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Article

Best Proximity Point Results for Multi-Valued Mappings in Generalized Metric Structure

1
Department of Mathematics, Quaid-i-Azam University, Islamabad 45320, Pakistan
2
Department of Mathematics, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia
*
Author to whom correspondence should be addressed.
Symmetry 2024, 16(4), 502; https://doi.org/10.3390/sym16040502
Submission received: 16 March 2024 / Revised: 7 April 2024 / Accepted: 15 April 2024 / Published: 21 April 2024

Abstract

:
In this paper, we introduce the novel concept of generalized distance denoted as J θ and call it an extended b-generalized pseudo-distance. With the help of this generalized distance, we define a generalized point to set distance J θ ( u , H ) , a generalized Hausdorff type distance and a P J θ -property of a pair ( H , K ) of nonempty subsets of extended b-metric space ( U , ρ θ ) . Additionally, we establish several best proximity point theorems for multi-valued contraction mappings of Nadler type defined on b-metric spaces and extended b-metric spaces. Our findings generalize numerous existing results found in the literature. To substantiate the introduced notion and validate our main results, we provide some concrete examples.

1. Introduction

Fréchet [1] began the study of spaces with distance functions in 1905 by giving every pair of generic objects in a nonempty set a non-negative value. These spaces were subsequently termed metric spaces by Hausdorff. In these types of spaces, the distance between two objects is specified by a metric function or distance function that, in addition to being non-negativity, also has the triangle inequality, symmetry, and identity of indiscernibles. There are plenty of metric space generalizations, and most of them are accomplished by eradicating, weakening, or expanding one of the aforementioned features. (see, for example, refs. [2,3,4,5,6,7] and the references therein). One of the generalizations of metric space is symmetric space. The triangular inequality of a metric function is removed in symmetric spaces (see [8,9]), and several substitutes of the triangular inequality are used to demonstrate different features and the existence of a fixed point (abbreviated as F. point) of contractive type mappings. Numerous researchers developed significant F. point theorems in the context of symmetric spaces, which they applied to the split minimization problem, the split feasibility problem, and the positive solutions of fractional periodic boundary value problems (see, for example, [10,11]). A fundamental result in F. point theory is the Banach contraction principle. Several extensions of this result have appeared in the literature (see, for example, refs. [12,13,14] and the references cited therein). We can also find various generalizations of the variant Banach contraction principle using the graph theoretic approach. The graphs considered by Jachymski [15] are such that G = ( V ( G ) ; E ( G ) ) , where V ( G ) is the set of vertices and E ( G ) is the set of edges, satisfy the conditions V ( G ) = U and Δ U E ( G ) U × U , so that E ( G ) is, in fact, a reflexive binary relation on U . Here, Δ U = { ( u , u ) : u U } is the diagonal of U × U . Other recent results for single-valued and multi-valued operators in metric spaces endowed with graphs are given by Bojor [16], Aleomraninejada et al. [17], Beg et al. [18] and by Chifu et al. [19].
In a metric space ( U , ρ ) , the F. point of a multi-valued mapping Γ : U 2 U is an element p U , such that p Γ p . If Γ p is a closed subset of U , then p U is a F. point of Γ if D ( p , Γ p ) = 0 , where D ( p , Γ p ) = inf u Γ p ρ ( p , u ) . Now, if H and K are nonempty subsets of a metric space ( U , ρ ) and Γ : H 2 K is a multi-valued mapping. Then it is not necessary that Γ has a F. point p in H . The idea of best proximity point originates here. A best proximity point (abbreviated as B.P. point) of the multi-valued mapping Γ : H 2 K is an element p H , such that D ( p , Γ p ) = d s t ( H , K ) where d s t ( H , K ) = inf { ρ ( u , e ) : u H , e K } . If Γ : H K is a non-self single-valued mapping, then an element p H is called a B.P. point of Γ if ρ ( p , Γ p ) = d s t ( H , K ) . Many researchers have been interested in the topics of B.P. points for single-valued and multi-valued mappings in recent years. For single-valued mappings, the existence of B.P. points was established by S. Sadiq Basha et al. [20], C. Di Baria et al. [21], M.A. Al-Thagafi and N. Shahzad [22], D. Sarkar [23], and many others. B.P. point theorems for multi-valued mappings were established by G. AlNemer et al. [24], K. Włodarczyk and R. Plebaniak [25], A. Abkar and M. Gabeleh [26], M.A. Al-Thagafi and N. Shahzad [27], M. Gabeleh [28], and many others. In 2014, Plebaniak [29] established an important B.P. point theorem by adopting the following definitions.
Definition 1
([29]). Let ( U , ρ b ) be a b-metric space (b-m space) (with constant s 1 ). A mapping J b : U × U [ 0 , ) is said to be a b-generalized pseudo-distance (b-G pseudo-distance) on U if it satisfies
(Jb1)
J b ( u , t ) s [ J b ( u , e ) + J b ( e , t ) ] u , e , t U .
(Jb2)
For any sequences { u n : n N } and { e n : n N } in U satisfying
lim m sup n > m J b ( u m , u n ) = 0 ,
and
lim n J b ( u n , e n ) = 0 ,
the following holds
lim n ρ b ( u n , e n ) = 0 .
Throughout, let the triplet ( U , ρ b , J b ) denote a b-m space ( U , ρ b ) (with s 1 ) equipped with a b-G pseudo-distance J b .
Definition 2
([29]). Let H and K be the subsets of a topological space ( U , τ ) . A multi-valued mapping Γ : H 2 K is called closed whenever a sequence { u n : n N } in H converges to u H and a sequence { e n : n N } in K converges to e K , such that e n Γ ( u n ) , f o r a l l n N , implying that e Γ ( u ) .
Theorem 1
([29]). Let H and K be the subsets of a complete space ( U , ρ b , J b ) , such that they are closed, J b is associated with ( H , K ) , and ( H , K ) has the P J b -property. Let Γ : H 2 K be a closed, multi-valued mapping, such that
s H J b ( Γ u , Γ e ) k J b ( u , e ) u , e U ,
for some 0 k < 1 . Let Γ u C B ( U ) , Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .

