Abstract
Let be the sequence of imaginary parts of non-trivial zeros of the Riemann zeta-function . Using a certain estimate on the pair correlation of the sequence in the intervals with , we prove that the set of shifts , , approximating any non-vanishing analytic function defined in the strip with accuracy has a positive lower density in as . Moreover, this set has a positive density for all but at most countably . The above approximation property remains valid for certain compositions .
Keywords:
Montgomery pair correlation conjecture; non-trivial zeros; Riemann zeta-function; universality MSC:
11M06; 11M26
1. Introduction
The Riemann zeta-function , , is defined, for , by
where the infinite product is taken over all prime numbers, and has analytic continuation over the whole complex plane, except for the point which is a simple pole with residue 1. The function and its value distribution play an important role not only in analytic number theory but in mathematics in general.
It is well known by a Bohr and Courant work [1] that the set of values of with any fixed is dense in . Voronin obtained [2] the infinite-dimensional version of the Bohr–Courant theorem, proving the so-called universality of . This means that every non-vanishing analytic function in the strip can be approximated by shifts . We recall the modern version of the Voronin theorem. Denote by the class of compact subsets of the strip D with connected complements, and by with the class of continuous non-vanishing functions on K that are analytic in the interior of K. Then, for , and every , the inequality
is true; see, for example, [3,4,5,6]. Thus, we have that there are infinitely many shifts approximating a given function .
The above theorem is of continuous type because in shifts can take arbitrary real values. If runs over a certain discrete set, then we have the discrete universality that was proposed in [7]. Denote by the cardinality of a set A, and suppose that N runs over the set of non-negative integers. If K and are as above, then we have, for and ,
Approximations of analytic functions by more general discrete shifts were considered in [8,9,10].
Denote by the positive imaginary parts of non-trivial zeros of the function . Discrete universality theorems with shifts were obtained in [11,12]. In [11], for this the Riemann hypothesis was used, while in [12], the weak form of the Montgomery pair correlation conjecture [13] was involved. More precisely, the estimate, for ,
was required. Analogical results for more general functions were given in [14,15].
On the other hand, all above theorems are non-effective in the sense that any concrete shift approximating a given analytic function is not known. This shortcoming leads to the idea of universality in intervals as short as possible containing with approximating property. The first result in this direction was obtained in [16].
Theorem 1.
Suppose that , and . Then, for every ,
The aim of this paper is the universality of the function in short intervals with shifts . In this case, the estimate (1) is not sufficient. Therefore, for with , we use the following hypothesis:
which, as estimate (1), also gives a certain information on the pair correlation of non-trivial zeros, differently from estimate (1), however, in short intervals.
Theorem 2.
Suppose that , and estimate (2) are true. Let and . Then, for every and ,
Moreover, “lim inf” can be replaced by “lim” for all but at most countably many .
Theorem 2 has a generalization for certain compositions . Denote by the space of analytic functions on the strip D endowed with the topology of uniform convergence on compacta. Moreover, let
and, for the operator and distinct complex numbers ,
Then we have
Theorem 3.
Suppose that estimate (2) is true, , and is a continuous operator such that . For , let and be a continuous function on K, and analytic in the interior of K. For , let K be an arbitrary compact subset of D, and . Then, for every and ,
Moreover “lim inf” can be replaced by “lim” for all but at most countably many .
For example, the operators and satisfy the hypotheses of Theorem 3 with and .
The proofs of Theorems 2 and 3 use probabilistic limit theorems for measures in the space . Denote by the Borel -field of the space . The main limit theorem will be proved for
as . We divide its proof into four sections.
2. A Limit Theorem on the Torus
Denote by the unit circle on the complex plane, by the set of all prime numbers, and define the set
where for all . With the product topology and pointwise multiplication, the torus is a compact topological Abelian group. Therefore, on , the probability Haar measure can be defined, and we have the probability space . Denote by the pth component of an element , .
