see, e.g., [19,20,21,22,23,24]). CTC has great influence on HIV-1 infection, which might be 100–1000 times faster than VTC virus spread [25]. In [26,27], viral infection models with latently infected cells and CTC transmission were studied.
Immune impairment: models (1) and (2) assume that the presence of an antigen can only simulate the immune CTL response, and neglect the CTL immune impairment. In fact, HIV-1 is one of the viruses that has the ability to suppress the CTL response and cause CTL immune impairment [28]. In this case, the pollution dynamics of the CTLs can be written as follows (see, e.g., [28,29,30,31,32,33,34,35]):
I ˙ ( t ) = λ Y ( t ) δ I ( t ) Y ( t ) π I t ,
where, λ Y is the stimulation of CTL immunity and δ I Y is the CTL immune impairment. Modeling the latently infected cells and CTL immune impairment was studied in [36,37]. Intracellular time delay was considered in [36], while CTL immune response delay was considered in [37].
A viral infection model with CTL immune impairment, latently infected cells and CTC transmission can be written as [38,39,40]:
H ˙ ( t ) = α η H t ρ 1 H t V t ρ 3 H t Y t ,
S ˙ ( t ) = ρ 1 H t V t + ρ 3 H t Y t σ + μ S t ,
Y ˙ ( t ) = σ S t τ Y t γ I t Y t ,
V ˙ ( t ) = ε Y t θ V t ,
I ˙ ( t ) = λ Y t π I t δ I t Y t ,
where, S ( t ) is the concentration of the latently infected cells at time t. The healthy CD4 + T cells become infected by two modes: the VTC infection mode via HIV-1, ρ 1 H V and the CTC infection mode via actively infected cells, ρ 3 H Y . Latently infected cells are activated at rate σ S and die at rate μ S . Elaiw et al. [41] studied a virus dynamics model with CTC infection, immune impairment and intracellular time delay. In [40], CTL immune response delay was included. Alofi and Azoz [39] studied a viral infection model with general VTC and CTC infection rates.
We noted that the models presented in [38,39,40] assume that the CTC transmission is only due to the actively infected cells. However, it was reported in Ref. [42] that latently infected cells can also infect the healthy CD 4 + T cells through the CTC mechanism. In Refs. [43,44,45,46,47,48,49], some virus dynamics models were developed by assuming that both latently and actively infected cells contribute to the CTC mechanism. However, the immune impairment was not considered in these papers.
The aim of the present work is to study two within-host HIV-1 dynamics models by involving latently infected cells, CTL immune impairment and CTC transmission. Both latently and actively infected cells contribute in CTC infection. In the second model, we included three types of distributed time delays. For both models we are investigating the non-negativity and boundedness of solutions, calculating the basic reproduction number, finding the model’s equilibria, establishing the global stability of equilibria, confirming the theoretical results by numerical simulation and discussing the obtained results.

2. Model with Latent CTC Transmission and CTL Immune Impairment

2.1. System Description

We propose an HIV-1 dynamics model with immune impairment, latently infected cells and two modes of transmissions, namely VTC and CTC. Both latently and actively infected cells contribute to CTC infection. Under these assumptions, we present the following model:
H ˙ ( t ) = α η H t ρ 1 H t V t ρ 2 H t S t ρ 3 H t Y t , S ˙ ( t ) = ρ 1 H t V t + ρ 2 H t S t + ρ 3 H t Y t σ + μ S t , Y ˙ ( t ) = σ S t τ Y t γ I t Y t , V ˙ ( t ) = ε Y t θ V t , I ˙ ( t ) = λ Y t π I t δ I t Y t .
In our proposed model we assume that the healthy CD4 + T cells become infected by three rates: the VTC infection rate via HIV-1 particles, ρ 1 H V , the CTC infection rate via latently infected cells, ρ 2 H S , and the CTC infection rate via actively infected cells, ρ 3 H Y .

2.2. Basic Properties

2.2.1. Nonnegativity and Boundedness of the Solutions

Lemma 1. 
Consider system (8), then there exists a positively invariant compact set
Ω = H , S , Y , V , I R 0 5 : 0 H t , S t , Y t Λ 1 , 0 V t Λ 2 , 0 I t Λ 3 .
Proof. 
We have
H ˙ H = 0 = α > 0 , S ˙ S = 0 = ρ 1 H V + ρ 3 H Y 0 , for all H , V , Y 0 , Y ˙ Y = 0 = σ S 0 , for all S 0 , V ˙ V = 0 = ε Y 0 , for all Y 0 , I ˙ I = 0 = λ Y 0 , for all Y 0 .
Therefore, ( H ( t ) , S ( t ) , Y ( t ) , V ( t ) , I ( t ) ) R 0 5 , for all t 0 when ( H ( 0 ) , S ( 0 ) , Y ( 0 ) , V ( 0 ) , I ( 0 ) ) R 0 5 . Now, we define
T t = H t + S t + Y t + τ 2 ε V t + τ 4 λ I t .
Then, we have
T ˙ t = H ˙ t + S ˙ t + Y ˙ t + τ 2 ε V ˙ t + τ 4 λ I ˙ t = α η H t μ S t τ 4 Y t γ + τ δ 4 λ I t Y t τ θ 2 ε V t τ π 4 λ I t α η H t μ S t τ 4 Y t τ θ 2 ε V t τ π 4 λ I t α ϕ H t + S t + Y t + τ 2 ε V t + τ 4 λ I t = α ϕ T t ,
where ϕ = min η , μ , τ 4 , θ , π . Hence,
T t e ϕ t T 0 α ϕ + α ϕ .
This yields 0 T t Λ 1 if T 0 Λ 1 , where Λ 1 = α ϕ . Since all state variables are nonnegative, then 0 H t , S t , Y t Λ 1 , 0 V t Λ 2 , and 0 I t Λ 3 , for all t 0 if H 0 + S 0 + Y 0 + τ 2 ε V 0 + τ 4 λ I 0 Λ 1 , where Λ 2 = 2 ε Λ 1 τ and Λ 3 = 4 λ Λ 1 τ . Therefore, H t , S t , Y t , V t and I t are all bounded, which implies that Ω is a positively invariant compact set with respect to system (8). □

2.2.2. Reproduction Number and Equilibria

Lemma 2. 
For system (8), there exists a positive basic reproduction number 0 such that
(i) 
there exists only one equilibrium point Q 0 when 0 1 , and
(ii) 
there exists two equilibria Q 0 and Q 1 when 0 > 1 .
Proof. 
It is clear that system (8) always admits an infection-free equilibrium Q 0 = H 0 , 0 , 0 , 0 , 0 , where H 0 = α η . Now, we apply the method of the next-generation matrix proposed in [50] to determine the basic reproduction number of system (8) based on the infected compartments in model (8), ordered S , Y , V . The nonlinear terms with new infection Γ ^ 1 and the outflow term Δ ^ 1 are given by the following matrices:
Γ ^ 1 = ρ 1 H V + ρ 2 H S + ρ 3 H Y 0 0 , Δ ^ 1 = σ + μ S σ S + τ Y + γ I Y ε Y + θ V .
We compute the derivative of Γ ^ 1 and Δ ^ 1 at the equilibrium Q 0 to obtain the following matrices:
Γ 1 = ρ 2 H 0 ρ 3 H 0 ρ 1 H 0 0 0 0 0 0 0 , Δ 1 = σ + μ 0 0 σ τ 0 0 ε θ .
Note that the next generation matrix is in the following form:
Γ 1 Δ 1 1 = H 0 ρ 1 ε σ + ρ 2 θ τ + ρ 3 σ θ σ + μ θ τ H 0 ρ 1 ε + ρ 3 θ θ τ ρ 1 H 0 θ 0 0 0 0 0 0 .
The basic reproduction number 0 is the spectral radius of the matrix Γ 1 Δ 1 1 and is given as:
0 = H 0 ρ 1 ε σ + ρ 2 θ τ + ρ 3 σ θ σ + μ θ τ = 01 + 02 + 03 ,
where
01 = H 0 ε σ ρ 1 θ τ σ + μ , 02 = H 0 ρ 2 σ + μ , 03 = H 0 σ ρ 3 τ σ + μ .
Note that the parameter 01 measures the average number of secondary infected cells caused by the contact between the virus particles and the healthy cells, while 02 and 03 measure the average number of secondary infected cells caused by surviving latently and actively infected cells, respectively. To find the other equilibrium in addition to Q 0 , we let H , S , Y , V , I be any equilibrium satisfying the following equations:
0 = α η H ρ 1 H V ρ 2 H S ρ 3 H Y ,
0 = ρ 1 H V + ρ 2 H S + ρ 3 H Y σ + μ S ,
0 = σ S τ Y γ I Y ,
0 = ε Y θ V ,
0 = λ Y π I δ I Y .
From Equations (13) and (14), we obtain
V = ε Y θ , I = λ Y π + δ Y .
Substituting from Equation (15) into Equation (12), we obtain
S = π τ Y + γ λ + τ δ Y 2 σ π + δ Y .
From Equations (10) and (11), we obtain
α η H = σ + μ S .
Substituting from Equation (16) into Equation (17), we obtain
H = 1 η α σ + μ π τ Y + γ λ + τ δ Y 2 σ π + δ Y .
Substituting from Equations (15), (16) and (18) into Equation (11), we obtain
η θ Y σ π + δ Y 2 A Y 3 + B Y 2 + C Y + D = 0 ,
where
A = σ + μ γ λ + δ τ θ ρ 2 δ τ + γ λ + δ σ ε ρ 1 + θ ρ 3 , B = δ η θ σ + μ γ λ + δ τ + π τ σ + μ α δ δ σ ε ρ 1 + θ ρ 3 + θ γ λ + δ τ ρ 2 + π σ + μ γ λ + δ τ ε σ ρ 1 + θ τ ρ 2 + σ ρ 3 , C = η θ π σ + μ 2 δ τ + γ λ α π δ σ ε ρ 1 + θ ρ 3 + θ γ λ + δ τ ρ 2 + π π τ σ + μ α δ ε σ ρ 1 + θ τ ρ 2 + σ ρ 3 , D = η θ τ π 2 σ + μ 1 0 ,
where 0 is defined by Equation (9). From Equation (19), we have
  • If Y = 0 , then from Equations (15), (16) and (18) we obtain the infection-free equilibrium Q 0 .
  • If Y 0 , then we have A Y 3 + B Y 2 + C Y + D = 0 . In this case, let us define a function Ψ Y on [ 0 , ) as:
    Ψ Y = A Y 3 + B Y 2 + C Y + D .
    We have Ψ 0 = η θ τ π 2 σ + μ 1 0 < 0 when 0 > 1 and lim Y Ψ Y = , which implies that Ψ has a positive real root Y 1 . Then, by substituting from Equations (15) and (16) into Equation (10), we obtain
    H 1 = α η + ρ 1 V 1 + ρ 2 S 1 + ρ 3 Y 1 ,
    where
    S 1 = π τ Y 1 + γ λ + δ τ Y 1 2 σ π + δ Y 1 , V 1 = ε Y 1 θ , I 1 = λ Y 1 π + δ Y 1 .
It is clear that the infected equilibrium Q 1 = H 1 , S 1 , Y 1 , V 1 , I 1 exists when 0 > 1 . □

