1. Introduction
Let H be an infinite-dimensional separable complex Hilbert space, the algebra of all bounded linear operators on H, and the closed ideal of all compact operators. For an operator , we write for the conjugate operator of T, for its kernel, and for its range. The dimension, codimension, and index of T are denoted by , and , respectively.
An operator is called upper semi-Fredholm if is closed and is finite- dimensional. If is closed and finite-codimensional, is called a lower semi-Fredholm operator. We call Fredholm if is closed and finite-codimensional and is finite-dimensional. For a semi-Fredholm operator (upper semi-Fredholm operator or lower semi-Fredholm operator), let and . The index of a semi-Fredholm operator is given by . The operator T is Weyl if it is Fredholm of index zero. is called left (right) semi-Weyl if T is upper (lower) semi-Fredholm with (). Let denote the set of all left semi-Weyl operators. For an operator , the spectrum , the essential spectrum , the Weyl spectrum , and the essential approximate point spectrum of T are defined by , , , and , respectively.
Let be the set of all Fredholm operators. We denote the Calkin algebra by . Let be the quotient map. It is well known that if and only if is invertible in .
A bijective linear map
is called a Jordan isomorphism if
for every
or, equivalently,
for all
A and
B in
. It is obvious that every isomorphism and every anti-isomorphism is a Jordan isomorphism. For further properties of Jordan homomorphisms, we refer the reader to [
1,
2].
In the last two decades, there has been considerable interest in the so-called linear preserver problems (see the survey articles [
3,
4,
5]). The goal of studying linear preservers is to give structural characterizations of linear maps on algebras having some special properties such as leaving invariant a certain subset of the algebra or leaving invariant a certain function on the algebra. One of the most-famous problems in this direction is Kaplansky’s problem ([
6]): Let
be a surjective linear map between two semi-simple Banach algebras
and
. Suppose that
for all
. Is it true that
is a Jordan isomorphism? This problem was first solved in the finite-dimensional case. Dieudonné ([
7]) and Marcus and Purves ([
8]) proved that every unital invertibility preserving linear map on a complex matrix algebra is either an inner automorphism or a linear anti-automorphism. This result was later extended to the algebra of all bounded linear operators on a Banach space by Sourour ([
9]) and to von Neumann algebra by Aupetit ([
10]). Many linear preserver problems have been of interest for infinite-dimensional cases. For the most-significant partial results relevant to our discussions, we refer the reader to [
9,
10,
11]. New contributions to the study of the linear preserver problem have been recently made by Mbekhta in [
12], Alizadeh and Shakeri in [
13], Bueno, Furtado, and Sivakumar in [
14], Buenoa, Furtadob, Klausmeierc, and Veltrid in [
15], and Bendaoud, Bourhim and Sarih in [
16].
In this article, we studied linear maps preserving left (right) semi-Weyl operators in both directions. We characterized the linear maps , which are surjective up to compact operators preserving the set of semi-Weyl operators in both directions. As an application, we proved that preserves the essential approximate point spectrum if and only if the ideal of all compact operators is invariant under , the induced map on the Calkin algebra is an automorphism, and if both and T are Fredholm.
2. Linear Maps Preserving the Set of Left (Right) Semi-Weyl Fredholm Operators
We say that a linear map preserves property X in both directions, which means that if T is in the domain, then T has property X if and only if has property X. Therefore, a linear map preserves the set of left semi-Weyl operators in both directions if .
A linear map is said to be surjective up to compact operators if, for every , there exists such that . It is clear that if is surjective, then it is surjective up to compact operators.
In order to prove the theorem and the corollaries, we need some known results.
Lemma 1 (Theorem 4.2 in [
5]).
Let H be an infinite-dimensional separable Hilbert space and be a linear map surjective up to compact operators. Then, the following are equivalent:- (1)
ϕ preserves upper semi-Fredholm operators in both directions;
- (2)
ϕ preserves lower semi-Fredholm operators in both directions;
- (3)
, and the induced map is an automorphism multiplied by an invertible element .
Lemma 2 (Theorem 2.1 in [
12]).
Let H be an infinite-dimensional separable Hilbert space and be a linear map surjective up to compact operators. Then, the following are equivalent:- (1)
ϕ preserves the set of Fredholm operators in both directions;
- (2)
, and the induced map is the composition of either an automorphism or an anti-automorphism and left multiplication by an invertible element in .
Lemma 3 (Theorem 4.8 in [
3]).
Let A be a factor, and let B be a primitive Banach algebra. For a surjective up to inessential elements linear map , the following are equivalent:- (1)
ϕ preserves Fredholm elements in both directions and is the Weyl element of B;
- (2)
ϕ preserves Weyl elements in both directions;
- (3)
Let and be the ideal of the inessential elements of A and B. Then, , and the induced map is either an isomorphism or an anti-isomorphism multiplied by an invertible element .