2. Preliminaries

The triangle inequality related to the metric function is important in the context of B.P point theorems and fixed-point theorems for demonstrating the convergence of an iterative sequence. Consequently, a number of authors have endeavored to identify spaces where the triangle inequality was incorporated in a more mild or comprehensive manner, guaranteeing that the presence of a fixed point or B.P. point could still be proven. In 1993, Czerwik [3] gave a weaker axiom than the triangular inequality of metric space and formally defined the notion of b-metric space. Afterward, Fagin et al. [30] argued about a relaxation of the triangle inequality and named this new distance measure non-linear elastic math (NEM). A comparable form of the relaxed triangle inequality was also applied to the measurement of ice floes [31] and trade [32]. Because of all those applications, Kamran et al. [13] was able to present the following definition of extended b-metric space.
Definition 3
([13]). Let U be a nonempty set and θ : U × U [ 1 , ) .
A function ρ θ : U × U [ 0 , ) is called an extended b-metric if for each u , e , t U it satisfies
(Mθ1):
ρ θ ( u , e ) = 0 i f f u = e ;
(Mθ2):
ρ θ ( u , e ) = ρ θ ( e , u ) ;
(Mθ3):
ρ θ ( u , t ) θ ( u , t ) [ ρ θ ( u , e ) + ρ θ ( e , t ) ] .
The pair ( U , ρ θ ) is called an extended b-metric space (E.b-m space).
Remark 1.
A b-m space becomes a special case of E.b-m space when θ ( u , e ) = s for s 1 , u , e U .
Example 1
([33]). Let U = [ 0 , 1 ] . Define θ : U × U [ 0 , ) as
θ ( u , e ) = 1 + u + e u + e f o r u e 0 1 f o r u = e = 0 .
Let ρ θ : U × U [ 0 , ) be defined by
ρ θ ( u , e ) = 1 ue f o r u , e ( 0 , 1 ] w i t h u e ,
ρ θ ( u , e ) = 0 f o r u , e [ 0 , 1 ] w i t h u = e ,
ρ θ ( u , 0 ) = ρ θ ( 0 , u ) = 1 u f o r u ( 0 , 1 ] .
Then ( U , ρ θ ) is E.b-m space.
Note. Throughout this manuscript, we assume that the E.b-metric ρ θ is continuous on U 2 = U × U .
The following is the main result of [13].
Theorem 2
([13]). Let ( U , ρ θ ) be a complete E.b-m space and a mapping Γ : U U satisfy
ρ θ ( Γ u , Γ e ) k ρ θ ( u , e ) u , e U ,
for some 0 k < 1 such that for each u 0 U , lim n , m θ ( u n , u m ) < 1 k , here u n = Γ n ( u 0 ) ,   n = 1 , 2 , 3 , . Then ρ θ ( p , Γ p ) = 0 for a unique p U . Moreover, for each e U , Γ n ( e ) p .
Drawing inspiration from the concept of extended b-metric and b -generalized pseudo-distances, we introduce the novel concept of generalized distance, within an extended b-metric space. This notion extends, generalizes, and improves the notion of E.b-metric and the notion of b-generalized pseudo-distances. Furthermore, some B.P. point theorems are proved in this new framework, which generalizes and extends many previous findings in the literature. In order to clarify and validate ideas and claims, numerous examples are offered.