2.2.3. Stability of Equilibria Q 0 and Q 1

Theorem 1. 
If 0 < 1 , then the Q 0 of system (8) is locally asymptotically stable (L.A.S), and unstable when 0 > 1 .
Proof. 
Following the work by Willems [51], local asymptotic stability of equilibrium Q 0 is determined by the eigenvalues of its corresponding Jacobian matrix which is given by
J 1 = η ρ 1 V ρ 2 S ρ 3 Y ρ 2 H ρ 3 H ρ 1 H 0 ρ 1 V + ρ 2 S + ρ 3 Y ρ 2 H σ + μ ρ 3 H ρ 1 H 0 0 σ τ + γ I 0 γ Y 0 0 ε θ 0 0 0 λ δ I 0 π + δ Y .
For matrix (20), the characteristic equation J 1 x I 5 = 0 is solved as x + π x + η K x = 0 , where
K x = x 3 + m 2 x 2 + m 1 x + m 0 ,
and
m 0 = θ τ σ + μ 1 0 > 0 , m 1 = θ τ + θ σ + μ 1 02 + τ σ + μ 1 02 + 03 > 0 , m 2 = θ + τ + σ + μ 1 02 > 0 , m 1 m 2 m 0 = α ε σ ρ 1 η + τ + σ + μ 1 02 θ ( θ + τ ) + θ σ + μ 1 02 + τ σ + μ 1 02 + 03 > 0 ,
where 0 < 1 . It is clear that the Jacobian matrix J 1 has two negative eigenvalues, π and η . Other eigenvalues are calculated as the roots of the cubic equation presented in (21). All roots of Equation (21) have negative real parts based on Routh-Hurwitz criteria [51]. Therefore, the infection-free equilibrium Q 0 is L.A.S when 0 < 1 . Let 0 > 1 , then we have  m 0 < 0 . This means that Equation (21) has at least one positive real root. Hence, Q 0 is unstable when 0 > 1 . □
In the following theorems, global stability of equilibria will be discussed. Let a function F be defined as F z = z 1 ln z . Denote H , S , Y , V , I = H t , S t , Y t , V t , I t .
Theorem 2. 
For system (8), if 0 < 1 , then Q 0 is globally asymptotically stable (G.A.S).
Proof. 
We define a Lyapunov function candidate as:
Θ 0 = H 0 F H H 0 + S + σ + μ 1 02 σ Y + ρ 1 H 0 θ V + τ σ + μ 1 0 λ σ I .
Clearly, Θ 0 ( H , S , Y , V , I ) > 0 for all H , S , Y , V , I > 0 , and Θ 0 ( H 0 , 0 , 0 , 0 , 0 ) = 0 . We calculate d Θ 0 d t along the solutions of model (8) as:
d Θ 0 d t = 1 H 0 H d H d t + d S d t + σ + μ 1 02 σ d Y d t + ρ 1 H 0 θ d V d t + τ σ + μ 1 0 λ σ d I d t = 1 H 0 H α η H ρ 1 H V ρ 2 H S ρ 3 H Y + ρ 1 H V + ρ 2 H S + ρ 3 H Y σ + μ S + σ + μ 1 02 σ σ S τ Y γ I Y + ρ 1 H 0 θ ε Y θ V + τ σ + μ 1 0 λ σ λ Y π I δ I Y = 1 H 0 H α η H + ρ 2 H 0 σ + μ + σ + μ 1 02 S + ρ 3 H 0 τ σ + μ 1 02 σ + ρ 1 H 0 ε θ + τ σ + μ 1 0 σ Y π τ σ + μ 1 0 λ σ I γ σ + μ 1 02 σ + δ τ σ + μ 1 0 λ σ I Y .
After direct calculation and using H 0 = α / η , we obtain
d Θ 0 d t = 1 H 0 H η H 0 η H π τ σ + μ 1 0 λ σ I σ + μ λ σ γ λ 1 02 + τ δ 1 0 I Y = η H H 0 2 H π τ σ + μ 1 0 λ σ I σ + μ λ σ γ λ 1 02 + τ δ 1 0 I Y .
Clearly, d Θ 0 d t 0 when 0 < 1 with equality holding when H = H 0 and Y = I = 0 . Let Φ 0 = H , S , Y , V , I : d Θ 0 d t = 0 , and Φ 0 be the largest invariant subset of Φ 0 . Therefore, all solutions converge to Φ 0 [52]. All elements in Φ 0 satisfy H ( t ) = H 0 and Y ( t ) = I ( t ) = 0 . Then, the third equation of system (8) gives
0 = Y ˙ t = σ S t S t = 0 , for all t .
Moreover, the first equation of model (8) yields
0 = H ˙ t = α η H 0 ρ 1 H 0 V t V t = 0 , for all t .
Therefore, Φ 0 = H , S , Y , V , I Φ 0 : H = H 0 , S = Y = V = I = 0 = Q 0 . Hence, we obtain that when 0 < 1 , then Q 0 is G.A.S according to the LaSalle’s invariance principle (L.I.P) [52]. □
Theorem 3. 
For system (8), if 0 > 1 , then Q 1 is G.A.S.
Proof. 
Define
Θ 1 = H 1 F H H 1 + S 1 F S S 1 + H 1 ρ 1 ε + ρ 3 θ Y 1 θ τ + γ I 1 F Y Y 1 + ρ 1 H 1 V 1 θ F V V 1 + γ H 1 ρ 1 ε + ρ 3 θ 2 θ τ + γ I 1 λ δ I 1 I I 1 2 .
It is noted from the equilibrium condition Equation (14) that λ δ I 1 = π I 1 Y 1 > 0 . Clearly, Θ 1 is positive definite. We calculate d Θ 1 d t as:
d Θ 1 d t = 1 H 1 H d H d t + 1 S 1 S d S d t + H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 1 Y 1 Y d Y d t + ρ 1 H 1 θ 1 V 1 V d V d t + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 I I 1 d I d t = 1 H 1 H α η H ρ 1 H V ρ 2 H S ρ 3 H Y + 1 S 1 S ρ 1 H V + ρ 2 H S + ρ 3 H Y σ + μ S + H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 1 Y 1 Y σ S τ Y γ I Y + ρ 1 H 1 θ 1 V 1 V ε Y θ V + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 I I 1 λ Y π I δ I Y = 1 H 1 H α η H + ρ 2 H 1 σ + μ + σ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 S + ρ 3 H 1 Y ρ 1 H V + ρ 2 H S + ρ 3 H Y S 1 S + σ + μ S 1 σ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 S Y 1 Y τ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I Y Y 1 + ρ 1 H 1 ε θ Y ρ 1 H 1 ε θ Y V 1 V + ρ 1 H 1 V 1 + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 I I 1 λ Y π I δ I Y .
Using the following equilibrium conditions for Q 1
α = η H 1 + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 , ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 = σ + μ S 1 , σ S 1 = τ + γ I 1 Y 1 Y 1 = σ S 1 τ + γ I 1 , V 1 = ε Y 1 θ , λ Y 1 π I 1 δ I 1 Y 1 = 0 ,
We obtain
ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 = H 1 ρ 1 ε + ρ 3 θ Y 1 θ = σ H 1 ρ 1 ε + ρ 3 θ S 1 θ τ + γ I 1 , ρ 2 H 1 σ + μ + σ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 S 1 = 0 .
Therefore, Equation (22) will take the following form:
d Θ 1 d t = 1 H 1 H η H 1 η H + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 1 H 1 H + ρ 3 H 1 Y ρ 1 H 1 V 1 H V S 1 H 1 V 1 S ρ 2 H 1 S 1 H H 1 ρ 3 H 1 Y 1 H Y S 1 H 1 Y 1 S + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 σ H 1 ρ 1 ε + ρ 3 θ S 1 θ τ + γ I 1 S Y 1 S 1 Y τ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I Y Y 1 + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I 1 Y Y 1 + ρ 1 H 1 ε Y 1 θ Y Y 1 ρ 1 H 1 ε Y 1 θ Y V 1 Y 1 V + ρ 1 H 1 V 1 + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 I I 1 λ Y π I δ I Y λ Y 1 + π I 1 + δ I 1 Y 1 + δ I 1 Y δ I 1 Y = η H H 1 2 H + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 2 H 1 H + ρ 3 H 1 Y ρ 1 H 1 V 1 H V S 1 H 1 V 1 S ρ 2 H 1 S 1 H H 1 ρ 3 H 1 Y 1 H Y S 1 H 1 Y 1 S ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 S Y 1 S 1 Y H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 τ + γ I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I I 1 Y Y 1 + ρ 1 H 1 V 1 Y Y 1 ρ 1 H 1 V 1 Y V 1 Y 1 V + ρ 1 H 1 V 1 + γ λ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 I I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I 1 λ δ I 1 I I 1 2 δ γ H 1 ρ 1 ε + ρ 3 θ I 1 θ τ + γ I 1 λ δ I 1 I I 1 Y Y 1 .
This implies that
d Θ 1 d t = η H H 1 2 H + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 2 H 1 H + ρ 3 H 1 Y ρ 1 H 1 V 1 H V S 1 H 1 V 1 S ρ 2 H 1 S 1 H H 1 ρ 3 H 1 Y 1 H Y S 1 H 1 Y 1 S ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 S Y 1 S 1 Y H 1 ρ 1 ε + ρ 3 θ θ Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 I I 1 Y Y 1 + ρ 1 H 1 V 1 Y Y 1 ρ 1 H 1 V 1 Y V 1 Y 1 V + ρ 1 H 1 V 1 + γ H 1 ρ 1 ε + ρ 3 θ θ τ + γ I 1 λ δ I 1 λ δ I 1 I I 1 Y Y 1 γ H 1 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I 1 λ δ I 1 I I 1 2 = η H H 1 2 H + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 2 H 1 H + ρ 3 H 1 Y ρ 1 H 1 V 1 H V S 1 H 1 V 1 S ρ 2 H 1 S 1 H H 1 ρ 3 H 1 Y 1 H Y S 1 H 1 Y 1 S ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 S Y 1 S 1 Y H 1 ρ 1 ε + ρ 3 θ Y 1 θ Y Y 1 1 + ρ 1 H 1 V 1 Y Y 1 ρ 1 H 1 V 1 Y V 1 Y 1 V + ρ 1 H 1 V 1 γ H 1 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I 1 λ δ I 1 I I 1 2 = η H H 1 2 H + ρ 1 H 1 V 1 + ρ 2 H 1 S 1 + ρ 3 H 1 Y 1 2 H 1 H + ρ 3 H 1 Y ρ 1 H 1 V 1 H V S 1 H 1 V 1 S ρ 2 H 1 S 1 H H 1 ρ 3 H 1 Y 1 H Y S 1 H 1 Y 1 S ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 S Y 1 S 1 Y ρ 1 H 1 V 1 + ρ 3 H 1 Y 1 Y Y 1 1 + ρ 1 H 1 V 1 Y Y 1 ρ 1 H 1 V 1 Y V 1 Y 1 V + ρ 1 H 1 V 1 γ H 1 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I 1 λ δ I 1 I I 1 2 .
Finally, we obtain
d Θ 1 d t = η + ρ 2 S 1 H H 1 2 H + ρ 1 H 1 V 1 4 H 1 H H V S 1 H 1 V 1 S S Y 1 S 1 Y Y V 1 Y 1 V + ρ 3 H 1 Y 1 3 H 1 H H Y S 1 H 1 Y 1 S S Y 1 S 1 Y γ H 1 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I 1 λ δ I 1 I I 1 2 .
The geometrical and arithmetical means relationship implies
4 H 1 H + H V S 1 H 1 V 1 S + S Y 1 S 1 Y + Y V 1 Y 1 V , 3 H 1 H + H Y S 1 H 1 Y 1 S + S Y 1 S 1 Y .
Hence, if 0 > 1 , then d Θ 1 d t 0 for all H , S , Y , V , I > 0 . Additionally, d Θ 1 d t = 0 when H = H 1 , S = S 1 , Y = Y 1 , V = V 1 and I = I 1 . Let Φ 1 be the largest invariant subset of Φ 1 = H , S , Y , V , I : d Θ 1 d t = 0 . Therefore, Φ 1 = Q 1 . Applying L.I.P, we obtain that if 0 > 1 , then  Q 1 is G.A.S [52]. □