Lemma 4 (Theorem 3.1 in [
4]).
Let A be a unital C*-algebra of real rank zero and B a unital semi-simple complex Banach algebra. Let denote any one of the spectral functions , and . Suppose is a surjective linear map. If for every , then ϕ is a Jordan homomorphism. Furthermore, if B is prime, then ϕ is either a homomorphism or an anti-homomorphism. Theorem 1. Let H be an infinite-dimensional Hilbert space, and let be a linear map preserving left (or right) semi-Weyl operators in both directions. Assume that ϕ is surjective up to compact operators and is Weyl, then , and the induced map is an automorphism multiplied by an invertible element .
Proof. Suppose that is a linear map preserving left semi-Weyl operators in both directions. Let , where is invertible and . There exists such that .
The linear map
is defined by:
Then,
preserves the left semi-Weyl operators in both directions and
, where
. Let us give some properties for the linear map
: (i)
is surjective up to compact operators.
In fact, for any , there exists and such that . Then, , where .
(ii) For any , .
Since ⇔⇔, it follows that for any .
(iii) preserves compact operators in both directions.
First, we claim that
From the stability properties of the index function, it is clear that
Let
and
denote the boundary and the polynomial convex hull of a compact subset
E of ℂ, respectively. For any
, since
it follows that
.
Now, let such that for all . Then, for all . Taking into account the semisimplicity of and the spectral characterization of the radical, it is not difficult to prove that
Let , for any ; since preserves left semi-Weyl operators in both directions, there exists and for which . Hence, . Then, . For the converse, let , for any , , then . It follows that . Now, we prove that preserves compact operators in both directions.
(iv) , and consequently, .
If and , then . Thus, for all , . From the proof of (iii), we know that .
(v) Let be an induced linear map such that , then is an isomorphism or an anti-isomorphism.
From the fact that is invariant under , then induces a linear map such that . Clearly, is surjective, since is surjective up to compact operators. We prove now that is injective. Since and , we can obtain that is injective.
From (ii), we know that, for any , . Then, from (iii), . This shows that is an -preserving map. Thus, the induced mapping is an -preserving map. By Lemma 4, is either an isomorphism or an anti-isomorphism.
(vi) is an isomorphism.
First, we will prove that preserves upper semi-Fredholm operators in both directions. By Lemma 2, we know that preserves Fredholm operators in both directions. Let be an upper semi-Fredholm; there are two cases to consider: and . If , using the fact that is a linear map preserving left semi-Weyl operators in both directions, we know that is upper semi-Fredholm. If , then T is Fredholm; thus, is Fredholm since preserves Fredholm operators in both directions. Using the same way, we can prove that T is upper semi-Fredholm if is upper semi-Fredholm. By Lemma 1, is an isomorphism.
From the definition of , we know that preserves compact operators in both directions, and hence, is invariant under . Let induce a linear map such that . Then, .
Similar to the above proof, the result is true if is a linear map preserving right semi-Weyl operators in both directions. The proof is completed. □
Under the same hypothesis and notation as in Theorem 1, we obtain that
preserves the essential spectrum ([
12], Theorem 3.2). Then,
or
for any
. Since
preserves left semi-Weyl operators in both directions, it follows that
for any
. Thus,
for any
. Furthermore, we can prove that
for any upper (lower) semi-Fredholm operator
. By Lemma 1, Lemma 2, and Lemma 3, we can obtain:
Corollary 1. Let be a linear map preserving left (right) semi-Weyl operators in both directions. Assume that ϕ is surjective up to compact operators and is Weyl, then:
- (1)
ϕ preserves Fredholm operators in both directions;
- (2)
ϕ preserves Weyl operators in both directions;
- (3)
ϕ preserves upper semi-Fredholm operators in both directions;
- (4)
ϕ preserves lower semi-Fredholm operators in both directions;
- (5)
ϕ preserves semi-Fredholm operators in both directions;
- (6)
For any , ;
- (7)
For any upper (lower) semi-Fredholm operator T, .
Remark 1. If is a linear map preserving Fredholm operators (or upper semi-Fredholm operators, or lower semi-Fredholm operators, or semi-Fredholm operators) in both directions, we cannot induce that ϕ is a linear map preserving left semi-Weyl operators in both directions. For example, let be defined by:then there exists such that . Define as , . We can see that ϕ is surjective and preserves Fredholm operators (upper semi-Fredholm operators, lower semi-Fredholm operators, semi-Fredholm operators) in both directions, but ϕ is not a linear map preserving left semi-Weyl operators in both directions. From Remark 1, we have the question: If is a linear map preserving Fredholm operators (or upper semi-Fredholm operators, or lower semi-Fredholm operators, or semi-Fredholm operators) in both directions, when does ϕ preserve left semi-Weyl operators in both directions. To answer this question, let us begin by a Lemma (Lemma 2.4 in [5]). Lemma 5. Let be a lower (respectively upper) semi-Fredholm. If A is not Fredholm, then there exists a lower (respectively upper) semi-Fredholm operator B such that every non-trivial linear combination , or , is lower (respectively upper) semi-Fredholm, but not Fredholm.