3. Main Results

In the following, we start by formulating our notion.
Definition 4.
Let ( U , ρ θ ) be an E.b-m space. A mapping J θ : U × U [ 0 , ) is said to be an extended b-generalized pseudo-distance (E.b-G pseudo-distance) on U if it satisfies
(Jθ1)
J θ ( u , t ) θ ( u , t ) [ J θ ( u , e ) + J θ ( e , t ) ] u , e , t U .
(Jθ2)
For any sequences { u n : n N } and { e n : n N } in U satisfying
lim m sup n > m J θ ( u m , u n ) = 0 ,
and
lim n J θ ( u n , e n ) = 0 ,
the following holds
lim n ρ θ ( u n , e n ) = 0 .
Remark 2.
Every E.b-metric ρ θ : U × U [ 0 , ) on U is an E.b-G pseudo-distance on U , but the converse is not true in general.
Example 2.
Let B be a closed subset of ( U , ρ θ ) such that it contains at least two points. Let r > 0 with r > δ ( B ) where δ ( B ) = sup { ρ θ ( u , e ) ; u , e B } .
Define J θ : U × U [ 0 , ) as
J θ ( u , e ) = ρ θ ( u , e ) i f { u , e } B r i f { u , e } B .
Then, J θ is an extended b-generalized pseudo-distance on U .
Proof. 
(Jθ1)
Let u 0 , e 0 , t 0 U satisfy
J θ ( u 0 , t 0 ) > θ ( u 0 , t 0 ) [ J θ ( u 0 , e 0 ) + J θ ( e 0 , t 0 ) ] .
Then, { u 0 , e 0 , t 0 } is not a subset of B , because if it is a subset of B , then
J θ ( u 0 , e 0 ) = ρ θ ( u 0 , e 0 ) , J θ ( u 0 , t 0 ) = ρ θ ( u 0 , t 0 ) , J θ ( e 0 , t 0 ) = ρ θ ( e 0 , t 0 ) .
So (8) becomes
ρ θ ( u 0 , t 0 ) > θ ( u 0 , t 0 ) [ ρ θ ( u 0 , e 0 ) + ρ θ ( e 0 , t 0 ) ] .
This is a contradiction to the fact that ρ θ is an extended b-metric on U . Therefore, there exists some u { u 0 , e 0 , t 0 } , such that u B . If u = u 0 , then J θ ( u 0 , t 0 ) = r , and J θ ( u 0 , e 0 ) = r . Thus (8) becomes r > θ ( u 0 , t 0 ) [ r + J θ ( e 0 , t 0 ) ] , which is a contradiction.
Similarly, if we take u = e 0 or u = t 0 , then we obtain a contradiction. Hence, the condition ( J θ 1 ) is fulfilled, i.e.,
J θ ( u , t ) θ ( u , t ) [ J θ ( u , e ) + J θ ( e , t ) ] for all u , e , t U .
(Jθ2)
Let { u n : n N } and { e n : n N } be any sequences in U such that
lim m sup n > m J θ ( u m , u n ) = 0 and lim n J θ ( u n , e n ) = 0 . We show that
lim n ρ θ ( u n , e n ) = 0 .
Since lim n J θ ( u n , e n ) = 0 , lim n t n = 0 where t n = J θ ( u n , e n ) R + , which further implies that for 0 < ε < r there is some k N , such that
t n < ε < r whenever n k .
From this we obtain the following:
J θ ( u n , e n ) < ε < r whenever n k ,
ρ θ ( u n , e n ) < ε whenever n k .
Since t n = J θ ( u n , e n ) n N , and J θ ( u , e ) = ρ θ ( u , e ) u , e U , when J θ ( u , e ) r , lim n ρ θ ( u n , e n ) = 0 .
Note. Throughout, let the triplet ( U , ρ θ , J θ ) denote an E.b-m space ( U , ρ θ ) equipped with the E.b-G pseudo-distance J θ .
Remark 3.
An E.b-G pseudo-distance need not be a b-G pseudo-distance.
The following counter-example validates Remark 3.
Example 3.
Let U = [ 0 , 1 ] . Define θ : U × U [ 0 , ) as
θ ( u , e ) = 1 + u e u + e f o r u , e [ 0 , 1 ] 3 2 f o r u = e = 0 .
Let ρ θ : U × U [ 0 , ) be defined by
ρ θ ( u , e ) = 1 u e i f u , e ( 0 , 1 ] a n d u e ,
ρ θ ( u , e ) = 0 i f u , e [ 0 , 1 ] a n d u = e ,
ρ θ ( u , 0 ) = ρ θ ( 0 , u ) = 1 u i f u ( 0 , 1 ] .
Then, ( U , ρ θ ) is an E.b-m space. (See [34]). Let J θ : U × U [ 0 , ) be defined by
J θ ( u , e ) = ρ θ ( u , e ) f o r a l l u , e U .
Then, by Remark 2, the map J θ is an E.b-G pseudo-distance on U . We show that J θ is not a b-G pseudo-distance on U . Let us suppose, on the contrary, J θ be a b-G pseudo-distance on U . Then, there is some s 1 , such that
J θ ( u , t ) s [ J θ ( u , e ) + J θ ( e , t ) ] f o r a l l u , e , t U .
Now, if l > 1 , then l + 1 > 1 and 1 l , 1 l + 1 ( 0 , 1 ] . Let u = 1 l , e = 0 , t = 1 l + 1 , then (9) becomes
J θ 1 l , 1 l + 1 s J θ 1 l , 0 + J θ 0 , 1 l + 1 .
So l ( l + 1 ) s [ l + l + 1 ] . Thus
l 2 + l s [ 2 l + 1 ] .
Let l = 3 s + 3 > 1 . Then (10) becomes
( 3 s + 3 ) 2 + 3 s + 3 s [ 2 ( 3 s + 3 ) + 1 ]
and so
3 s 2 + 14 s + 12 0 ,
which is a contradiction to s 1 . Thus, J θ is not a b-G pseudo-distance on U .
We formulate the following definitions.
Definition 5.
Let H and K be nonempty subsets of ( U , ρ θ , J θ ) . Define
J θ ( u , K ) = inf e K J θ ( u , e ) ,
d s t ( H , K ) = inf { J θ ( u , e ) : u H , e K } ,
H 0 = { u H : J θ ( u , e ) = d s t ( H , K ) f o r s o m e e K } ,
K 0 = { e K : J θ ( u , e ) = d s t ( H , K ) f o r s o m e u H } .
H J θ : C B ( U ) × C B ( U ) [ 0 , ) b y
H J θ ( H , K ) = max { sup u H J θ ( u , K ) , sup e K J θ ( e , H ) } f o r a l l H , K C B ( U ) .
Here, C B ( U ) = { S U ; S is closed and bounded } .
Definition 6.
Let H and K be the subsets of ( U , ρ θ , J θ ) with H 0 . Then:
(i)
The pair ( H , K ) is said to have a P J θ -property if and only if
J θ ( u 1 , e 1 ) = d s t ( H , K ) , J θ ( u 2 , e 2 ) = d s t ( H , K ) J θ ( u 1 , u 2 ) = J θ ( e 1 , e 2 ) ,
where u 1 , u 2 H 0 , and e 1 , e 2 K 0 .
(ii)
An E.b-G pseudo-distance J θ is said to be associated with ( H , K ) , if for any sequences { u n : n N } and { e n : n N } in U , such that
lim n u n = u ; lim n e n = e ; a n d J θ ( u n , e n 1 ) = d s t ( H , K ) n N ,
we have ρ θ ( u , e ) = d s t ( H , K ) .
It is clear that for E.b-metric space ( U , ρ θ ) if we put J θ = ρ θ , then the mapping ρ θ is associated with each pair ( H , K ) of nonempty subsets of U , because of the continuity of ρ θ (we have chosen ρ θ to be continuous throughout).
The following lemmas are important to prove our main result.
Lemma 1.
Let { u n : n { 0 } N } be a sequence in the complete space ( U , ρ θ , J θ ) , such that
lim m sup n > m J θ ( u m , u n ) = 0 ,
and lim n , m θ ( u n , u m ) exists and is finite. Then { u n : n { 0 } N } is Cauchy.
Proof. 
From (11) we can write that
ε > 0 , m 1 = m 1 ( ε ) N , m > m 1 , { sup { J θ ( u m , u n ) : n > m } < ε } .
In particular,
ε > 0 , m 1 = m 1 ( ε ) N , m > m 1 , t N , { J θ ( u m , u t + m ) < ε } .
Let i 0 , j 0 N , i 0 > j 0 , be fixed and arbitrary. Define
e m = u i 0 + m a n d t m = u j 0 + m for m N .
Then, (12) gives
lim m J θ ( u m , e m ) = lim m J θ ( u m , t m ) = 0 .
Therefore, by (11) and (13) and ( J θ 2 ) , we obtain
lim m ρ θ ( u m , e m ) = lim m ρ θ ( u m , t m ) = 0 .
Let k = i 0 + m , l = j 0 + m , then by using ( ρ θ 3 ) , (13), and (15) we have
ρ θ ( u k , u l ) = ρ θ ( u i 0 + m , u j 0 + m ) θ ( u i 0 + m , u j 0 + m ) [ ρ θ ( u i 0 + m , u m ) + ρ θ ( u m , u j 0 + m ] = θ ( u i 0 + m , u j 0 + m ) ρ θ ( u i 0 + m , u m ) + θ ( u i 0 + m , u j 0 + m ) ρ θ ( u m , u j 0 + m ) = θ ( u i 0 + m , u j 0 + m ) ρ θ ( e m , u m ) + θ ( u i 0 + m , u j 0 + m ) ρ θ ( u m , t m ) 0 as m .
Thus, { u n : n { 0 } N } is Cauchy. □
The following example validates Lemma 1.
Example 4.
Let U = [ 0 , 1 ] with the extended b-metric ρ θ defined in Example 1. Let B = [ 0.6 , 0.8 ] and J θ : U × U [ 0 , ) be defined by
J θ ( u , e ) = ρ θ ( u , e ) i f { u , e } B 4 i f { u , e } B .
Then, by Example 2, the mapping J θ is an E.b-G pseudo-distance on U . Define { u n = 0.5 : n N } , then J θ ( u m , u n ) = ρ θ ( u m , u n ) = 0 , m , n N and lim m sup n > m J b ( u m , u n ) = 0 . Also lim n , m θ ( u n , u m ) = 1.25 , which is a finite number. All the conditions of Lemma 1 hold, and lim n , m ρ θ ( u m , u n ) = lim n , m ρ θ ( 0.5 , 0.5 ) = 0 . Hence, { u n = 0.5 : n N } , is a Cauchy sequence.
Note. Throughout, let H and K denote the nonempty closed subsets of U .
Lemma 2.
Let the space ( U , ρ θ , J θ ) be complete and Γ : H 2 K be a multi-valued mapping. Then,
u , e H , β > 0 t Γ u , x Γ e { J θ ( t , x ) H J θ ( Γ u , Γ e ) + β } .
Proof. 
Let u , e H , β > 0 and t Γ u be fixed and arbitrary. Then by infimum definition,
x Γ e , { J θ ( t , x ) < inf { J θ ( t , y ) : y Γ e } + β } .
Next,
inf { J θ ( t , y ) : y Γ e } + β sup { inf { J θ ( z , y ) : y Γ e } : z Γ u } + β max { sup { inf { J θ ( z , y ) : y Γ e } : z Γ u } , sup { inf { J θ ( y , z ) : z Γ u } : y Γ e } + β = H J θ ( Γ u , Γ e ) + β .
Hence, by (17) we obtain
J θ ( t , x ) H J θ ( Γ u , Γ e ) + β } .
Thus, (16) holds. □
The following example validates Lemma 2.
Example 5.
Let ( U , ρ θ ) be the E.b-m space defined in Example 1. Let H = { 0.1 , 0.2 , 0.5 , 0.6 } , K = [ 0.7 , 0.9 ] , and B = { 0.1 , 0.2 } [ 0.5 , 0.9 ] and J θ : U × U [ 0 , ) be defined by
J θ ( u , e ) = d θ ( u , e ) i f { u , e } B 51 i f { u , e } B
for all u , e U . Then, by Example 2, the mapping J θ is an E.b-G pseudo-distance on U . Assume that Γ : H 2 K is of the form
Γ u = { 0.7 , 0.75 , 0.8 } i f u = 0.1 { 0.8 , 0.85 , 0.9 } i f u = 0.2 { 0.9 } i f u { 0.5 , 0.6 } .
We consider the following cases.
Case (i)