3. Model with Distributed Time Delays

3.1. System Description

In the following model, we consider the distributed time delays in system (8) to become represented by delay differential equations (DDEs):
H ˙ ( t ) = α η H t ρ 1 H t V t ρ 2 H t S t ρ 3 H t Y t , S ˙ ( t ) = 0 k 1 f 1 ϱ e h 1 ϱ H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ ( σ + μ ) S t , Y ˙ ( t ) = σ 0 k 2 f 2 ϱ e h 2 ϱ S t ϱ d ϱ τ Y t γ I t Y t , V ˙ ( t ) = ε 0 k 3 f 3 ϱ e h 3 ϱ Y t ϱ d ϱ θ V t , I ˙ ( t ) = λ Y t π I t δ I t Y t .
Here, f 1 ϱ e h 1 ϱ demonstrates the probability that healthy CD4 + T cells contacted by HIV-1 particles or infected cells at time t ϱ and after surviving ϱ time units become latently infected cells at time t. The factor f 2 ϱ e h 2 ϱ is the probability that latently infected cells after surviving ϱ time units turned to actively infected cells at time t. Further, the factor f 3 ϱ e h 3 ϱ represents the probability of new HIV-1 particles after surviving ϱ time units and maturing at time t. Here, h i > 0 ,   i = 1 , 2 , 3 are constants. ϱ is the delay parameter taken from a probability distribution function f i ϱ over the interval [ 0 , k i ] ,   i = 1 , 2 , 3 , where k i is the limit superior of the delay period. Function f i ϱ ,   i = 1 , 2 , 3 satisfies the following conditions:
f i ϱ > 0 , 0 k i f i ϱ d ϱ = 1 , and 0 k i f i ϱ e β ϱ d ϱ < , where β > 0 .
Let F ¯ i ( ϱ ) = f i ( ϱ ) e h i ϱ and F i = 0 k i F ¯ i ( ϱ ) d ϱ ,   i = 1 , 2 , 3 . Therefore, 0 < F i 1 ,   i = 1 , 2 , 3 .
The initial conditions of system (23) are:
H r = a 1 r , S r = a 2 r , Y r = a 3 r , V r = a 4 r , I r = a 5 r , a j r 0 , j = 1 , 2 , , 5 , r [ k , 0 ] , k = max { k 1 , k 2 , k 3 } ,
where a j r C ( [ k , 0 ] , R 0 ) ,   j = 1 , 2 , , 5 and C =   C k , 0 , R 0 is the Banach space of continuous functions with norm a j = sup k ζ 0 a j ζ for all a j C . Therefore, system (23) with initial conditions (24) has a unique solution [52,53]. The biological meaning of all remaining variables and parameters follow the same identifications as given in Section 2.

