3. Sum of Soft Topological Spaces
In this section, we introduce and study the concept of sum of soft topological spaces. Then, we investigate which properties are additive and finitely additive.
Definition 18. A collection of two or more soft sets is said to be pairwise disjoint if the intersection of any two distinct soft sets is the null soft set.
Proposition 2. Let be a family of pairwise disjoint soft topological spaces and . Then, the collection over is a soft open set in for every defines a soft topology on Y with a fixed set of parameters A.
Proof. It is clear that and are members of . Let , where be an arbitrary family. Then, for each and . Thus, for each . Thus, is closed under arbitrary unions. Let and be two members of . Then, and for each . Therefore, for each . Thus, is closed under finite intersections. Hence, is a soft topology on Y. □
Definition 19. The soft topological space given in the above proposition is said to be the sum of soft topological spaces and is denoted by .
Remark 1. The term of sum of soft topological spaces was given in [31] without a condition of pairwise disjointness. Moreover, the authors of [31] did not study the properties of additive, finitely additive and countably additive which represent the main goal of this study. In fact, this definition leads to confusion on how constructing the sum of soft topological spaces and losing some well-known properties of the sum of soft topological spaces as the following example shows: Example 1. Let and let and . Consider that and are two soft topologies on and , respectively. The sum of soft topological spaces and does not exist according to Definition 19 because . However, the sum of soft topologies and on according to the definition given in [31] is . It is clear that and do not belong to τ and this contradicts the fact that the universal sets and belong to τ, see Corollary 1. Moreover, is soft connected and this contradicts the fact that the sum of soft topological spaces is soft disconnected, see Corollary 2. Proposition 3. A soft subset of is soft closed if and only if is a soft closed subset of for every .
Proof. is a soft closed subset of is a soft open subset of for every is a soft closed subset of for every . □
Corollary 1. All soft sets are soft clopen in .
Corollary 2. Every sum of soft topological spaces is soft disconnected.
Proposition 4. If is a class of pairwise disjoint soft topological spaces and is a subspace of for every , then the soft topology of the sum of subspaces and the soft topological subspace on of the sum soft topology coincide.
Proof. Straightforward. □
Definition 20. A property is said to be:
- 1.
additive if, for any family of soft topological spaces with the property , the sum of this family also has property .
- 2.
finitely additive (resp., countably additive) if, for any finite (resp., countable) family soft topological spaces with the property , the sum of this family also has property .
Theorem 2. The property of being a p-soft -space is an additive property for .
Proof. We prove the theorem in the case of . Let . Then, we have the following two cases:
1. There exists such that .
Since is p-soft , then there exist two disjoint soft open subsets and of such that and . It follows from Definition 19 that and are disjoint soft open subsets of .
2. There exist such that and .
Now, and are soft open subsets of and , respectively. It follows from Definition 19 that and are disjoint soft open subsets of .
It follows from the two cases above that is a p-soft -space.
The theorem can be proved similarly in the cases of .
To prove the theorem in the cases of and , it suffices to prove the p-soft regularity and soft normality, respectively.
First, we prove the p-soft regularity property. Let be a soft closed subset of such that . It follows from Proposition 3 that is soft closed in for each . Since , there is only such that . This implies that there are disjoint soft open subsets and of such that and . Now, is a soft open subset of containing . The disjointness between and ends the proof that is a p-soft regular space.
Second, we prove the soft normality property. Let and be two disjoint soft closed subsets of . It follows from Proposition 3 that and are soft closed in for each . Since is soft normal for each , then there exist two disjoint soft open subsets and of such that and . This implies that , and . Hence, is a soft normal space. □
Proposition 5. The property of being a discrete soft space is an additive property.
Proof. Let be a soft subset of . Then, is a soft subset of for each . Therefore, it is a soft open subset of for each . Hence, is a soft open subset of . □
In the following two examples, we show that the properties of indiscrete and door soft spaces are not additive properties. Recall that a soft topological space is a door soft space if each subset in it is soft open, or soft closed, or both.
Example 2. Let and let and . Then, and are two indiscrete soft topologies on and , respectively. Now, is the sum of soft topologies and on . Since τ is not indiscrete, then the indiscrete soft space property is not an additive property.
Example 3. Let and let and . Then, , and are two door soft topologies on and , respectively. Now, , is the sum of soft topologies and on . Since τ is not a door soft topology, then the door soft topology is not an additive property.
Proposition 6. The property of being a soft compact space is a finitely additive property.
Proof. Let be a finite family of pairwise disjoint soft compact spaces and let be the sum of this family. Suppose that is a soft open cover of . Then, for every . Since is soft compact for every , there exist finite subsets of I such that , , ..., . Letting , now, for every . Since M is finite, then is soft compact. □
The following example shows that soft compactness is not an additive property.
Example 4. Let and let , where n belongs to the set of natural numbers. Consider the discrete soft topology on . Now, is a family of pairwise disjoint soft compact spaces. It follows from Proposition 5 that the sum of these soft spaces is soft discrete. Obviously, is not soft compact. Hence, soft compactness is not an additive property.
Proposition 7. If the sum of soft topological spaces is soft compact, then we have the following two assertions that are true:
- 1.
all are soft compact.
- 2.
the index set I is finite.
Proof. 1. From Corollary 1, is a soft closed subspace of for each . It follows from Theorem 1 that is soft compact for each .
2. Let be the sum of soft topological spaces. Then, is a soft open cover of . It is clear that does not have a finite subcover. This contradicts the fact that is soft compact. Hence, it must be that I is finite. □
Remark 2. It is clear that the soft topological spaces and given in Example 2 are soft hyperconnected. Moreover, they are soft connected. However, the sum of and is neither soft hyperconnected nor soft connected. This means that the properties of soft hyperconnected and soft connected are not finite additive.