If Γ u = { 0.7 , 0.75 , 0.8 } , Γ e = { 0.8 , 0.85 , 0.9 } , then u = 0.1 , e = 0.2 and H J θ ( Γ u , Γ e ) = 1.58 . For t = 0.7 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.7 , 0.9 ) = 1.58 H J θ ( Γ u , Γ e ) = 1.58 + β . For t = 0.75 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.75 , 0.9 ) = 1.48 H J θ ( Γ u , Γ e ) = 1.58 + β . For t = 0.8 Γ u , ,   x = 0.8 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.8 , 0.8 ) = 0 H J θ ( Γ u , Γ e ) = 1.58 + β . So in this case, Equation (16) holds.
Case (ii)
If Γ u = { 0.7 , 0.75 , 0.8 } , Γ e = { 0.9 } , then u = 0.1 , e { 0.5 , 0.6 } , H J θ ( Γ u , Γ e ) = 1.58 . For t = 0.7 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.7 , 0.9 ) = 1.58 H J θ ( Γ u , Γ e ) = 1.58 + β . For t = 0.75 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.75 , 0.9 ) = 1.48 H J θ ( Γ u , Γ e ) = 1.58 + β . For t = 0.8 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.8 , 0.9 ) = 1.38 H J θ ( Γ u , Γ e ) = 1.58 + β . So in this case, Equation (16) holds.
Case (iii)
If Γ u = { 0.8 , 0.85 , 0.9 } , Γ e = { 0.9 } , then u = 0.2 , e { 0.5 , 0.6 } , and H J θ ( Γ u , Γ e ) = 1.38 . For t = 0.8 Γ u , ,   x = 0.9 Γ e , such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.8 , 0.9 ) = 1.38 H J θ ( Γ u , Γ e ) = 1.38 + β . For t = 0.85 Γ u , ,   x = 0.9 Γ e such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.85 , 0.9 ) = 1.3 H J θ ( Γ u , Γ e ) = 1.38 + β . For t = 0.9 Γ u , ,   x = 0.9 Γ e such that for all β > 0 , we have J θ ( t , x ) = J θ ( 0.9 , 0.9 ) = 0 H J θ ( Γ u , Γ e ) = 1.38 + β . So in this case, Equation (16) holds.
In the following, we include our first main result.
Theorem 3.
Let the space ( U , ρ θ , J θ ) be complete, such that J θ is associated with ( H , K ) and ( H , K ) has the P J θ -property. Let Γ : H 2 K be a closed, multi-valued mapping, such that
s u H J θ ( Γ u , Γ e ) k J θ ( u , e ) ,
for all u , e U , and for some 0 k < 1 with
lim n , m θ ( u n , u m ) < 1 k , lim n , m θ ( e n , e m ) < 1 k .
Here, s u = inf e Γ u θ ( u , e ) , u n H 0 and e n Γ u n , n = 0 , 1 , 2 , . Let Γ u C B ( U ) , Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
Let u 0 H 0 , e 0 Γ u 0 K 0 . Then there exists u 1 H 0 , such that
J θ ( u 1 , e 0 ) = d s t ( H , K ) .
Since u 0 , u 1 H 0 , e 0 Γ u 0 , so that by Lemma 2, there exists e 1 Γ u 1 K 0 , such that
J θ ( e 0 , e 1 ) H J θ ( Γ u 0 , Γ u 1 ) + k .
Again, as e 1 K 0 , there exists u 2 H 0 , such that
J θ ( u 2 , e 1 ) = d s t ( H , K ) .
Now u 1 , u 2 H 0 , e 1 Γ u 1 , so according to Lemma 2, there exists e 2 Γ u 2 , such that
J θ ( e 1 , e 2 ) H J θ ( Γ u 1 , Γ u 2 ) + k 2 .
We continue the above process, then by induction, we find { u n : n { 0 } N } and { e n : n { 0 } N } , such that
(i)
u n H 0 , e n K 0 n { 0 } N ;
(ii)
e n Γ u n n { 0 } N ;
(iii)
J θ ( u n , e n 1 ) = d s t ( H , K ) n N ;
(iv)
J θ ( e n 1 , e n ) H J θ ( Γ u n 1 , Γ u n ) + k n n N .
Now, for any n N , we have J θ ( u n , e n 1 ) = d s t ( H , K ) and J θ ( u n + 1 , e n ) = d s t ( H , K ) . Since the pair ( H , K ) has the P J θ -property, we deduce
J θ ( u n , u n + 1 ) = J θ ( e n 1 , e n ) , n N .
Now for u = u n , e = u n + 1 , and n N by (18), we obtain
H J θ ( Γ u n , Γ u n + 1 ) k s u n J θ ( u n , u n + 1 ) n { 0 } N .
Next, for all n N , we have
J θ ( u n , u n + 1 ) = J θ ( e n 1 , e n ) H J θ ( Γ u n 1 , Γ u n ) + k n k s u n 1 J θ ( u n 1 , u n ) + k n k J θ ( u n 1 , u n ) + k n = k J θ ( e n 2 , e n 1 ) + k n k H J θ ( Γ u n 2 , Γ u n 1 ) + k n 1 + k n = k H J θ ( Γ u n 2 , Γ u n 1 ) + 2 k n k 2 s u n 2 J θ ( u n 2 , u n 1 ) + 2 k n k 2 J θ ( u n 2 , u n 1 ) + 2 k n = k 2 J θ ( e n 3 , e n 2 ) + 2 k n k 2 H J θ ( Γ u n 3 , Γ u n 2 ) + k n 2 + 2 k n = k 2 H J θ ( Γ u n 3 , Γ u n 2 ) + 3 k n k 3 s u n 3 J θ ( u n 3 , u n 2 ) + 3 k n k 3 J θ ( u n 3 , u n 2 ) + 3 k n k n J θ ( u 0 , u 1 ) + n k n .
We obtain
J θ ( u n , u n + 1 ) k n J θ ( u 0 , u 1 ) + n k n n N .
Now, for each n > m , we obtain
J θ ( u m , u n ) θ ( u m , u n ) [ J θ ( u m , u m + 1 ) + J θ ( u m + 1 , u n ) ] θ ( u m , u n ) J θ ( u m , u m + 1 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) J θ ( u m + 1 , u m + 2 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) J θ ( u m + 2 , u n ) i = m n 1 j = m i θ ( u j , u n ) J θ ( u i , u i + 1 ) i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i k i = i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + j = m i θ ( u j , u n ) i k i = i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i = m n 1 j = m i θ ( u j , u n ) i k i i = m n 1 j = 1 i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i = m n 1 j = 1 i θ ( u j , u n ) i k i = J θ ( u 0 , u 1 ) i = m n 1 j = 1 i θ ( u j , u n ) k i + i = m n 1 j = 1 i θ ( u j , u n ) i k i .
Let, a m = j = 1 m θ ( u j , u n ) k m , S m = i = 1 m j = 1 i θ ( u j , u n ) k i and a m = j = 1 m θ ( u m , u n ) m k m , S m = i = 1 m j = 1 i θ ( u j , u n ) i k i . Then lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) k < 1 , and
lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) m + 1 m k = lim m , n θ ( u m + 1 , u n ) 1 + 1 m k = lim m , n θ ( u m + 1 , u n ) k + lim m , n θ ( u m + 1 , u n ) k m < 1 + 0 .
Since lim m , n θ ( u m + 1 , u n ) is finite and lim m k m = 0 , the series i = 1 j = 1 i θ ( u j , u n ) k i and i = 1 j = 1 i θ ( u j , u n ) i k i converge by ratio test for each n N . For n > m , inequality (25) implies
J θ ( u m , u n ) J θ ( u 0 , u 1 ) [ S n 1 S m ] + S n 1 S m .
Letting m , we obtain
lim m sup n > m J θ ( u m , u n ) = 0 .
From inequalities (23) and (24), we have
lim m sup n > m J θ ( e m , e n ) = 0 .
Also lim n , m θ ( u n , u m ) < 1 k , and lim n , m θ ( e n , e m ) < 1 k . By Lemma 1, the sequence { u n : n { 0 } N } is Cauchy in H and { e n : n { 0 } N } is Cauchy in K . Since the subsets H and K are closed in the complete space ( U , ρ θ ) , there is some p in H and q in K such that u n p , e n q . Since e n Γ u n for all n { 0 } N and the multi-valued non-self mapping Γ is closed, q Γ p . Since J θ ( u n , e n 1 ) = d s t ( H , K ) and J θ is associated with ( H , K ) , we deduce that ρ θ ( p , q ) = d s t ( H , K ) . Now,
d s t ( H , K ) = ρ θ ( p , q ) D ( p , Γ p ) D ( p , K ) d s t ( H , K ) ,
Hence,
D ( p , Γ p ) = d s t ( H , K ) .
This completes the proof. □
In the following, we include our second result.
Theorem 4.
Let the space ( U , ρ θ ) be complete and the pair ( H , K ) has the P ρ θ -property. Let Γ : H 2 K be a closed multi-valued mapping that satisfies
s u H ρ θ ( Γ u , Γ e ) k ρ θ ( u , e ) ,
for all u , e U and for some 0 k < 1 with
lim n , m θ ( u n , u m ) < 1 k , lim n , m θ ( e n , e m ) < 1 k .
Here, s u = inf e Γ u θ ( u , e ) , u n H 0 and e n Γ u n , n = 0 , 1 , 2 . Let Γ u C B ( U ) ,   Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
Since every extended b-metric ρ θ is an E.b-G pseudo-distance on U , if J θ = ρ θ , then ρ θ is associated with each pair ( H , K ) , because of the continuity of ρ θ and P J θ -property becomes P ρ θ -property. Thus, all the axioms of Theorem 3 are fulfilled. Hence, there exists some p H such that D ( p , Γ p ) = d s t ( H , K ) . (The detailed proof of Theorem 4 is given in Appendix A). □
The following is another result for complete space ( U , ρ θ , J θ ) .
Theorem 5.
Let the space ( U , ρ θ , J θ ) be complete space such that J θ is associated with the pair ( H , K ) and ( H , K ) has the P J θ -property. Let Γ : H K be a non-self continuous mapping that satisfies
s u J θ ( Γ u , Γ e ) k J θ ( u , e ) ,
for all u , e H and for some 0 k < 1 with
lim n , m θ ( u n , u m ) < 1 k , lim n , m θ ( e n , e m ) < 1 k .
Here, s u = θ ( u , Γ u ) , u n H 0 , e n = Γ u n , n = 0 , 1 , 2 . Let Γ t K 0 f o r e a c h t H 0 . Then ρ θ ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
Since the contraction mapping Γ : H K is continuous, if { u n : n N } and { e n : n N } are any two sequences in H and K , respectively, such that u n p H , and e n q K , and e n = Γ u n n N , then Γ u n Γ p which implies e n Γ u . Since the limit of sequence in ( U , ρ θ ) is unique, p = Γ q . Thus, the mapping Γ is closed. All the axioms of Theorem 3 are fulfilled. Hence, there exists some p H such that D ( p , Γ p ) = d s t ( H , K ) . (The detailed proof of Theorem 5 is given in Appendix B). □
Theorem 6.
Let the space ( U , ρ θ ) be complete and the pair ( H , K ) has the P ρ θ -property. Let Γ : H K be a non-self continuous mapping that satisfies
s u ρ θ ( Γ u , Γ e ) k ρ θ ( u , e ) ,
for all u , e H , and for some 0 k < 1 with
lim n , m θ ( u n , u m ) < 1 k , lim n , m θ ( e n , e m ) < 1 k .
Here, s u = θ ( u , Γ u ) , u n H 0 and e n = Γ u n , n = 0 , 1 , 2 . Let Γ t K 0 f o r e a c h t H 0 . Then ρ θ ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting J θ = ρ θ in Theorem 5, we arrive at the desired result. (The detailed proof of Theorem 6 is given in Appendix C). □