3.2. Basic Properties

3.2.1. Nonnegativity and Ultimate Boundedness of the Solutions

Lemma 3. 
For system (23together with initial conditions (24), there exists a compact set Ω ^ that is positively invariant, where
Ω ^ = { ( H , S , Y , V , I ) C 0 5 : H ( t ) Λ ^ 1 , S ( t ) Λ ^ 1 , Y ( t ) Λ ^ 2 , I ( t ) Λ ^ 3 , V ( t ) Λ ^ 4 } .
Proof. 
In the beginning we show the nonnegativity of solutions. From the first equation of system (23), we have H ˙ H = 0 = α > 0 , then H ( t ) > 0 , for all t 0 . In addition, from the remaining equations of system (23) we have
S ˙ t + σ + μ S t = 0 k 1 F ¯ 1 ϱ H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ S t = a 2 ( 0 ) e ( σ + μ ) t + 0 t e ( σ + μ ) ( t ϰ ) 0 k 1 F ¯ 1 ϱ H ϰ ϱ ( ρ 1 V ϰ ϱ + ρ 2 S ϰ ϱ + ρ 3 Y ϰ ϱ ) d ϱ d ϰ 0 . Y ˙ t + τ + γ I ( t ) Y ( t ) = σ 0 k 2 F ¯ 2 ϱ S t ϱ d ϱ Y t = a 3 ( 0 ) e 0 t ( τ + γ I ( u ) ) d u + σ 0 t e ϰ t ( τ + γ I ( u ) ) d u 0 k 2 F ¯ 2 ϱ S ϰ ϱ d ϱ d ϰ 0 . V ˙ t + θ V t = ε 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ d ϱ V t = a 4 ( 0 ) e θ t + ε 0 t e θ ( t ϰ ) 0 k 3 F ¯ 3 ϱ Y ϰ ϱ d ϱ d ϰ 0 . I ˙ t + π + δ Y t I t = λ Y t I t = a 5 ( 0 ) e 0 t ( π + δ Y ( u ) ) d u + λ 0 t e ϰ t ( π + δ Y ( u ) ) d u Y ϱ d ϱ 0 ,
for all t [ 0 , k ] . Then, by a recursive argument we have H t , S t , Y t , V t and I t are nonnegative for all t 0 . Therefore, the solutions of system (23) satisfy H t , S t , Y t , V t , I t R 0 5 , for all t 0 . Next, we prove the ultimate boundedness of all solutions. From the first equation of system (23), we have lim t sup H t α η .
Next, we define
T 1 t = 0 k 1 F ¯ 1 ϱ H t ϱ d ϱ + S t .
Then
T ˙ 1 t = 0 k 1 F ¯ 1 ϱ H ˙ t ϱ d ϱ + S ˙ t = 0 k 1 F ¯ 1 ( ϱ ) α η H t ϱ d ϱ σ + μ S t = α F 1 η 0 k 1 F ¯ 1 ( ϱ ) H t ϱ d ϱ σ + μ S t α ϕ 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ d ϱ + S t = α ϕ 1 T 1 t ,
where ϕ 1 = min { η , σ + μ } . This implies that lim t sup T 1 t α ϕ 1 = Λ ^ 1 . Since 0 k 1 F ¯ 1 ϱ H t ϱ d ϱ and S t are nonnegative, then lim t sup S t Λ ^ 1 . In addition, we let
T 2 t = Y t + τ 2 λ I t .
This yields
T ˙ 2 t = Y ˙ t + τ 2 λ I ˙ t = σ 0 k 2 F ¯ 2 ϱ S t ϱ d ϱ τ Y t γ I t Y t + τ 2 λ λ Y t π I t δ I t Y t = σ 0 k 2 F ¯ 2 ϱ S t ϱ d ϱ τ 2 Y t τ π 2 λ I t ( γ + τ δ 2 λ ) I t Y t σ 0 k 2 F ¯ 2 ϱ S t ϱ d ϱ τ 2 Y t τ π 2 λ I t σ Λ ^ 1 ϕ 2 Y t + τ 2 λ I t = σ Λ ^ 1 ϕ 2 T 2 t ,
where ϕ 2 = min { τ 2 , π } . Hence, lim t sup T 2 t σ Λ ^ 1 ϕ 2 = Λ ^ 2 . Since Y t and I t are nonnegative, then lim t sup Y t Λ ^ 2 , and lim t sup I t 2 λ Λ ^ 2 τ = Λ ^ 3 . Finally, from the fourth equation of system (23), we obtain
V ˙ t = ε 0 k 3 F ¯ 3 ϱ Y t ϱ d ϱ θ V t ε F 3 Λ ^ 2 θ V t ε Λ ^ 2 θ V t .
Therefore, lim t sup V ( t ) ε Λ ^ 2 θ = Λ ^ 4 . We conclude that H t , S t , Y t , V t and I t are ultimately bounded. Thus, the compact set Ω ^ is positively invariant with respect to system (23). □

3.2.2. Reproduction Number and Equilibria

Lemma 4. 
For system (23), there exists a positive basic reproduction number ˜ 0 such that
(i) 
there exists only one equilibrium point Q ˜ 0 when ˜ 0 1 , and
(ii) 
there exists two equilibria Q ˜ 0 and Q ˜ 1 when ˜ 0 > 1 .
Proof. 
It is clear that system (23) always has an infection-free equilibrium Q ˜ 0 = ( H ˜ 0 , 0 , 0 , 0 , 0 ) , where H ˜ 0 = α η . In the following, we will apply the method of next generation matrix to determine the basic reproduction number of system (23). Based on the infected compartments in model (23), ordered S , Y , V . The nonlinear terms with new infection Γ ^ 2 and the outflow term Δ ^ 2 are given by the following matrices:
Γ ^ 2 = F 1 ρ 1 H V + ρ 2 H S + ρ 3 H Y 0 0 , Δ ^ 2 = ( σ + μ ) S σ F 2 S + τ Y + γ I Y ε F 3 Y + θ V .
We compute the derivative of Γ ^ 2 and Δ ^ 2 at the equilibrium Q ˜ 0 to obtain the following matrices:
Γ 2 = F 1 ρ 2 H ˜ 0 F 1 ρ 3 H ˜ 0 F 1 ρ 1 H ˜ 0 0 0 0 0 0 0 , Δ 2 = σ + μ 0 0 σ F 2 τ 0 0 ε F 3 θ .
Note that the next generation matrix is in the following form:
Γ 2 Δ 2 1 = F 1 H ˜ 0 F 2 σ F 3 ρ 1 ε + ρ 3 θ + ρ 2 θ τ σ + μ θ τ F 1 H ˜ 0 F 3 ρ 1 ε + ρ 3 θ θ τ F 1 H ˜ 0 ρ 1 θ 0 0 0 0 0 0 .
The basic reproduction number ˜ 0 is the spectral radius of the matrix Γ 2 Δ 2 1 and is given as:
˜ 0 = F 1 H ˜ 0 F 2 σ F 3 ρ 1 ε + ρ 3 θ + ρ 2 θ τ σ + μ θ τ = ˜ 01 + ˜ 02 + ˜ 03 ,
where
˜ 01 = F 1 F 2 F 3 H ˜ 0 ε σ ρ 1 θ τ σ + μ , ˜ 02 = F 1 H ˜ 0 ρ 2 σ + μ , ˜ 03 = F 1 F 2 H ˜ 0 σ ρ 3 τ σ + μ .
Note that all parameters ˜ 0 i , i = 1 , 2 , 3 have the same biological meaning as the parameters 0 i , i = 1 , 2 , 3 that are explained in Section 2. To find the other equilibrium in addition to Q ˜ 0 , we let H , S , Y , V , I be any equilibrium satisfying the following equations:
0 = α η H ρ 1 H V ρ 2 H S ρ 3 H Y ,
0 = F 1 ρ 1 H V + ρ 2 H S + ρ 3 H Y σ + μ S ,
0 = σ F 2 S τ Y γ I Y ,
0 = ε F 3 Y θ V ,
0 = λ Y π I δ I Y .
From Equations (29) and (30), we obtain
V = ε F 3 Y θ , I = λ Y π + δ Y .
Substituting from Equation (31) into Equation (28), we obtain
S = π τ Y + γ λ + τ δ Y 2 σ F 2 π + δ Y .
From Equations (26) and (27), we obtain
α η H = σ + μ S F 1 .
Substituting from Equation (32) into Equation (33), we obtain
H = 1 η α σ + μ π τ Y + γ λ + τ δ Y 2 σ F 1 F 2 π + δ Y .
Substituting from Equations (31), (32) and (34) into Equation (27), we obtain
Y η θ σ 2 F 2 2 π + δ Y 2 A ˜ Y 3 + B ˜ Y 2 + C ˜ Y + D ˜ = 0 ,
where
A ˜ = σ + μ ( γ λ + τ δ ) θ ρ 2 ( γ λ + τ δ ) + δ σ F 2 ε F 3 ρ 1 + θ ρ 3 , B ˜ = σ + μ ( γ λ + τ δ ) δ σ η θ F 2 + π θ τ ρ 2 + π σ F 2 ε F 3 ρ 1 + θ ρ 3 + π τ σ + μ α δ σ F 1 F 2 θ ρ 2 ( γ λ + τ δ ) + δ σ F 2 ε F 3 ρ 1 + θ ρ 3 , C ˜ = π π θ ρ 2 τ 2 σ + μ 2 α δ σ 2 F 1 F 2 2 ε F 3 ρ 1 + θ ρ 3 + σ F 2 π ε τ F 3 ρ 1 σ + μ + θ γ λ + 2 τ δ η σ + μ α F 1 ρ 2 + π θ τ ρ 3 σ + μ , D ˜ = σ η θ τ F 2 π 2 σ + μ 1 ˜ 0 ,
where ˜ 0 is defined by Equation (25). From Equation (35), we have
  • If Y = 0 , then from Equations (31), (32) and (34) we obtain the infection-free equilibrium Q ˜ 0 .
  • If Y 0 , then we have A ˜ Y 3 + B ˜ Y 2 + C ˜ Y + D ˜ = 0 . In this case, let us define a function Ψ ¯ Y on [ 0 , ) as:
    Ψ ¯ Y = A ˜ Y 3 + B ˜ Y 2 + C ˜ Y + D ˜ .
    We have
    Ψ ¯ 0 = σ η θ τ F 2 π 2 σ + μ 1 ˜ 0 < 0 if ˜ 0 > 1 , lim Y Ψ ¯ Y = ,
    which show that Ψ ¯ has a positive real root Y ˜ 1 . Then, by substituting from Equations (31) and (32) into Equation (26), we obtain
    H ˜ 1 = α η + ρ 1 V ˜ 1 + ρ 2 S ˜ 1 + ρ 3 Y ˜ 1 ,
    where
    S ˜ 1 = π τ Y ˜ 1 + ( γ λ + τ δ ) Y ˜ 1 2 σ F 2 π + δ Y ˜ 1 , V ˜ 1 = ε F 3 Y ˜ 1 θ , I ˜ 1 = λ Y ˜ 1 π + δ Y ˜ 1 .
It is clear that the infected equilibrium Q ˜ 1 = H ˜ 1 , S ˜ 1 , Y ˜ 1 , V ˜ 1 , I ˜ 1 exists when ˜ 0 > 1 . □

