1. Introduction
In 1946, Davenport and Heilbronn [
1] made a significant contribution by adapting the Hardy-Littlewood method. Their work provided valuable insight and helped to prove that if
are nonzero real numbers, not all of the same sign, and not all in a rational ratio, then for every
the inequality
has infinitely many solutions in natural numbers
provided that
. Later, Davenport and Roth [
2] proved that if
, then
suffices with a suitable absolute constant
C. More recently, Schwarz [
3] demonstrated that if either
or
(for
), then the inequality
has infinitely many solutions, with all
being prime numbers.
In 1967, for the specific case
and
, Baker [
4] advanced the field by demonstrating that when
there are infinitely many ordered triples of primes
such that
with
,
. From now on, we will assume that the conditions in Equations (
1)–(
4) are met. The Baker’s approach laid the groundwork for further exploration in this area. Subsequently, the upper bound of the right-hand side of Equation (
5) was sharpened by [
5,
6,
7,
8,
9,
10]
and here
.
The best result to date belongs to K. Matomäki, but Baker and Harman [
8] proved that under the generalized Riemann hypothesis, it is possible to reach
.
Recent research has concentrated mainly on cases involving a limited number of summands.
In 2012 Li Wei-ping, Wang Tian-ze [
11] proved the existence of infinitely many triples of primes such that
where
and
. Later, Langusco and Zaccagnini [
12] proved Equation (
6) with
and
. They notice that the same arguments give Equation (
6) with
and
. In [
13], Gambini, Languasco and Zaccagnini proved that Equation (
6) is fulfilled with
and
A similar problem observed by Languasco and Zaccagnini [
14] is the existence of infinitely many solutions in primes of the diophantine inequality
with
. Later, Fu Linzhu, Liqun Hu, and Xuan Long [
15] extended their result to
.
Another type of Diophantine inequality is those with more summands and again with mixed powers. We mention some of them.
Wang and Yao [
16] considered the inequality
and proved that it has infinitely many solutions in prime variables
. Under conditions
, and if both
and
are algebraic, the author proved that the exponent can be replaced by
. For the inequality
with
, Zhu [
17] proved that it has infinitely many solutions in the prime variables
with
. Later, Mu [
18] improved recent results by proving the solvability of this inequality with
for
and
for
.
Alongside Diophantine inequalities involving mixed powers, inequalities that impose additional restrictions on the participating prime numbers are also of interest.
In 1991 Tolev [
19] solved the diophantine inequality in Equation (
5) in primes
near to squares. More precisely he proved the existance of infinitely many triples
satisfying (
5) with
and such that
(as usual,
denotes the distance from
to the nearest integer). Later Dimitrov [
20] proved (
5) with
with Piatetski-Shapiro primes
,
,
.
Another famous and still unsolved problem is the existence of infinitely many primes
p such that
is also prime. Let
be an integer with no more than
r prime factors, counted with their multiplicities. In 1973, Chen [
21] showed that there are infinitely many primes
p with
.
In 2015, Dimitrov and Todorova [
22] mixed Vaughan and Chen problems, and for
and
they proved (
5) with
,
,
. Dimitrov [
23] improved this result with
and
,
,
. Later, the author [
24] proved the existence of infinitely many triples of primes satisfying Equation (
5) with
,
,
, and
. We refer to a hybrid theorem demonstrated by Dimitrov in [
25], which establishes the inequality in Equation (
5) that involves the primes
, where
is of the form
.
In the present paper, we will study the Diophantine inequality with mixed powers of primes, such that , , are almost primes. More precisely, we prove the following theorem:
Theorem 1.
If the conditions in Equations (1)–(4) are fulfilled and , then there are infinitely many ordered triples of primes withand 2. Notations
By , we always denote primes. As usual, and denote, respectively, Euler’s function and Möbius’ function. Let and be the largest common divisor and the least common multiple of . Instead of , for simplicity, we write . As usual, denotes the integer part of y, .
Let
be Dirichlet us character and let
be the corresponding
L function. We will use the notation.
where
is the Riemann zeta function.