Similarly to the proof of Proposition 6, we prove the following:
Proposition 8. The property of being a soft Lindelöf space is a countably additive property.
Definition 21. A soft topological space is said to be soft locally compact if every soft point has a soft compact neighborhood.
Theorem 3. The sum of soft topological spaces is soft locally compact if and only if all soft spaces are soft locally compact.
Proof. Necessity: Let be a soft point in . Then, there is a soft compact neighborhood of in . Since is soft closed, then is a soft compact set in . Therefore, is a soft compact set in . Since , then . Hence, is a soft compact neighborhood of in , as required.
Sufficiency: Let be a soft point in . Then, there is such that . Since is soft locally compact, then there is a soft compact neighborhood of in . Since for each , then is a soft compact neighborhood of in . □
Theorem 4. The sum of soft topological spaces is soft paracompact if and only if all soft spaces are soft paracompact.
Proof. Necessity: From Corollary 1, is a soft closed subspace of for each . It follows from Theorem 1 that is soft paracompact for each .
Sufficiency: Suppose that is a soft open cover of . Then, is a soft open cover of for each . By hypothesis, there is a such that is a locally finite soft open refinement of . Now, is a soft open refinement of . Since the family of is pairwise disjoint, then is locally finite as well. Hence, is soft paracompact. □
Definition 22. Let be a family of soft mappings. Then, we define a soft mapping as follows: For each soft subsets and of and , respectively, we have:
- 1.
; and
- 2.
Theorem 5. A soft mapping is soft continuous (resp. soft open, soft closed) if and only if every soft mapping is soft continuous (resp. soft open, soft closed).
Proof. We merely give a proof for the theorem in the case of soft continuity and one can prove the cases between parentheses similarly.
Necessity: Suppose that a soft mapping is soft continuous. Taking an arbitrary soft map , where . Let be a soft open subset of . Then, is a soft open subset of . By assumption, is a soft open subset of . Since for each , then . Therefore, is a soft open subset of , as required.
Sufficiency: Suppose that is soft continuous for every and let be a soft open subset of . Now, is a soft open subset of for every . By assumption, is a soft open subset of for every . Therefore, is a soft open subset of . Since , then is a soft open subset of , as required. □
Corollary 3. A soft mapping is soft homeomorphism if and only if every soft mapping is soft homeomorphism.
Theorem 6. Let and (resp. and , and ) be the soft interior (resp. soft closure, soft limit) points of a soft set in and , respectively. Then:
- 1.
.
- 2.
.
- 3.
.
Proof. and
[Since ]
.
2, 3. Following similar above arguments, results 2 and 3 are satisfied. □
Corollary 4. Let and be the soft boundary of a soft set in and , respectively. Then, .
Proof. (by the above theorem)
. □
Theorem 7. A soft set is soft semi-open (resp. soft pre-open, soft α-open, soft b-open, soft β-open) in if and only if all are soft semi-open (resp. soft pre-open, soft α-open, soft b-open, soft β-open) in .
Proof. We give a proof for the theorem in the case of soft semi-open sets and one can prove the cases between parentheses similarly.
Necessity: Let be a soft semi-open subset of . Then, . Now, . Since is soft open in , then . From Theorem 6, we have . Thus, . Hence, is a soft semi-open set in .
Sufficiency: Let be a soft semi-open subset of . Then, . It follows from Theorem 6 that . Thus, is soft semi-open in . It is well known that is a soft semi-open subset of . □
Lemma 1. Let be a soft subset of . Then, the collection is locally finite.
Proof. For each , there is a soft open subset of such that . Since is the only member of such that , the desired result holds. □
Theorem 8. is a soft dense subset of if and only if all are a soft dense subset of .
Proof. Necessity: First, we prove that for each . Suppose that there exists such that . Then, . Therefore, . However, this contradicts that is a soft dense subset of . Second, it is clear that . Since the collection is locally finite, then . This implies that for each .
Sufficiency: The proof follows from the fact that . □
Proposition 9. The property of being a soft separable space is a countably additive property.
Proof. Let be a countable family of pairwise disjoint soft topological spaces such that there exists a countable soft dense subset of for each . Set . Obviously, is countable. In addition, . Thus, is soft dense. Thus, is soft separable. Hence, the desired result is proved. □
Theorem 9. is soft extremally disconnected if and only if all are soft extremally disconnected.
Proof. Necessity: Let be a soft open subset of . Then, it is a soft open subset of . By hypothesis, is soft open. Since , then is a soft open subset of . Hence, is soft extremally disconnected.
Sufficiency: Let be a soft open subset of . Then, . It follows from Lemma 1 that . Since is a soft open subset of for each , then is a soft open subset of . Thus, is soft open. Hence, is soft extremally disconnected. □
The other path of this study is the answer of the following two questions:
Under what conditions can a soft topological space represent the sum of soft topological spaces?
If a soft topological space represents the sum of soft topological spaces, what is the maximum number of these soft topological spaces?
The following results answer these questions.
Theorem 10. If is stable soft disconnected, then it represents the sum of two soft topological spaces.
Proof. Since is soft disconnected, then it contains at least a proper soft clopen set . Since is stable, then for each . Thus, the two soft subspaces and are soft topological spaces such that is their sum. □
Corollary 5. If contains m stable soft clopen sets, then represents the sum of m soft topological spaces.
Theorem 11. If for a soft subset of . Then, the maximum partition of for Y represents the maximum number of soft topological spaces of the sum .
Proof. Straightforward. □