3.2.3. Stability of Equilibria Q ˜ 0 and Q ˜ 1

In the following theorems, global asymptotic stability of equilibria will be discussed.
Theorem 4. 
For system (23), if ˜ 0 < 1 , then Q ˜ 0 is G.A.S and it is unstable when ˜ 0 > 1 .
Proof. 
Consider
Θ ˜ 0 = H ˜ 0 F H H ˜ 0 + 1 F 1 S + σ + μ 1 ˜ 02 σ F 1 F 2 Y + ρ 1 H ˜ 0 θ V + τ σ + μ 1 ˜ 0 λ σ F 1 F 2 I + 1 F 1 0 k 1 F ¯ 1 ( ϱ ) t ϱ t H ( ϰ ) ρ 1 V ( ϰ ) + ρ 2 S ( ϰ ) + ρ 3 Y ( ϰ ) d ϰ d ϱ + σ + μ 1 ˜ 02 F 1 F 2 0 k 2 F ¯ 2 ( ϱ ) t ϱ t S ( ϰ ) d ϰ d ϱ + ρ 1 H ˜ 0 ε θ 0 k 3 F ¯ 3 ( ϱ ) t ϱ t Y ( ϰ ) d ϰ d ϱ .
Clearly, Θ ˜ 0 ( H , S , Y , V , I ) > 0 for all H , S , Y , V , I > 0 , and Θ ˜ 0 ( H 0 , 0 , 0 , 0 , 0 ) = 0 . We calculate d Θ ˜ 0 d t as:
d Θ ˜ 0 d t = 1 H ˜ 0 H d H d t + 1 F 1 d S d t + σ + μ 1 ˜ 02 σ F 1 F 2 d Y d t + ρ 1 H ˜ 0 θ d V d t + τ σ + μ 1 ˜ 0 λ σ F 1 F 2 d I d t + H ρ 1 V + ρ 2 S + ρ 3 Y 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ + σ + μ 1 ˜ 02 F 1 S σ + μ 1 ˜ 02 F 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ d ϱ + ρ 1 H ˜ 0 ε F 3 θ Y ρ 1 H ˜ 0 ε θ 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ d ϱ = 1 H ˜ 0 H α η H ρ 1 H V ρ 2 H S ρ 3 H Y + 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ σ + μ S F 1 + σ + μ 1 ˜ 02 F 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ d ϱ τ σ + μ 1 ˜ 02 σ F 1 F 2 Y γ σ + μ 1 ˜ 02 σ F 1 F 2 I Y + ρ 1 H ˜ 0 ε θ 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ d ϱ ρ 1 H ˜ 0 V + τ σ + μ 1 ˜ 0 λ σ F 1 F 2 λ Y π I δ I Y + ρ 1 H V + ρ 2 H S + ρ 3 H Y 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ + σ + μ 1 ˜ 02 F 1 S σ + μ 1 ˜ 02 F 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ d ϱ + ρ 1 H ˜ 0 ε F 3 θ Y ρ 1 H ˜ 0 ε θ 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ d ϱ .
After direct calculation and using H ˜ 0 = α / η , we obtain
d Θ ˜ 0 d t = 1 H ˜ 0 H η H ˜ 0 η H π τ σ + μ 1 ˜ 0 λ σ F 1 F 2 I σ + μ λ σ F 1 F 2 γ λ 1 ˜ 02 + τ δ 1 ˜ 0 I Y = η H H ˜ 0 2 H π τ σ + μ 1 ˜ 0 λ σ F 1 F 2 I σ + μ λ σ F 1 F 2 γ λ 1 ˜ 02 + τ δ 1 ˜ 0 I Y .
Clearly, d Θ ˜ 0 d t 0 when ˜ 0 < 1 with equality holding when H = H ˜ 0 and Y = I = 0 . Let Φ ¯ 0 = H , S , Y , V , I : d Θ ˜ 0 d t = 0 , and Φ ¯ 0 be the largest invariant subset of Φ ¯ 0 . Therefore, all solutions converge to Φ ¯ 0 [52]. All elements in Φ ¯ 0 satisfy H ( t ) = H ˜ 0 and Y ( t ) = I ( t ) = 0 . Then, the third equation of system (23) gives
0 = Y ˙ t = σ 0 k 2 F ¯ 2 ( ϱ ) S t ϱ d ϱ .
The nonnegativity of S implies that S t = 0 for all t . Moreover, the first equation of model (23) yields
0 = H ˙ t = α η H ˜ 0 ρ 1 H ˜ 0 V t V t = 0 , for all t .
Therefore, Φ ¯ 0 = H , S , Y , V , I Φ ¯ 0 : H = H ˜ 0 , S = Y = V = I = 0 = Q ˜ 0 . Hence, according to L.I.P, we obtain that when ˜ 0 < 1 , then Q ˜ 0 is G.A.S [52].
On the other hand, model (23) can be rewritten as:
U ˙ t = F U t , U t ϱ ,
where U t = H t , S t , Y t , V t , I t T . This system is a coupled system of ordinary differential equations with a delay parameter, using total differentiation at Q ˜ 0 we have
H ˙ = F H | Q ˜ 0 H + F S | Q ˜ 0 S + F Y | Q ˜ 0 Y + F V | Q ˜ 0 V + F I | Q ˜ 0 I , S ˙ = F H | Q ˜ 0 H + F S | Q ˜ 0 S + F Y | Q ˜ 0 Y + F V | Q ˜ 0 V + F I | Q ˜ 0 I , Y ˙ = F H | Q ˜ 0 H + F S | Q ˜ 0 S + F Y | Q ˜ 0 Y + F V | Q ˜ 0 V + F I | Q ˜ 0 I , V ˙ = F H | Q ˜ 0 H + F S | Q ˜ 0 S + F Y | Q ˜ 0 Y + F V | Q ˜ 0 V + F I | Q ˜ 0 I , I ˙ = F H | Q ˜ 0 H + F S | Q ˜ 0 S + F Y | Q ˜ 0 Y + F V | Q ˜ 0 V + F I | Q ˜ 0 I .
Suppose that the linear DDEs system (36) has exponential solutions.
H = e x t W H , S = e x t W S , Y = e x t W Y , V = e x t W V , I = e x t W I .
Substituting this ansatz into system (36) and rearranging it, we obtain A W = 0 , where
A = x + η ρ 2 H ˜ 0 ρ 3 H ˜ 0 ρ 1 H ˜ 0 0 0 x + σ + μ ρ 2 H ˜ 0 F ^ 1 ρ 3 H ˜ 0 F ^ 1 ρ 1 H ˜ 0 F ^ 1 0 0 σ F ^ 2 x + τ 0 0 0 0 ε F ^ 3 x + θ 0 0 0 λ 0 x + π , W = W H W S W Y W V W I .
Note that the characteristic equation is the set of x such that matrix A is not invertible, which means det A = 0 , then the characteristic equation of system (23) at Q ˜ 0 is given by x + π x + η K ˜ ( x ) = 0 , where K ˜ ( x ) is a continuous function defined on [ 0 , ) as:
K ˜ ( x ) = x 3 + θ + σ + μ + τ H ˜ 0 F ^ 1 ρ 2 x 2 + τ σ + μ H ˜ 0 F ^ 1 ρ 2 + θ σ + μ + τ H ˜ 0 F ^ 1 ρ 2 σ H ˜ 0 F ^ 1 F ^ 2 ρ 3 x σ ε H ˜ 0 F ^ 1 F ^ 2 F ^ 3 ρ 1 + θ τ σ + μ H ˜ 0 F ^ 1 ρ 2 σ H ˜ 0 F ^ 1 F ^ 2 ρ 3 ,
where F ^ i = 0 k i f i ( ϱ ) e x + h i ϱ d ϱ , i = 1 , 2 , 3 . Let ˜ 0 > 1 , then we have K ˜ ( 0 ) = θ τ σ + μ 1 ˜ 0 < 0 and lim x K ˜ ( x ) = , which implies that K ˜ ( x ) has a positive real root. Hence, Q ˜ 0 is unstable when ˜ 0 > 1 .
Theorem 5. 
For system (23), if ˜ 0 > 1 , then Q ˜ 1 is G.A.S.
Proof. 
Define
Θ ˜ 1 = H ˜ 1 F H H ˜ 1 + S ˜ 1 F 1 F S S ˜ 1 + H ˜ 1 F 3 ρ 1 ε + ρ 3 θ Y ˜ 1 θ τ + γ I ˜ 1 F Y Y ˜ 1 + ρ 1 H ˜ 1 V ˜ 1 θ F V V ˜ 1 + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ 2 θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 2 + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) t ϱ t F H ( ϰ ) V ( ϰ ) H ˜ 1 V ˜ 1 d ϰ d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) t ϱ t F H ( ϰ ) S ( ϰ ) H ˜ 1 S ˜ 1 d ϰ d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) t ϱ t F H ( ϰ ) Y ( ϰ ) H ˜ 1 Y ˜ 1 d ϰ d ϱ + σ H ˜ 1 S ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) t ϱ t F S ( ϰ ) S ˜ 1 d ϰ d ϱ + ρ 1 H ˜ 1 ε Y ˜ 1 θ 0 k 3 F ¯ 3 ( ϱ ) t ϱ t F Y ( ϰ ) Y ˜ 1 d ϰ d ϱ .
It is noted from the equilibrium condition Equation (30) that λ δ I ˜ 1 = π I ˜ 1 Y ˜ 1 > 0 . It is clear that Θ ˜ 1 is positive definite. We calculate d Θ ˜ 1 d t along the solutions of model (23) as:
d Θ ˜ 1 d t = 1 H ˜ 1 H d H d t + 1 F 1 1 S ˜ 1 S d S d t + H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 1 Y ˜ 1 Y d Y d t + ρ 1 H ˜ 1 θ 1 V ˜ 1 V d V d t + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 d I d t + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H V H ˜ 1 V ˜ 1 1 ln H V H ˜ 1 V ˜ 1 H t ϱ V t ϱ H ˜ 1 V ˜ 1 + 1 + ln H t ϱ V t ϱ H ˜ 1 V ˜ 1 d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H S H ˜ 1 S ˜ 1 1 ln H S H ˜ 1 S ˜ 1 H t ϱ S t ϱ H ˜ 1 S ˜ 1 + 1 + ln H t ϱ S t ϱ H ˜ 1 S ˜ 1 d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H Y H ˜ 1 Y ˜ 1 1 ln H Y H ˜ 1 Y ˜ 1 H t ϱ Y t ϱ H ˜ 1 Y ˜ 1 + 1 + ln H t ϱ Y t ϱ H ˜ 1 Y ˜ 1 d ϱ + σ H ˜ 1 S ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) S S ˜ 1 1 ln S S ˜ 1 S t ϱ S ˜ 1 + 1 + ln S t ϱ S ˜ 1 d ϱ + ρ 1 H ˜ 1 ε Y ˜ 1 θ 0 k 3 F ¯ 3 ( ϱ ) Y Y ˜ 1 1 ln Y Y ˜ 1 Y t ϱ Y ˜ 1 + 1 + ln Y t ϱ Y ˜ 1 d ϱ = 1 H ˜ 1 H α η H ρ 1 H V ρ 2 H S ρ 3 H Y + 1 F 1 1 S ˜ 1 S 0 k 1 F ¯ 1 ( ϱ ) H t ϱ ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ σ + μ S + H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 1 Y ˜ 1 Y σ 0 k 2 F ¯ 2 ( ϱ ) S t ϱ d ϱ τ Y γ I Y + ρ 1 H ˜ 1 θ 1 V ˜ 1 V ε 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ d ϱ θ V + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 λ Y π I δ I Y + ρ 1 H ˜ 1 V ˜ 1 F 1 F 1 H V H ˜ 1 V ˜ 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ V t ϱ H ˜ 1 V ˜ 1 ln H t ϱ V t ϱ H V d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 F 1 H S H ˜ 1 S ˜ 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S t ϱ H ˜ 1 S ˜ 1 ln H t ϱ S t ϱ H S d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 F 1 H Y H ˜ 1 Y ˜ 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ Y t ϱ H ˜ 1 Y ˜ 1 ln H t ϱ Y t ϱ H Y d ϱ + σ H ˜ 1 S ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 F 2 S S ˜ 1 0 k 2 F ¯ 2 ( ϱ ) S t ϱ S ˜ 1 ln S t ϱ S d ϱ + ρ 1 H ˜ 1 ε Y ˜ 1 θ F 3 Y Y ˜ 1 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ Y ˜ 1 ln Y t ϱ Y d ϱ .