In this section, we will prove a limit theorem for
as .
Before the statement of a limit theorem for as , we will recall some useful results that will be used in its proof. Denote by the number of non-trivial zeros of in the region .
Lemma 1 (von Mongoldt formula).
For ,
For the proof, see, for example, [17].
Denote by the number of zeros of with and .
Lemma 2.
Suppose that with . Then, for , uniformly in σ,
Proof of the lemma can be found in [18].
For positive , denote by the von Mongoldt function if , and zero, otherwise.
Lemma 3.
For positive and ,
with every .
Proof.
The lemma is Theorem 2 of [19] with . □
Lemma 4.
Suppose that with . Then, for positive , as ,
Proof.
Since
in view of Lemma 3,
An application of Lemma 1 gives
and
Therefore,
and
Hence,
This together with Equation (3) proves the lemma. □
Now, we state the limit theorem for .
Theorem 4.
Suppose that, for any , . Then converges weakly to the Haar measure as .
Proof.
Denote by , , the Fourier transform of , i.e.,
where the star “*” means that only a finite number of integers are distinct from zero. Thus, by the definition of ,
Clearly,
Now, suppose that . Since the set is linearly independent within the field of rational numbers , in that case we have
Thus, we will estimate the sum
It is easily seen that
where in , and in . Obviously,
Therefore, by Lemma 2 and estimate (2),
This, and estimates (7) and (8) show that
Lemma 4 with implies
Therefore, in view of estimate (9),
Thus, by Equation (5),
This together with Equation (6) shows that
and the lemma is proved because the right-hand side of the latter equality is the Fourier transform of the measure . □
3. A Limit Theorem for Absolutely Convergent Series
Let be a fixed number, and for . Extend the function to the set by setting
and define
and
Then the latter series are absolutely convergent for [5]. Consider the function defined by
The absolute convergence of the series implies the continuity of .
For , define
Theorem 5.
Suppose that . Then converges weakly to the measure .
Proof.
The theorem follows from the equality
continuity of the function , Theorem 4 and Theorem 5.1 of [20]. □
The weak convergence of is closely connected to that of as . Define
Then is an -valued random element on the probability space [5]. We recall that the latter infinite product, for almost all , is uniformly convergent on compact subsets . Denote by the distribution of the random element , i.e.,
The following statement is very important.
Proposition 1.
The probability measure converges weakly to measure as .
Proof.
For , define
It is known that , as , converges weakly to [5]. Moreover, , as , and , as , converge weakly to the same probability measure on . Thus, converges weakly to as . □
4. Mean Square Estimates in Short Intervals
To derive the weak convergence of from that of as , the estimate for
with is needed.
We will use the following mean square estimate in short intervals.
Lemma 5.
Suppose that σ, , is fixed and . Then, uniformly in H,
The lemma follows from Theorem 7.1 of [21], and was used in [16].
Lemma 6.
Suppose that and estimate (2) is true. Then, for every fixed σ, , and ,
Proof.
We will apply the Gallagher lemma connecting discrete mean squares with those continuous of some functions; for the proof, see Lemma 1.4 of [22]. Let , be real numbers, be a finite set in the interval ,
and let be a complex-valued continuous function on having a continuous derivative on . Then the Gallagher lemma asserts that
We apply the Gallagher lemma for the function . In our case , , and }. By estimate (2), we have
Now, an application of the Gallagher lemma gives
The estimate (4) gives with certain
If , then, in view of Lemma 5, the right-hand side of (13) is
If , then
and
Thus, in this case,
This together with estimate (13) shows that
Estimate (14) and an application of the Cauchy integral formula lead to the bound
This, estimate (14) and (12) prove the lemma. □
Now, we are ready to state an approximation lemma.
5. Approximation in the Mean
Denote by the metric in which induces the topology of uniform convergence on compacta. More precisely, for ,
where is a sequence of compact subsets such that
for all , and every compact lies in a certain .