4. Consequences and Examples

In this section, we include some important B.P. point theorems in the settings of b-m space ( U , ρ b ) and b-G pseudo-distance space ( U , ρ b , J b ) . We also furnish readers with concrete examples to validate our results.
Corollary 1.
Let the space ( U , ρ b , J b ) be complete such that J b is associated with the pair ( H , K ) and ( H , K ) has the P J b -property. Let Γ : H 2 K be a multi-valued closed mapping that satisfies
s H J b ( Γ u , Γ e ) k J b ( u , e ) ,
for all u , e H and for some 0 k < 1 with k s < 1 . Let Γ u C B ( U ) , Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting J θ = J b in Theorem 3, we arrive at the desired result. □
Corollary 2.
Let the space ( U , ρ b ) be complete and the pair ( H , K ) has the P ρ b -property. Let Γ : H 2 K be a closed multi-valued mapping that satisfies
s H ρ b ( Γ u , Γ e ) k ρ b ( u , e ) ,
for all u , e U and for some 0 k < 1 with k s < 1 . Let Γ u C B ( U ) , Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting ρ θ = d b in Theorem 4, we arrive at the desired result. □
Corollary 3.
Let the space ( U , ρ ) be complete space and the pair ( H , K ) has the P ρ -property. Let Γ : H 2 K be a closed, multi-valued mapping that satisfies
H ρ ( Γ u , Γ e ) k ρ ( u , e ) ,
for all u , e H and for some 0 k < 1 . Let Γ u C B ( U ) , Γ t K 0 f o r e a c h u H , t H 0 . Then D ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting ρ θ = ρ in Theorem 4, we arrive at the desired result. □
Corollary 4.
Let the space ( U , ρ b , J b ) be complete such that J b is associated with the pair ( H , K ) and ( H , K ) has the P J b -property. Let Γ : H K be a non-self continuous mapping that satisfies
s J b ( Γ u , Γ e ) k J b ( u , e ) ,
for all u , e H and for some 0 k < 1 with k s < 1 . Let Γ t K 0 f o r e a c h t H 0 . Then ρ b ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting J θ = J b in Theorem 5, we arrive at the desired result. □
Corollary 5.
Let the space ( U , ρ b ) be complete and the pair ( H , K ) has the P ρ b -property. Let Γ : H K be a non-self continuous mapping that satisfies
s ρ b ( Γ u , Γ e ) k ρ b ( u , e ) ,
for all u , e H and for some 0 k < 1 with k s < 1 . Let Γ t K 0 f o r e a c h t H 0 . Then ρ b ( p , Γ p ) = d s t ( H , K ) for some p H .
Proof. 
By setting ρ θ = ρ b in Theorem 6, we arrive at the desired result. □
The following example validates Theorem 3.
Example 6.
Let U = [ 0 , 1 ] with the extended b-metric ρ θ defined in Example 1. Let H = [ 0.1 , 0.2 ] , K = [ 0.3 , 0.4 ] and B = [ 0.1 , 0.125 ] [ 0.2 , 0.4 ] and J θ : U × U [ 0 , ) be defined by
J θ ( u , e ) = ρ θ ( u , e ) i f { u , e } B 110 i f { u , e } B .
Then, by Example 2, the mapping J θ is an E.b-G pseudo-distance on U . Define Γ : H 2 K as
Γ u = { 0.3 } [ 0.375 , 0.4 ] f o r u [ 0.1 , 0.125 ] [ 0.375 , 0.4 ] f o r u ( 0.125 , 0.15 ) [ 0.35 , 0.4 ] f o r u [ 0.15 , 0.175 ) [ 0.325 , 0.4 ] f o r u [ 0.175 , 0.1875 ) { 0.3 } [ 0.325 , 0.4 ] f o r u = 0.1875 { 0.4 } f o r u ( 0.1875 , 0.2 ] .
(1) 
We show that the pair ( H , K ) has the P J θ -property.
Observe that d s t ( H , K ) = 12.5 and H 0 = { 0.2 } , = { 0.4 } .
Hence, ( H , K ) has the P J θ -property.
Also, Γ ( H 0 ) = Γ ( 0.2 ) = 0.4 K 0 .
(2) 
We show that the mapping J θ is associated with ( H , K ) .
Let { u n : n N } and { e n : n N } be any two sequences in U such that lim n u n = u , lim n e n = e and
J θ ( u n , e n 1 ) = d s t ( H , K ) f o r a l l n N .
Since d s t ( H , K ) = 12.5 < 110 . By definition of J θ we have
J θ ( u n , e n 1 ) = ρ θ ( u n , e n 1 ) = d s t ( H , K ) .
By (36) and continuity of ρ θ we have ρ θ ( u , e ) = d s t ( H , K ) .
(3) 
We show that (18) holds, i.e.,
s u H J θ ( Γ u , Γ e ) k J θ ( u , e ) f o r a l l u , e H and f o r s o m e k [ 0 , 1 ) .
Let u , e H be arbitrary and fixed, and k = 1 2 [ 0 , 1 ) . By definition of Γ, we have Γ ( H ) K = [ 0.3 , 0.4 ] B . Moreover, by definition of J θ we have H J θ ( Γ u , Γ e ) 12 , for each u , e H . We discuss the following cases.
Case(a)
If { u , e } B { u , e } , then there are three possibilities.
(i) 
u B and e B .
(ii) 
u B and e B .
(iii) 
u B and e B .
If u B , then u ( 0.125 , 0.2 ) and s u 3   u ( 0.125 , 0.2 ) , J θ ( u , e ) = 110 and s u H J θ ( Γ u , Γ e ) 3 ( 12 ) 110 2 = k J θ ( u , e ) .
If u B , then u H B = [ 0.1 , 0.125 ] { 0.2 } and s u 3   u [ 0.1 , 0.125 ] { 0.2 } , J θ ( u , e ) = 110 and s u H J θ ( Γ u , Γ e ) 3 ( 12 ) 110 2 = k J θ ( u , e ) . So (37) holds.
Case(b)
If { u , e } B = { u , e } , then u , e H B = [ 0.1 , 0.125 ] { 0.2 } . Now, from the definition of Γ, we have: Γ u = Γ e u , e [ 0.1 , 0.125 ] , Γ 0.2 Γ u u [ 0.1 , 0.125 ] . Thus H J θ ( Γ u , Γ e ) = 0 for all u , e [ 0.1 , 0.125 ] { 0.2 } .
Hence, s u H J θ ( Γ u , Γ e ) = 0 k J θ u , e [ 0.1 , 0.125 ] { 0.2 } . So (37) holds.
By the definition of Γ, Γ u is closed and bounded for all u H .
(4) 
We see that p = 0.2 is a B.P. point of Γ, since D ( p , Γ p ) = ρ θ ( 0.2 , { 0.4 } ) = 12.5 = d s t ( H , K ) .