Corollary 2. Let be a linear map preserving left (right) semi-Weyl operators in both directions. Assume that ϕ is surjective up to compact operators, then is a Fredholm operator.
Proof. Denote . We will prove that T is Fredholm. On the contrary, we assumed that this is not the case. Since I is a left semi-Weyl operator, T must be a left semi-Weyl operator. Then, by Lemma 5, there exists such that is upper semi-Fredholm, but not Fredholm, which means that is left semi-Weyl. We can further find such that for some . Any compact perturbation of a left semi-Weyl operator is a left semi-Weyl operator; thus, is left semi-Weyl for every . As is a linear map preserving left semi-Weyl operators in both directions, we obtain that , a contradiction. □
Corollary 3. Let linear map be surjective up to compact operators, then the following statements are equivalent:
- (1)
ϕ preserves left semi-Weyl operators in both directions, and is Weyl;
- (2)
ϕ preserves left semi-Weyl operators in both directions, and if both and T are Fredholm;
- (3)
ϕ preserves right semi-Weyl operators in both directions, and if both and T are Fredholm;
- (4)
ϕ preserves Fredholm operators in both directions, and if both and T are semi-Fredholm;
- (5)
ϕ preserves upper semi-Fredholm operators in both directions, and if both and T are upper semi-Fredholm;
- (6)
; the induced map is an automorphism multiplied by an invertible element , and if both and T are Fredholm.
Proof. By the proof of Theorem 1 and Corollary 1, we only need to prove that . By Lemma 1, we know that preserves upper semi-Fredholm operators and Fredholm operators in both directions. Let , then is upper semi-Fredholm. If , then because preserves Fredholm operators in both directions, thus . If , then is Fredholm, and hence, , again . Using the same way, we can prove that if . This proves that preserves left semi-Weyl operators in both directions. Thus, is Fredholm. Since both and I are Fredholm, it follows that . Then, is Weyl. □
Let
be surjective up to compact operators. If
preserves left semi-Weyl operators in both directions and
is Weyl, we cannot induce that
is
-preserving. For example, let
be defined by:
and define
and
. Let
be a linear map, and consider the linear map
defined by
. Then,
is surjective up to compact operators and preserves the set of left semi-Weyl operators in both directions; also,
is Weyl. According to the calculation, we obtain that
, while
. This says that
is not
-preserving. There is a question: When does a map satisfying the hypothesis of Theorem 1 preserve the essential approximate point spectrum?
Corollary 4. Let H be an infinite-dimensional Hilbert space, and let be a linear map. Assume that ϕ is surjective up to compact operators, then the following statements are equivalent:
- (1)
ϕ preserves left semi-Weyl operators in both directions and ;
- (2)
ϕ preserves right semi-Weyl operators in both directions and ;
- (3)
ϕ is -preserving, i.e., for all ;
- (4)
; the induced map is an automorphism, and if both and T are Fredholm.
Proof. In view of the preceding theorem and corollaries, we only need to prove the equivalence of (1) and (3). Suppose that
preserves the left semi-Weyl operators in both directions and
. Let
,
. Since
⇔
⇔
, it follows that
for any
. For the converse, suppose that
for all
, then
preserves the left semi-Weyl operators in both directions. We need to prove that
. Put
. Let
,
, and
for which
(
is surjective up to compact operators). Then,
and
This gives
for all
. It follows from the proof of Theorem 1 that
is compact. □
Let be left semi-Weyl or right semi-Weyl}. Define the semi-Weyl spectrum of an operator as . Similar to the proof of Theorem 1, we have that We can prove the following:
Corollary 5. Let H be an infinite-dimensional Hilbert space, and let be a linear map. Assume that ϕ is surjective up to compact operators, then the following statements are equivalent:
- (1)
ϕ preserves semi-Weyl operators in both directions, and ;
- (2)
ϕ is -preserving, i.e., for all ;
- (3)
ϕ preserves semi-Fredholm operators in both directions, and ;
- (4)
; the induced map is an automorphism or an anti-isomorphism.
We conclude this paper by a natural conjecture that we have been unable to answer:
Conjecture 1.
Let H be an infinite-dimensional Hilbert space, and let be a linear map. Assume that is surjective up to compact operators, then the following statements are equivalent:
- (1)
preserves the essential approximate point spectrum;
- (2)
There exists an automorphism and there exists a linear map such that for every ;
- (3)
for every , where A is an invertible operator in and is a linear map.