Lemma 7.
Suppose that and (2) is true. Then, for every ,
Proof.
In view of the definition of the metric , it suffices to show that, for every compact ,
Thus, let be a fixed compact set. Denote the points of K by , and fix such that for . It is known [5] that
where
is the Euler gamma-function, and comes from the definition of . Let . From this, we have
with
Therefore, as in the proof of Lemma 12 of [16], we find that
Denote by positive constants. In view of the well-known estimate
we find that
Therefore, by Lemma 5,
Similarly, taking into account inequality (17), we find
This, Equations (18) and (16) prove (15). □
6. A Limit Theorem for
Theorem 6.
Suppose that and estimate (2) is true. Then converges weakly to as .
Proof.
In a certain probability space with measure define the random variable with the distribution
and consider the -valued random element
Moreover, let be the -valued random element with the distribution . Then, by Theorem 5,
where denotes the convergence in distribution. Moreover, by Proposition 1,
Define one more -valued random element
Then, using Lemma 7, we find that, for every ,
Now, this, Equations (19) and (20) together with Theorem 4.2 of [20] show that
and theorem is proved. □
For , define
Corollary 1.
Suppose that is a continuous operator, and (2) is true. Then converges weakly to as .
Proof.
The corollary follows from Theorem 5, continuity of F, equality
and Theorem 5.1 of [20]. □
7. Proof of Universality
Theorems 2 and 3 are derived from Theorem 6 and Corollary 1, respectively, by using the Mergelyan theorem on the approximation of analytic functions by polynomials [23].
Proof of Theorem2.
We recall that
It is well known, see, for example, [5], that the support of the measure is the set S. Define the set
where is a polynomial. Obviously, . Therefore, is an open neighbourhood of an element of the support of the measure . Thus, by a property of the support,
This, Theorem 6 and the equivalent of weak convergence in terms of open sets show that
Hence, by the definition of and ,
Now, we apply the Mergelyan theorem and choose the polynomial satisfying
This and inequality (22) prove the first part of the theorem.
To prove the second part of the theorem, define the set
Then the set is a continuity set of the measure for all but at most countably many . This remark, Theorem 6 and the equivalent of weak convergence of probability measures in terms of open sets show that
for all but at most countably many . Inequality (23) implies the inclusion . Therefore, in view of inequality (21), we have . This, Equation (24) and the definitions of and prove the second part of the theorem. □
Proof of Theorem 3.
Denote by the support of the measure . We observe that contains the closure of the set . Actually, let and G be any open neighborhood of g. Then the set is open as well, and lies in S. Hence, because S is the support of . Therefore,
This shows that contains the set and its closure.
Case . By the Mergelyan theorem, there exists a polynomial such that
Then, for all if is small enough. Therefore, by the Mergelyan theorem again, we find a polynomial such that
Since , the set
is an open subset of . Hence,
This inequality together with Corollary 1, inequalities (25) and (26) prove the theorem in the case of the lower density.
In the case of density, consider the set defined in the proof of Theorem 2 which is a continuity set of the measure for all but at most countably many . Therefore, by Corollary 1,
Inequalities (25) and (26) show that . Thus, by inequality (27), . This, Equation (28) and the definitions of and prove the theorem in the case of density.
Case . In this case, the function lies in . Therefore, the Mergelyan theorem is not needed, and the theorem follows immediately from Corollary 1. □
Author Contributions
Conceptualization, A.L. and D.Š.; methodology, A.L. and D.Š.; investigation, A.L. and D.Š.; writing—original draft preparation, A.L. and D.Š.; writing—review and editing, A.L. and D.Š. All authors have read and agreed to the published version of the manuscript.
Funding
The research of the first author is funded by the European Social Fund (project number 09.3.3-LMT-K-712-01-0037) under grant agreement with the Research Council of Lithuania (LMT LT).
Conflicts of Interest
The authors declare no conflict of interest.
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