5. Concluding Remarks

We summarize our conclusion as follows.
(1)
We generalized the notion of b-G pseudo-distance J b [29] by introducing an E.b-G pseudo-distance J θ .
(2)
We gave an example of E.b-G pseudo-distance J θ which is not a b-G pseudo-distance J b in the sense of [29].
(3)
We proved B.P. point theorems for the multi-valued contraction mappings with respect to E.b-G pseudo-distance.
(4)
Our results generalized some recent results in the literature from metric spaces and b-metric spaces to E.b-m spaces.
(5)
By letting θ ( u , e ) = s for each u , e U where s 1 , Theorem 3 generalized the main result of [29] with the condition that k s < 1 (see Corollary 1).
(6)
Theorem 4 is the generalization of the main result of A. Abkar [26] from metric space to E.b-m space.
(7)
By letting θ ( u , e ) = 1 for all u , e U and ρ θ = d , Theorem 4 generalized the main result of [26] (see Corollary 3).

6. Future Scope

The research motivation in this article for the readers is that several important F. point and B.P. point results can be obtained using our newly introduced generalized distance space.

Author Contributions

Conceptualization, A.U.K. and M.S.; methodology, A.U.K. and M.S.; validation, M.S., A.H. and H.A.S.; formal analysis, A.U.K.; investigation, M.S., A.H. and H.A.S.; writing—original draft, A.U.K.; writing—review and editing, A.U.K., M.S., A.H. and H.A.S.; Supervision, M.S.; funding acquisition. A.H. and H.A.S. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

Data is contained within the article.

Acknowledgments

The third and fourth authors are grateful for the financial support provided by the King Abdulaziz University, P.O.Box 80203, Jeddah, Saudi Arabia.

Conflicts of Interest

The authors declare no conflict of interest.