For
and
we denote
where ∗ means that the sum is taken over primitive characters modulo
d. Also by
we denote Chebyshev’s functions,
and for a given character
, we write
We will write when . The letter denotes an arbitrarily small positive number, not the same in all appearances. For example, this convention enables us to write .
3. Auxiliary Results
In the proof of our Theorem, we will use a vector sieve, and we will need the following Lemma:
Lemma 1.
Suppose that . There exists an arithmetical functions (called Rosser’s functions of level ) with the following properties:
- 1.
For any positive integer d, we have - 2.
- 3.
If is such that and if where and satisfy Here, γ is Euler’s constant .
Proof. See Greaves (Chapter 4, [
26]) and [
27]. □
From Merten’s formula, we observe that it follows:
where
is the twin prime constant. From the properties of the functions of the linear sieve in Equations (
16) and (
17), it follows that
We will utilize Bombieri-Vinogradov’s theorem.
Lemma 2. (Bombieri–Vinogradov) For any the following inequalityis fulfilled. In the following Lemma, we provide explicit formulas for Chebyshev’s function and for the function .
Lemma 3.
Let . Thenwhere summation is taken over the non-trivial zeros of the Riemann zeta function such that . If and χ is a primitive character modulo q thenwhere summation is taken over the non-trivial zeros of the Dirichlet us L-function such that and , respectively. Proof. See [
28] §17 and [
28] §19. □
We need the following two Lemmas regarding the zeros of the Dirichlet L-functions and the Riemann zeta function.
Lemma 4.
For any there is a positive number such that if χ is a quadratic character modulo q and σ is a real zero of , then Proof. See Corollary 11.15 of §11, [
29]. □
Lemma 5.
For the Riemann ζ function has no zeros in the region The next three Lemmas provide information about the density of the zeros of Dirichlet us L-functions and of Riemann’s -function.
Lemma 6.
Let χ be a primitive character modulo q and . Then Lemma 7.
Let and function be defined with (13). Then Proof. See Theorem 12.2, §12, [
31,
32]. □
Lemma 8.
Let and function be defined by Equation (12). Then Proof. See ch. 11 [
33] and Theorem 1.1 [
34]. □
Lemma 9.
Suppose and α satisfy conditionsLet be complex numbers defined for , , and . Ifthen for any arbitrary small we have Proof. This is Lemma 1 from [
35]. □
4. Beginning of the Proof
Let
,
be positive real numbers that we will specify later, but for now we will only assume the conditions.
Consider the sum
with
given by Equation (
26). If we can establish the inequality
, then the inequality in Equation (
8) would have a solution in the primes
that satisfies the conditions
for
and
. If the number
has multiplicity-counted prime factors represented by
, then from Equations (
27) and (
30), we can conclude that
for
, and
. This implies that
and
are almost primes of order
, while
is an almost prime of order
.
To transform the sum
we take a function
such that
The function
has derivatives of sufficiently large order, and its Fourier transform
satisfy
for all
. For the existence of such a function, see [
36].
Using the function
, we get
Our goal is to demonstrate that for specific values of
and
(as large as possible), there exists a sequence
such that
. Then the number of prime solutions
of Equation (
8) in the interval
with
for
and
is positive. This approach allows us to generate an infinite sequence of triples of primes
that satisfy the desired properties.
Let
and
be the characteristic functions of primes
, such that
for
and
, respectively. Then from Equation (
34) follows that
Let
and
represent the lower and upper bounds of Rosser’s weights at levels
D and
, respectively (see Lemma 1). If
then, from Lemma 1 we have
,
.
We will utilize the following simple inequality.
analogous to the inequality in (Lemma 13, [
37]). Using Equations (
35) and (
37) we get
Substituting the function
from Equation (
38) with its inverse Fourier transform in Equation (
32), we get
Thus,
where
are the contributions of the consecutive terms on the right side of Equation (
39). It is clear that
Therefore,
We are going to estimate
. The integrals
and
can be treated similarly. Changing the order of summation and bearing in mind Equation (
36), we obtain
where
and
We note that
are real numbers such that
. Furthermore,
if
or
. Without utilizing the arithmetic structure of the Rosser weights, we will write them as
. In these cases, instead of
and
, we will simply write
and
.