Thus,
d Θ ˜ 1 d t = 1 H ˜ 1 H α η H + ρ 2 H ˜ 1 σ + μ F 1 + σ F 2 H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 S + ρ 3 H ˜ 1 Y 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S ˜ 1 S ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ + σ + μ S ˜ 1 F 1 σ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) S t ϱ Y ˜ 1 Y d ϱ τ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 Y Y ˜ 1 γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 I Y Y ˜ 1 ρ 1 H ˜ 1 ε θ 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ V ˜ 1 V d ϱ + ρ 1 H ˜ 1 V ˜ 1 + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 λ Y π I δ I Y + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ V t ϱ H V d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ S t ϱ H S d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ Y t ϱ H Y d ϱ + σ H ˜ 1 S ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) ln S t ϱ S d ϱ + ρ 1 H ˜ 1 ε F 3 Y ˜ 1 θ Y Y ˜ 1 + ρ 1 H ˜ 1 ε Y ˜ 1 θ 0 k 3 F ¯ 3 ( ϱ ) ln Y t ϱ Y d ϱ .
Using the following equilibrium conditions for Q ˜ 1
α = η H ˜ 1 + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 , ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 = σ + μ S ˜ 1 F 1 , σ S ˜ 1 = τ + γ I ˜ 1 F 2 Y ˜ 1 Y ˜ 1 = σ F 2 S ˜ 1 τ + γ I ˜ 1 , V ˜ 1 = ε F 3 Y ˜ 1 θ , λ Y ˜ 1 π I ˜ 1 δ I ˜ 1 Y ˜ 1 = 0 ,
We obtain
ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 = H ˜ 1 F 3 ρ 1 ε + ρ 3 θ Y ˜ 1 θ = σ F 2 H ˜ 1 F 3 ρ 1 ε + ρ 3 θ S ˜ 1 θ τ + γ I ˜ 1 , ρ 2 H ˜ 1 σ + μ F 1 + σ F 2 H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 S ˜ 1 = 0 .
Therefore, Equation (37) will take the following form:
d Θ ˜ 1 d t = 1 H ˜ 1 H η H ˜ 1 η H + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 1 H ˜ 1 H + ρ 3 H ˜ 1 Y 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S ˜ 1 S ρ 1 V t ϱ + ρ 2 S t ϱ + ρ 3 Y t ϱ d ϱ + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 σ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ S ˜ 1 θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) S t ϱ Y ˜ 1 S ˜ 1 Y d ϱ τ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 Y Y ˜ 1 γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 I Y Y ˜ 1 + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 I ˜ 1 Y Y ˜ 1 γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 I ˜ 1 Y Y ˜ 1 ρ 1 H ˜ 1 ε Y ˜ 1 θ 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ V ˜ 1 Y ˜ 1 V d ϱ + ρ 1 H ˜ 1 V ˜ 1 + γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 λ Y π I δ I Y λ Y ˜ 1 + π I ˜ 1 + δ I ˜ 1 Y ˜ 1 δ I ˜ 1 Y + δ I ˜ 1 Y + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ V t ϱ H V d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ S t ϱ H S d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ Y t ϱ H Y d ϱ + ρ 1 H ˜ 1 V ˜ 1 Y Y ˜ 1 + σ H ˜ 1 S ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ τ + γ I ˜ 1 0 k 2 F ¯ 2 ( ϱ ) ln S t ϱ S d ϱ + ρ 1 H ˜ 1 ε Y ˜ 1 θ 0 k 3 F ¯ 3 ( ϱ ) ln Y t ϱ Y d ϱ .
This implies that
d Θ ˜ 1 d t = η H H ˜ 1 2 H + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 2 H ˜ 1 H + ρ 3 H ˜ 1 Y ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S d ϱ ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S t ϱ H ˜ 1 S d ϱ ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S d ϱ ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ Y ˜ 1 S ˜ 1 Y d ϱ H ˜ 1 Y ˜ 1 F 3 ρ 1 ε + ρ 3 θ θ Y Y ˜ 1 1 ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ V ˜ 1 Y ˜ 1 V d ϱ + ρ 1 H ˜ 1 V ˜ 1 γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 2 + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ V t ϱ H V d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ S t ϱ H S d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ Y t ϱ H Y d ϱ + ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) ln S t ϱ S d ϱ + ρ 1 H ˜ 1 V ˜ 1 Y Y ˜ 1 + ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) ln Y t ϱ Y d ϱ = η H H ˜ 1 2 H + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 2 H ˜ 1 H γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 2 ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S d ϱ ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S t ϱ H ˜ 1 S d ϱ ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S d ϱ ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ Y ˜ 1 S ˜ 1 Y d ϱ + 2 ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ V ˜ 1 Y ˜ 1 V d ϱ + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ V t ϱ H V d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ S t ϱ H S d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ Y t ϱ H Y d ϱ + ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) ln S t ϱ S d ϱ + ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) ln Y t ϱ Y d ϱ .
Moreover, we have
ln H t ϱ V t ϱ H V = ln H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S + ln H ˜ 1 H + ln V ˜ 1 S V S ˜ 1 , ln H t ϱ Y t ϱ H Y = ln H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S + ln H ˜ 1 H + ln Y ˜ 1 S Y S ˜ 1 , ln H t ϱ S t ϱ H S = ln H t ϱ S t ϱ H ˜ 1 S + ln H ˜ 1 H , ln S t ϱ S = ln S t ϱ Y ˜ 1 S ˜ 1 Y + ln S ˜ 1 Y S Y ˜ 1 , ln Y t ϱ Y = ln Y t ϱ V ˜ 1 Y ˜ 1 V + ln Y ˜ 1 V Y V ˜ 1 .
Therefore, d Θ ˜ 1 d t will be
d Θ ˜ 1 d t = η H H ˜ 1 2 H + ρ 1 H ˜ 1 V ˜ 1 + ρ 2 H ˜ 1 S ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 2 H ˜ 1 H γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 2 ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S d ϱ ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ S t ϱ H ˜ 1 S d ϱ ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S d ϱ ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) S t ϱ Y ˜ 1 S ˜ 1 Y d ϱ + 2 ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) Y t ϱ V ˜ 1 Y ˜ 1 V d ϱ + ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S + ln H ˜ 1 H + ln V ˜ 1 S V S ˜ 1 d ϱ + ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ S t ϱ H ˜ 1 S + ln H ˜ 1 H d ϱ + ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) ln H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S + ln H ˜ 1 H + ln Y ˜ 1 S Y S ˜ 1 d ϱ + ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) ln S t ϱ Y ˜ 1 S ˜ 1 Y + ln S ˜ 1 Y S Y ˜ 1 d ϱ + ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) ln Y t ϱ V ˜ 1 Y ˜ 1 V + ln Y ˜ 1 V Y V ˜ 1 d ϱ .
Finally, we obtain
d Θ ˜ 1 d t = η H H ˜ 1 2 H ρ 1 H ˜ 1 V ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) F H t ϱ V t ϱ S ˜ 1 H ˜ 1 V ˜ 1 S + F H ˜ 1 H d ϱ ρ 2 H ˜ 1 S ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) F H t ϱ S t ϱ H ˜ 1 S + F H ˜ 1 H d ϱ ρ 3 H ˜ 1 Y ˜ 1 F 1 0 k 1 F ¯ 1 ( ϱ ) F H t ϱ Y t ϱ S ˜ 1 H ˜ 1 Y ˜ 1 S + F H ˜ 1 H d ϱ ρ 1 H ˜ 1 V ˜ 1 + ρ 3 H ˜ 1 Y ˜ 1 F 2 0 k 2 F ¯ 2 ( ϱ ) F S t ϱ Y ˜ 1 S ˜ 1 Y d ϱ ρ 1 H ˜ 1 V ˜ 1 F 3 0 k 3 F ¯ 3 ( ϱ ) F Y t ϱ V ˜ 1 Y ˜ 1 V d ϱ γ H ˜ 1 F 3 ρ 1 ε + ρ 3 θ π + δ Y θ τ + γ I ˜ 1 λ δ I ˜ 1 I I ˜ 1 2 .
Hence, if ˜ 0 > 1 then d Θ ˜ 1 d t 0 for all H , S , Y , V , I > 0 . In addition, d Θ ˜ 1 d t = 0 when H = H ˜ 1 , S = S ˜ 1 , Y = Y ˜ 1 , V = V ˜ 1 and I = I ˜ 1 . Let Φ ¯ 1 ˜ be the largest invariant subset of Φ ˜ 1 = H , S , Y , V , I : d Θ ˜ 1 d t = 0 . Therefore, Φ ¯ 1 ˜ = Q ˜ 1 . Applying L.I.P, we obtain Q ˜ 1 is G.A.S when ˜ 0 > 1 [52]. □