Appendix A

Since, according to Remark 2, every extended b-metric is an E.b-G pseudo-distance on U , so in Theorem 4, the extended b-metric ρ θ is an E.b-G pseudo-distance on U . By replacing J θ = ρ θ in Definitions 5 and 6, we obtain
D ( u , K ) = inf e K ρ θ ( u , e ) ,
d s t ( H , K ) = inf { ρ θ ( u , e ) : u H , e K } ,
H 0 = { u H : ρ θ ( u , e ) = d s t ( H , K ) for some e K } ,
K 0 = { e K : ρ θ ( u , e ) = d s t ( H , K ) for some u H } .
H ρ θ ( H , K ) = max { sup u H ρ θ ( u , K ) , sup e K ρ θ ( e , H ) } for all H , K C B ( U ) ,
and the P J θ -property becomes P ρ θ -property of the pair ( H , K ) .
Let u 0 H 0 , e 0 Γ u 0 K 0 . Then there exists u 1 H 0 such that
ρ θ ( u 1 , e 0 ) = d s t ( H , K ) .
Since u 0 , u 1 H 0 , e 0 Γ u 0 , and ρ θ is an E.b-G pseudo-distance on U , so by Lemma 2, there exists e 1 Γ u 1 K 0 such that
ρ θ ( e 0 , e 1 ) H ρ θ ( Γ u 0 , Γ u 1 ) + k .
Again, as e 1 K 0 , so there exists u 2 H 0 such that
ρ θ ( u 2 , e 1 ) = d s t ( H , K ) .
Now u 1 , u 2 H 0 , e 1 Γ u 1 , and ρ θ is an E.b-G pseudo-distance on U , so by Lemma 2, there exists e 2 Γ u 2 such that
ρ θ ( e 1 , e 2 ) H ρ θ ( Γ u 1 , Γ u 2 ) + k 2 .
We continue the above process, then, by induction, we find { u n : n { 0 } N } , and { e n : n { 0 } N } such that
(i)
u n H 0 , e n K 0 n { 0 } N ;
(ii)
e n Γ u n n { 0 } N ;
(iii)
ρ θ ( u n , e n 1 ) = d s t ( H , K ) n N ;
(iv)
ρ θ ( e n 1 , e n ) H ρ θ ( Γ u n 1 , Γ u n ) + k n n N .
Now, for any n N , we have ρ θ ( u n , e n 1 ) = d s t ( H , K ) and ρ θ ( u n + 1 , e n ) = d s t ( H , K ) . Since the pair ( H , K ) has the P ρ θ -property, we deduce
ρ θ ( u n , u n + 1 ) = ρ θ ( e n 1 , e n ) , n N .
Now for u = u n , e = u n + 1 , and n N , by (27), we obtain
H ρ θ ( Γ u n , Γ u n + 1 ) k s u n ρ θ ( u n , u n + 1 ) n { 0 } N .
Next, for all n N , we have
ρ θ ( u n , u n + 1 ) = ρ θ ( e n 1 , e n ) H ρ θ ( Γ u n 1 , Γ u n ) + k n k s u n 1 ρ θ ( u n 1 , u n ) + k n k ρ θ ( u n 1 , u n ) + k n = k ρ θ ( e n 2 , e n 1 ) + k n k H ρ θ ( Γ u n 2 , Γ u n 1 ) + k n 1 + k n = k H ρ θ ( Γ u n 2 , Γ u n 1 ) + 2 k n k 2 s u n 2 ρ θ ( u n 2 , u n 1 ) + 2 k n k 2 ρ θ ( u n 2 , u n 1 ) + 2 k n = k 2 ρ θ ( e n 3 , e n 2 ) + 2 k n k 2 H ρ θ ( Γ u n 3 , Γ u n 2 ) + k n 2 + 2 k n = k 2 H ρ θ ( Γ u n 3 , Γ u n 2 ) + 3 k n k 3 s u n 3 ρ θ ( u n 3 , u n 2 ) + 3 k n k 3 ρ θ ( u n 3 , u n 2 ) + 3 k n k n ρ θ ( u 0 , u 1 ) + n k n .
Therefore, we obtain
ρ θ ( u n , u n + 1 ) k n ρ θ ( u 0 , u 1 ) + n k n n N .
Now, for each n > m , we obtain
ρ θ ( u m , u n ) θ ( u m , u n ) [ ρ θ ( u m , u m + 1 ) + ρ θ ( u m + 1 , u n ) ] θ ( u m , u n ) ρ θ ( u m , u m + 1 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) ρ θ ( u m + 1 , u m + 2 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) ρ θ ( u m + 2 , u n ) i = m n 1 j = m i θ ( u j , u n ) ρ θ ( u i , u i + 1 ) i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i k i = i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + j = m i θ ( u j , u n ) i k i = i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i = m n 1 j = m i θ ( u j , u n ) i k i i = m n 1 j = 1 i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i = m n 1 j = 1 i θ ( u j , u n ) i k i = ρ θ ( u 0 , u 1 ) i = m n 1 j = 1 i θ ( u j , u n ) k i + i = m n 1 j = 1 i θ ( u j , u n ) i k i .
Let a m = j = 1 m θ ( u j , u n ) k m , S m = i = 1 m j = 1 i θ ( u j , u n ) k i and a m = j = 1 m θ ( u m , u n ) m k m , S m = i = 1 m j = 1 i θ ( u j , u n ) i k i . Then lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) k < 1 , and
lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) m + 1 m k = lim m , n θ ( u m + 1 , u n ) 1 + 1 m k = lim m , n θ ( u m + 1 , u n ) k + lim m , n θ ( u m + 1 , u n ) k m < 1 + 0 .
Since lim m , n θ ( u m + 1 , u n ) is finite and lim m k m = 0 , the series i = 1 j = 1 i θ ( u j , u n ) k i and i = 1 j = 1 i θ ( u j , u n ) i k i converge by ratio test for each n N . For n > m , above inequality implies
ρ θ ( u m , u n ) ρ θ ( u 0 , u 1 ) [ S n 1 S m ] + S n 1 S m .
Letting m , we conclude
lim m sup n > m ρ θ ( u m , u n ) = 0 .
From (A12) and (A13), we have
lim m sup n > m ρ θ ( e m , e n ) = 0 .
Also lim n , m θ ( u n , u m ) < 1 k , and lim n , m θ ( e n , e m ) < 1 k . By Lemma 1, the sequence { u n : n { 0 } N } is Cauchy in H and { e n : n { 0 } N } is Cauchy in K . But since the subsets H and K are closed in the complete space ( U , ρ θ ) , there is some p in H and q in K , such that u n p , e n q . Since e n Γ u n for all n { 0 } N and the multi-valued non-self mapping Γ is closed, q Γ p . Since ρ θ ( u n , e n 1 ) = d s t ( H , K ) and ρ θ is associated with ( H , K ) , because of the continuity of ρ θ (we have chosen ρ θ to be continuous throughout), we deduce that ρ θ ( p , q ) = d s t ( H , K ) . Now,
d s t ( H , K ) = ρ θ ( p , q ) D ( p , Γ p ) D ( p , K ) d s t ( H , K ) ,
Hence,
D ( p , Γ p ) = d s t ( H , K ) .
This completes the proof.

Appendix B

Let u 0 H 0 , e 0 = Γ u 0 K 0 . Then there exists u 1 H 0 such that
J θ ( u 1 , e 0 ) = d s t ( H , K ) .
Since u 0 , u 1 H 0 , for e 0 = Γ u 0 , e 1 = Γ u 1 K 0 , for all k > 0 , we have
J θ ( e 0 , e 1 ) ρ θ ( Γ u 0 , Γ u 1 ) + k .
Again, as e 1 K 0 , so there exists u 2 H 0 such that
J θ ( u 2 , e 1 ) = d s t ( H , K ) .
Now u 1 , u 2 H 0 , for e 1 = Γ u 1 , e 2 = Γ u 2 , we have
J θ ( e 1 , e 2 ) ρ θ ( Γ u 1 , Γ u 2 ) + k 2 .
We continue the above process, then by induction, we find { u n : n { 0 } N } , and { e n : n { 0 } N } such that
(i)
u n H 0 , e n K 0 n { 0 } N ;
(ii)
e n = Γ u n n { 0 } N ;
(iii)
J θ ( u n , e n 1 ) = d s t ( H , K ) n N ;
(iv)
J θ ( e n 1 , e n ) ρ θ ( Γ u n 1 , Γ u n ) + k n n N .
Now, for any n N , we have J θ ( u n , e n 1 ) = d s t ( H , K ) and J θ ( u n + 1 , e n ) = d s t ( H , K ) . Since the pair ( H , K ) has the P J θ -property, we deduce
J θ ( u n , u n + 1 ) = J θ ( e n 1 , e n ) , n N .
Now, for u = u n , e = u n + 1 , and n N , by (28), we obtain
J θ ( Γ u n , Γ u n + 1 ) k s u n J θ ( u n , u n + 1 ) n { 0 } N .
Next, for all n N , we have
J θ ( u n , u n + 1 ) = J θ ( e n 1 , e n ) ρ θ ( Γ u n 1 , Γ u n ) + k n k s u n 1 J θ ( u n 1 , u n ) + k n k J θ ( u n 1 , u n ) + k n = k J θ ( e n 2 , e n 1 ) + k n k J θ ( Γ u n 2 , Γ u n 1 ) + k n 1 + k n = k J θ ( Γ u n 2 , Γ u n 1 ) + 2 k n k 2 s u n 2 J θ ( u n 2 , u n 1 ) + 2 k n k 2 J θ ( u n 2 , u n 1 ) + 2 k n = k 2 J θ ( e n 3 , e n 2 ) + 2 k n k 2 J θ ( Γ u n 3 , Γ u n 2 ) + k n 2 + 2 k n = k 2 J θ ( Γ u n 3 , Γ u n 2 ) + 3 k n k 3 s u n 3 J θ ( u n 3 , u n 2 ) + 3 k n k 3 J θ ( u n 3 , u n 2 ) + 3 k n k n J θ ( u 0 , u 1 ) + n k n .
So we obtain
J θ ( u n , u n + 1 ) k n J θ ( u 0 , u 1 ) + n k n n N .
Now, for each n > m , we obtain
J θ ( u m , u n ) θ ( u m , u n ) [ J θ ( u m , u m + 1 ) + J θ ( u m + 1 , u n ) ] θ ( u m , u n ) J θ ( u m , u m + 1 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) J θ ( u m + 1 , u m + 2 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) J θ ( u m + 2 , u n ) i = m n 1 j = m i θ ( u j , u n ) J θ ( u i , u i + 1 ) i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i k i = i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + j = m i θ ( u j , u n ) i k i = i = m n 1 j = m i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i = m n 1 j = m i θ ( u j , u n ) i k i i = m n 1 j = 1 i θ ( u j , u n ) k i J θ ( u 0 , u 1 ) + i = m n 1 j = 1 i θ ( u j , u n ) i k i = J θ ( u 0 , u 1 ) i = m n 1 j = 1 i θ ( u j , u n ) k i + i = m n 1 j = 1 i θ ( u j , u n ) i k i .
Let a m = j = 1 m θ ( u j , u n ) k m , S m = i = 1 m j = 1 i θ ( u j , u n ) k i and a m = j = 1 m θ ( u m , u n ) m k m , S m = i = 1 m j = 1 i θ ( u j , u n ) i k i . Then lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) k < 1 , and
lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) m + 1 m k = lim m , n θ ( u m + 1 , u n ) 1 + 1 m k = lim m , n θ ( u m + 1 , u n ) k + lim m , n θ ( u m + 1 , u n ) k m < 1 + 0 .
Since lim m , n θ ( u m + 1 , u n ) is finite and lim m k m = 0 , the series i = 1 j = 1 i θ ( u j , u n ) k i and i = 1 j = 1 i θ ( u j , u n ) i k i converge by ratio test for each n N . For n > m , above inequality implies
J θ ( u m , u n ) J θ ( u 0 , u 1 ) [ S n 1 S m ] + S n 1 S m .
Letting m , we conclude
lim m sup n > m J θ ( u m , u n ) = 0 .
From (A8) and (A9), we have
lim m sup n > m J θ ( e m , e n ) = 0 .
Also lim n , m θ ( u n , u m ) < 1 k , and lim n , m θ ( e n , e m ) < 1 k . By Lemma 1, the sequence { u n : n { 0 } N } is Cauchy in H and { e n : n { 0 } N } is Cauchy in K . But since the subsets H and K are closed in the complete space ( U , J θ ) , there is some p in H and q in K such that u n p , e n q where e n = Γ u n n N , Since the contraction mapping Γ : H K is continuous, so Γ u n Γ p which implies e n Γ p . As the limit of a sequence in ( U , ρ θ ) is unique, q = Γ p . Since J θ ( u n , e n 1 ) = d s t ( H , K ) and J θ is associated with ( H , K ) , we deduce that ρ θ ( p , q ) = d s t ( H , K ) . Now,
d s t ( H , K ) = ρ θ ( p , q ) = ρ θ ( p , Γ p )
Hence,
ρ θ ( p , Γ p ) = d s t ( H , K ) .
This completes the proof.