Using the Davenport–Heilbronn adaptation of the circle method (see (Ch. 11, [
38])), we divide
into three separate integrals:
where
Here, the functions
and
are defined using the expression in Equations (
24) and (
26). From Lemma 2 [
22] we have that
and it is easy to see from Equation (
41) that
We will estimate
and
in
Section 4 and
Section 5, respectively. The estimation of the sums
is carried out in the same way. In
Section 6, we will finalize the proof of the theorem.
5. Asymptotic Formula for
To evaluate the sum , we need asymptotic formulas for and when . Since we will not be using the arithmetic properties of the Rosser weights, we will simply denote them by and .
In addition, we require the following two estimates.
Lemma 10.
Let , , for arbitrarily large fixed positive real number A,and the summation in the inner sum is taken over the non-trivial zeros of Dirichlet us L-function such that . Ifthen Proof. Using Lemmas 6 and 7 and following the same steps as in the proof of Lemma 9 from [
39] we get our statement. □
Lemma 11.
Using notations of Lemma 10 when and for arbitrarily large fixed positive real number A and every large enough real Y, the following inequalityis fulfilled. Proof. Using Lemmas 6 and 7 and following the proof of Lemma 9 from [
39] we get
where
Using the same reasoning as in the estimation of integral
from (Lemma 9, [
39]), we obtain the following
To estimate the integral
, we note from Lemma 4 that the Dirichlet function
does not have zeros in the region.
Choosing
, we find that
when
. So using Lemma 7 and working as in the estimate of integral
we get
As
when
we obtain
with
. Therefore, for sufficiently large
YFrom Equations (
54)–(
57) follows the statement of Lemma 11. □
The following Lemma offers information regarding the density of zeros of Riemann’s zeta function.
Lemma 12.
Let , ,and the summation in the inner sum is taken over the non-trivial zeros of Riemann’s ζ-function such that . Then for enough large Y and with the inequalityis fulfilled for an arbitrarily large positive A. Proof. Using Lemmas 5 and 8 and following the proof of Lemma 9 from [
39] we get
where
Working in the same way as in the estimation of integral
in the proof of Lemma 11 when
we obtain
Let us now consider the second integral:
It is easy to see that
when
. So,
and for sufficiently large
Y and
From Equations (
59)–(
61) follows the statement of Lemma 12. □
From now on, we will assume that A is a large positive fixed number for which the estimates of Lemmas 10–12 are satisfied.
We shall prove the following.
Lemma 13.
Let D, , Δ, and , and , be defined by Equations (24), (25), (28), (29), (42) and (43). If and Equation (23) are fulfilled, then for large enough X, the following equalitiesare fulfilled. Proof. The proof is the same as the proof of Lemma 10 [
40] but we use Lemmas 10–12 and the following choice for
T and
:
□
The following Lemmas provide estimates for the integrals and , as well as for the integrals derived from them.
Lemma 14.
For integrals and , defined by Equations (28) and (29), we have Proof. The statement is followed by partial integration. □
Lemma 15.
Let Δ be defined by Equation (24). Then for integrals and , defined by Equations (28) and (29), we have Proof. The proof of the first inequality is similar to that of Lemma 11 [
39]. We will demonstrate the second inequality. We notice that
Using Equation (
63) and the basic estimate
, we can conclude that
By choosing
, we prove the second inequality in our statement. □
The following Lemma is analogous to Lemma 11 from [
39].
Lemma 16.
Let Δ, D, be defined by Equations (24), (25) and (23) are fulfilled. Then for sums and (see Equations (42) and (43)), we have Proof. Using the inequality
the definition of Equation (
42) and arguing as in §6 [
22] we obtain
Working in a similar way, we get the estimate for the second integral. □
From now on, we will put
To find asymptotic formulae for
we need the following
Lemma 17.