4. Numerical Simulations

In this section, we perform some numerical simulations for systems (8) and (23) to confirm our theoretical findings. Further, we will investigate the effects of the CTL immune impairment on model (8), in addition to the effect of time delays on the dynamics of model (23).

4.1. Numerical Simulation for Model (8)

4.1.1. Effect of ρ i ,   i = 1 , 2 , 3 and δ on Stability of Equilibria

Here, we solve system (8) numerically with values of the parameters listed in Table 1. To investigate the stability of equilibria for system (8), we choose three different initial conditions as follows:
IC1: ( H ( 0 ) , S ( 0 ) , Y ( 0 ) , V ( 0 ) , I ( 0 ) ) = ( 400 , 4 , 2 , 1 , 1 ) ,
IC2: ( H ( 0 ) , S ( 0 ) , Y ( 0 ) , V ( 0 ) , I ( 0 ) ) = ( 250 , 5 , 2.85 , 3.5 , 0.5 ) ,
IC3: ( H ( 0 ) , S ( 0 ) , Y ( 0 ) , V ( 0 ) , I ( 0 ) ) = ( 500 , 6.5 , 4 , 4 , 1.6 ) .
Since the basic reproduction number 0 is used to control the stability of equilibria, and it depends on the infection rates ρ i , i = 1 , 2 , 3 , we vary the parameters ρ i , i = 1 , 2 , 3 and present the following two situations:
Stability of  Q 0 . We let ρ 1 = 0.0002 ,   ρ 2 = 0.0001 ,   ρ 3 = 0.0004 and  δ = 0.001 . For this set of parameters, we have 0 = 0.6869 < 1 . Figure 1 illustrates that the solution trajectories initiating with IC1-IC3 reach the equilibrium Q 0 = ( 1000 , 0 , 0 , 0 , 0 ) . This ensures that Q 0 is G.A.S according to the result of Theorem 2. From a biological point of view, we know this case means that the disease will die out and the human body will be cleared of the infection.
Stability of  Q 1 . We let ρ 1 = 0.003 ,   ρ 2 = 0.0001 ,   ρ 3 = 0.0004 and  δ = 0.001 . With such choice we obtain 0 = 2.7365 > 1 . It is clear that the equilibrium point Q 1 exists when 0 > 1 with Q 1 = ( 373.74 , 16.93 , 4.13 , 4.47 , 0.51 ) . Figure 2 shows that the numerical results confirm the theoretical results of Theorem 3 as the solutions of system (8) converge to Q 1 when 0 > 1 for all IC1–IC3. Biologically, this case sheds light on the fact that the HIV-1 particles and CTL cells will persist in the host.

4.1.2. Effect of the CTL Immune Impairment

In this case, we vary the parameter δ and choose ρ 1 = 0.003 ,   ρ 2 = 0.0001 and ρ 3 = 0.0004 . To investigate the immune impairment effects on the dynamics of system (8) we solve the system numerically taking under consideration different values of δ as shown in Table 2. In this case, we select the following initial condition:
IC4: ( H ( 0 ) , S ( 0 ) , Y ( 0 ) , V ( 0 ) , I ( 0 ) ) = ( 370 , 17 , 4 , 4.5 , 0.3 ) .
Table 2 shows that as δ is increased, the concentration of CTLs is decreased. Consequently, the concentration of latently and actively infected cells and free HIV-1 particles are increased. In the mean time, the concentration of healthy CD 4 + T cells is decreased. We observe from Figure 3, that the CTL immune impairment does not change the stability properties of the equilibria, since the parameter 0 does not depend on δ .

4.2. Numerical Simulation for Model (23)

In this subsection, for numerical purposes, we take a specific form of the probability distributed functions f i ( ϱ ) ,   i = 1 , 2 , 3 , as follows:
f i ( ϱ ) = δ * ϱ ϱ i , ϱ i 0 , k i , i = 1 , 2 , 3 ,
where δ * ( . ) is the Dirac delta function. When k i , we have
0 f i ϱ d ϱ = 1 , i = 1 , 2 , 3 .
Further, we have
F i = 0 δ * ϱ ϱ i e h i ϱ d ϱ = e h i ϱ i , i = 1 , 2 , 3 .
Hence, the distributed time delay system (23) will be transformed to a discrete time delay system as:
H ˙ ( t ) = α η H t ρ 1 H t V t ρ 2 H t S t ρ 3 H t Y t , S ˙ ( t ) = e h 1 ϱ 1 H t ϱ 1 ρ 1 V t ϱ 1 + ρ 2 S t ϱ 1 + ρ 3 Y t ϱ 1 σ + μ S t , Y ˙ ( t ) = σ e h 2 ϱ 2 S t ϱ 2 τ Y t γ I t Y t , V ˙ ( t ) = ε e h 3 ϱ 3 Y t ϱ 3 θ V t , I ˙ ( t ) = λ Y t π I t δ I t Y t .
For system (38), the basic reproduction number is given as:
˜ 0 ( 38 ) = H ˜ 0 e h 1 ϱ 1 σ e h 2 ϱ 2 ρ 1 ε e h 3 ϱ 3 + ρ 3 θ + ρ 2 θ τ σ + μ θ τ .
The effect of time delays on stability of equilibria
To investigate the impact of delay parameters on the solutions of system (38), we fix the parameters ρ 1 = 0.003 ,   ρ 2 = 0.0001 ,   ρ 3 = 0.0004 ,   δ = 0.001 ,   h 1 = 0.1 ,   h 2 = 0.2 and h 3 = 0.3 . On the other hand, the other parameters will be taken from Table 1. Moreover, we vary the delay parameters ϱ i ,   i = 1 , 2 , 3 . Since ˜ 0 ( 38 ) given in Equation (39) depends on ϱ i , then changing the parameters ϱ i will change the stability of equilibria. Let us take the following cases of the delay values:
Case: 1  ϱ 1 = 0.07 , ϱ 2 = 0.06 , ϱ 3 = 0.05 .
Case: 2  ϱ 1 = 0.8 , ϱ 2 = 0.7 , ϱ 3 = 0.9 .
Case: 3  ϱ 1 = 1.3 , ϱ 2 = 1.4 , ϱ 3 = 1.5 .
Case: 4  ϱ 1 = 1.8 , ϱ 2 = 1.9 , ϱ 3 = 2 .
Case: 5  ϱ 1 = 4 , ϱ 2 = 3 , ϱ 3 = 5 .
We solve system (38) under initial condition IC5
IC5: ( H ( r ) , S ( r ) , Y ( r ) , V ( r ) , L ( r ) ) = ( 400 , 4 , 2 , 1 , 1 ) , r [ ϱ , 0 ] , ϱ = max { ϱ 1 , ϱ 2 , ϱ 3 } . In Table 3, we demonstrate the values of ˜ 0 ( 38 ) for different values of ϱ i ,   i = 1 , 2 , 3 . We observe that as the parameters ϱ i are increased, the values of ˜ 0 ( 38 ) are decreased. The numerical solutions are displayed in Figure 4. We conclude that a significant effect is caused by the inclusion of time delays which causes increasing in the concentration of healthy CD 4 + T cells and decreasing in the concentrations of latently and actively infected cells, HIV-1 particles and CTL cells.