Let Δ, D, , z, , , , and be defined by Equations (24), (25), (27)–(29), (42), (43) andThen Proof. From Equation (
33) follows
where
From Lemma 13, and Equations (
19), (
20) and (
23) we have
Using the Cauchy-Schwarz inequality and Lemma 15, we get
Using analogous reasoning, Lemma 16 and Equation (
23) we get
From Equations (
65)–(
67) follows the statement of the Lemma. □
From Lemma 17 and from Equation (
45) we get
Let
We will evaluate
. The estimate of the integral
is the same. Using Lemma 14 and Equation (
33) we get
Using the restriction in Equation (
23), we choose
where
is an arbitrarily small positive number. From Equations (
19), (
20), (
68) and (
69) we get
Reasoning as in Lemma 4 [
22] for
we have
with a constant implied by the symbol ≫ depending only on
and
.
6. Asymptotic Formula for
From Equation (
49), we see that to find a nontrivial lower bound for
we have to prove that the integrals
,
and
are small enough. To establish this, we will use the fact that the ratio
is an irrational number. This will allow us to show that one of the sums
or
can always be estimated non-trivially. By the restrictions in Equation (
23), it follows that
and for these
D we will use Lemma 9. From this Lemma, we see that if
and if
is irrational, then
Also, we need the following
Lemma 18.
Let ,where Δ and H are denoted by Equations (24) and (26), satisfy Equation (3) and is defined by Equation (74). Then there exists a sequence of real numbers such that Proof. The proof is the same as in Lemma 8, [
24]. Since
by (Corollary 1B, [
41]), there exist infinitely many fractions
with arbitrarily large denominators such that
For sufficiently large
q, we choose
X such that
Following the proof of Lemma 8, [
24], we get an infinite sequence
of values of
q, satisfying Equation (
77). Then using Equation (
78) one gets an infinite sequence
of values of
X, such that at least one of the numbers
and
can be approximated by rational numbers with denominators, satisfying Equation (
72). Hence, the inequality Equation (
73) is fulfilled, and the proof is completed. □
The following Lemma gives an upper bound for the number of integers that can be represented as the sum of two squares belonging to some arithmetical progressions in two different ways.
Lemma 19.
Let , , andThen . Proof. It is well known that the number of representations of the integer
n as a sum of two squares is
. Using this fact, we obtain
It is well known (see Equation [
42]) that
and from here the Lemma assertion follows. □
To estimate the integral
we will use Equation (
74) to notice that
Next, from Equation (
33), above inequalities and estimate Equation (
76) for integral
, denoted by Equation (
46) we find
where
We will estimate only the integral
. The estimation of
is the same. Using twice the Cauchy-Schwarz inequality, we get
Arguing as in §6 [
22] we obtain
From Equation (
43) follows
with
defined by Equation (
79). From Lemma 19 we have
. Therefore,
From Equations (
26) and (
80)–(
83) with
follows
Now from Equations (
44), (
48), (
71) and (
84) we obtain
Similarly, we can determine
and
. From Equations (
41) and (
85) we get
Using Equations (
16), (
17) and (
19) we obtain
where
f and
F are functions of the linear sieve as described in Lemma 1. Choosing
= 3.2825 and Equation (
18) we get
From Equation (
70) with
and
we receive
and
. Therefore,
and the proof of Theorem 1 is complete.
7. Conclusions
Diophantine inequalities are an essential topic in analytic number theory. In general, we consider the following problem. Let
r be a positive integer and let
be non-zero real numbers, while
be positive real numbers. Furthermore, let
be a real number. The goal is to demonstrate that the inequality
has infinitely many solutions with primes
, where
can be made as small as possible. The number of variables
r is significant, and there are some hypotheses about the irrationality of at least one ratio
. Furthermore, the assumption that the numbers
do not share the same sign is crucial. When we impose some restrictions on the prime numbers
in Equation (
87), we can obtain a wide variety of problems regarding the solvability of Diophantine inequalities. If, in addition to the restrictions on
, we also add restrictions on the number
r and the variety of exponents
, we get a large number of interesting problems related to Diophantine inequalities. As a rule, the approach to each of these problems combines the Davenport–Heilbronn adaptation of the circle method with a method that corresponds to the specific restrictions imposed on the participating prime numbers.