5. Conclusions and Discussion

In this paper, we introduced two HIV-1 dynamic models with CTL immune impairment. The models consist of five compartments: healthy CD 4 + T cells, latently and actively infected cells, free HIV-1 particles and CTLs. We considered that the healthy CD 4 + T cells become infected by coming into contact with free HIV-1 particles, latently infected cells and actively infected cells. In the second model, we took into account three distributed time delays to be more realistic. We showed that the solutions of the models are nonnegative and bounded. We concluded that each model has two equilibria, the infection-free equilibrium, and the infected equilibrium. We found the basic reproduction number 0 (or ˜ 0 ) that controls the existence and global stability of the two equilibria. Number 0 (or ˜ 0 ) consists of three parts: the first is the contribution from the VTC infection, the second part is the contribution from the latent CTC spread, and the third part is the contribution from the active CTC spread. For both models, we formulated Lyapunov functions and applied L.I.P to establish the global asymptotic stability of the two equilibria. We proved that if the basic reproduction number 0 < 1 (or ˜ 0 < 1 ), then the infection-free equilibrium Q 0 (or Q ˜ 0 ) is G.A.S, and thus the infection dies out. Moreover, if 0 > 1 (or ˜ 0 > 1 ), then Q 0 (or Q ˜ 0 ) is unstable and the infected equilibrium Q 1 (or Q ˜ 1 ) is G.A.S, and thus the infection becomes chronic. Finally, we performed some numerical simulations to illustrate our theoretical results. We showed that the numerical results are consistent with theoretical results
We discussed the effect of immune impairment and time delay on the HIV-1 dynamics. We found that weak immunity contributes significantly to the development of the disease. Moreover, the presence of time delay can significantly decrease the basic reproduction number ˜ 0 and then suppress the HIV-1 replication. Therefore, to eliminate HIV-1 from the body, one should focus on designing control strategies which make ˜ 0 < 1 . Increasing delay parameters ϱ i , i = 1 , 2 , 3 may be observed when infected patients are treated with drug therapies against HIV-1.
We note that, when we ignore the latent CTC spread then model (8) leads to model (3)–(7). The basic reproduction number of system (3)–(7) is given by:
^ 0 = H 0 ε σ ρ 1 θ τ σ + μ + H 0 σ ρ 3 τ σ + μ .
Clearly, ^ 0 < 0 , and thus the presence of latent CTC transmission increases the basic reproduction number and then enhances the viral progression. Neglecting the latent CTC spread in the HIV-1 infection model will lead to underestimation of the basic reproduction number. Consequently, the designed drug therapies will not be accurate or sufficient to eradicate the viruses from the body.
Model (8) can be extended by including the diffusion of the cells and viruses as per Refs. [56,57]:
H ( t , p ) t ξ H Δ H t , p = α η H t , p ρ 1 H t , p V t , p ρ 2 H t , p S t , p ρ 3 H t , p Y t , p , S t , p t ξ S Δ S t , p = 0 k 1 f 1 ϱ e h 1 ϱ H t ϱ , p ρ 1 V t ϱ , p + ρ 2 S t ϱ , p + ρ 3 Y t ϱ , p d ϱ ( σ + μ ) S t , p , Y t , p t ξ Y Δ Y t , p = σ 0 k 2 f 2 ϱ e h 2 ϱ S t ϱ , p d ϱ τ Y t , p γ I t , p Y t , p , V t , p t ξ V Δ V t , p = ε 0 k 3 f 3 ϱ e h 3 ϱ Y t ϱ , p d ϱ θ V t , p , I t , p t ξ I Δ I t , p = λ Y t , p π I t , p δ I t , p Y t , p ,
where p is the position, ξ w is the diffusion coefficient of compartment w and Δ = 2 p 2 . Some other types of diffusion can also be included in our models (see e.g., [58,59,60]). We leave these points for future work.

Author Contributions

Conceptualization, N.H.A. and A.M.E.; Methodology, N.H.A.; Software, N.H.A., R.H.H. and A.M.E.; Validation, N.H.A. and A.M.E.; Formal analysis, N.H.A. and R.H.H.; Investigation, N.H.A.; Resources, N.H.A. and A.M.E.; Writing—original draft, N.H.A., R.H.H. and A.M.E.; Writing–review & editing, Wafa Shammakh; Visualization, N.H.A. and A.M.E.; Supervision, N.H.A. and A.M.E. All authors have read and agreed to the published version of the manuscript.

Funding

This work was funded by the University of Jeddah, Jeddah, Saudi Arabia, under grant No. (UJ-22-DR-102).

Data Availability Statement

Not applicable.

Acknowledgments

This work was funded by the University of Jeddah, Jeddah, Saudi Arabia, under grant No. (UJ-22-DR-102). The authors, therefore, acknowledge with thanks the University of Jeddah for its technical and financial support.

Conflicts of Interest

The authors declare that they have no conflict of interest regarding the publication of this paper.

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Figure 1. Solutions of system (8) when 0 < 1 .
Figure 1. Solutions of system (8) when 0 < 1 .
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Figure 2. Solutions of system (8) when 0 > 1 .
Figure 2. Solutions of system (8) when 0 > 1 .
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Figure 3. Solutions of system (8) with different values of the impairment parameter δ .
Figure 3. Solutions of system (8) with different values of the impairment parameter δ .
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Figure 4. Effect of the delay parameters on the solutions of system (38).
Figure 4. Effect of the delay parameters on the solutions of system (38).
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Table 1. Model parameters.
Table 1. Model parameters.
ParameterValueReferenceParameterValueReference
α 10[54] τ 0.8[32]
η 0.01[54] γ 0.04[32]
ρ 1 varied- ε 2.6[55]
ρ 2 varied- θ 2.4[55]
ρ 3 varied- λ 0.025[32]
σ 0.2[54] π 0.2[32]
μ 0.17[54] δ varied-
Table 2. Effect of the CTL immune impairment parameter.
Table 2. Effect of the CTL immune impairment parameter.
δ Equilibria
δ = 0 Q 1 = 373.8995 , 16.9216 , 4.1241 , 4.4678 , 0.5155
δ = 0.05 Q 1 = 369.6465 , 17.0366 , 4.2053 , 4.5557 , 0.2563
δ = 0.1 Q 1 = 368.2255 , 17.0750 , 4.2328 , 4.5855 , 0.1698
δ = 0.9 Q 1 = 365.8669 , 17.1387 , 4.2790 , 4.6356 , 0.0264
Table 3. The disparity of ˜ 0 ( 38 ) with respect to the delay parameters.
Table 3. The disparity of ˜ 0 ( 38 ) with respect to the delay parameters.
Delay Parameters ( ϱ 1 , ϱ 2 , ϱ 3 ) Equilibria ˜ 0 ( 38 )
( 0.07 , 0.06 , 0.05 ) Q ˜ 1 ( 38 ) = ( 384.729 , 16.513 , 3.982 , 4.249 , 0.488 ) 2.656
( 0.8 , 0.7 , 0.9 ) Q ˜ 1 ( 38 ) = ( 558.891 , 11.005 , 2.358 , 1.95 , 0.291 ) 1.812
( 1.3 , 1.4 , 1.5 ) Q ˜ 1 ( 38 ) = ( 747.257 , 5.998 , 1.125 , 0.777 , 0.14 ) 1.346
( 1.8 , 1.9 , 2 ) Q ˜ 1 ( 38 ) = ( 936.985 , 1.423 , 0.243 , 0.144 , 0.03 ) 1.069
( 4 , 3 , 5 ) Q ˜ 0 ( 38 ) = ( 1000 , 0 , 0 , 0 , 0 ) 0.461
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AlShamrani, N.H.; Halawani, R.H.; Shammakh, W.; Elaiw, A.M. Global Properties of HIV-1 Dynamics Models with CTL Immune Impairment and Latent Cell-to-Cell Spread. Mathematics 2023, 11, 3743. https://doi.org/10.3390/math11173743

AMA Style

AlShamrani NH, Halawani RH, Shammakh W, Elaiw AM. Global Properties of HIV-1 Dynamics Models with CTL Immune Impairment and Latent Cell-to-Cell Spread. Mathematics. 2023; 11(17):3743. https://doi.org/10.3390/math11173743

Chicago/Turabian Style

AlShamrani, Noura H., Reham H. Halawani, Wafa Shammakh, and Ahmed M. Elaiw. 2023. "Global Properties of HIV-1 Dynamics Models with CTL Immune Impairment and Latent Cell-to-Cell Spread" Mathematics 11, no. 17: 3743. https://doi.org/10.3390/math11173743

APA Style

AlShamrani, N. H., Halawani, R. H., Shammakh, W., & Elaiw, A. M. (2023). Global Properties of HIV-1 Dynamics Models with CTL Immune Impairment and Latent Cell-to-Cell Spread. Mathematics, 11(17), 3743. https://doi.org/10.3390/math11173743

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