Appendix C

Since, by Remark 2, every extended b-metric is an E.b-G pseudo-distance on U , so in Theorem 6, the extended b-metric ρ θ is an E.b-G pseudo-distance on U . By replacing J θ = ρ θ in Definitions 5 and 6, we obtain
d s t ( H , K ) = inf { ρ θ ( u , e ) : u H , e K } ,
H 0 = { u H : ρ θ ( u , e ) = d s t ( H , K ) for some e K } ,
K 0 = { e K : ρ θ ( u , e ) = d s t ( H , K ) for some u H } ,
and the P J θ -property becomes P ρ θ -property of the pair ( H , K ) .
Let u 0 H 0 , e 0 = Γ u 0 K 0 . Then, there exists u 1 H 0 such that
ρ θ ( u 1 , e 0 ) = d s t ( H , K ) .
Since u 0 , u 1 H 0 , for e 0 = Γ u 0 , e 1 = Γ u 1 K 0 , for all k > 0 , we have
ρ θ ( e 0 , e 1 ) ρ θ ( Γ u 0 , Γ u 1 ) + k .
Again, as e 1 K 0 , so there exists u 2 H 0 , such that
ρ θ ( u 2 , e 1 ) = d s t ( H , K ) .
Now u 1 , u 2 H 0 , for e 1 = Γ u 1 , e 2 = Γ u 2 , we have
ρ θ ( e 1 , e 2 ) ρ θ ( Γ u 1 , Γ u 2 ) + k 2 .
We continue the above process; then, by induction, we find { u n : n { 0 } N } , and { e n : n { 0 } N } such that
(i)
u n H 0 , e n K 0 n { 0 } N ;
(ii)
e n = Γ u n n { 0 } N ;
(iii)
ρ θ ( u n , e n 1 ) = d s t ( H , K ) n N ;
(iv)
ρ θ ( e n 1 , e n ) ρ θ ( Γ u n 1 , Γ u n ) + k n n N .
Now, for any n N , we have J θ ( u n , e n 1 ) = d s t ( H , K ) and ρ θ ( u n + 1 , e n ) = d s t ( H , K ) . Since the pair ( H , K ) has the P ρ θ -property, we deduce
ρ θ ( u n , u n + 1 ) = ρ θ ( e n 1 , e n ) , n N .
Now for u = u n , e = u n + 1 , and n N , by (29), we obtain
ρ θ ( Γ u n , Γ u n + 1 ) k s u n ρ θ ( u n , u n + 1 ) n { 0 } N .
Next, for all n N , we have
ρ θ ( u n , u n + 1 ) = ρ θ ( e n 1 , e n ) ρ θ ( Γ u n 1 , Γ u n ) + k n k s u n 1 ρ θ ( u n 1 , u n ) + k n k ρ θ ( u n 1 , u n ) + k n = k ρ θ ( e n 2 , e n 1 ) + k n k ρ θ ( Γ u n 2 , Γ u n 1 ) + k n 1 + k n = k ρ θ ( Γ u n 2 , Γ u n 1 ) + 2 k n k 2 s u n 2 ρ θ ( u n 2 , u n 1 ) + 2 k n k 2 ρ θ ( u n 2 , u n 1 ) + 2 k n = k 2 ρ θ ( e n 3 , e n 2 ) + 2 k n k 2 ρ θ ( Γ u n 3 , Γ u n 2 ) + k n 2 + 2 k n = k 2 ρ θ ( Γ u n 3 , Γ u n 2 ) + 3 k n k 3 s u n 3 ρ θ ( u n 3 , u n 2 ) + 3 k n k 3 ρ θ ( u n 3 , u n 2 ) + 3 k n k n ρ θ ( u 0 , u 1 ) + n k n .
So we obtain
ρ θ ( u n , u n + 1 ) k n ρ θ ( u 0 , u 1 ) + n k n n N .
Now, for each n > m , we obtain
ρ θ ( u m , u n ) θ ( u m , u n ) [ ρ θ ( u m , u m + 1 ) + ρ θ ( u m + 1 , u n ) ] θ ( u m , u n ) ρ θ ( u m , u m + 1 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) ρ θ ( u m + 1 , u m + 2 ) + θ ( u m , u n ) θ ( u m + 1 , u n ) ρ θ ( u m + 2 , u n ) i = m n 1 j = m i θ ( u j , u n ) ρ θ ( u i , u i + 1 ) i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i k i = i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + j = m i θ ( u j , u n ) i k i = i = m n 1 j = m i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i = m n 1 j = m i θ ( u j , u n ) i k i i = m n 1 j = 1 i θ ( u j , u n ) k i ρ θ ( u 0 , u 1 ) + i = m n 1 j = 1 i θ ( u j , u n ) i k i = ρ θ ( u 0 , u 1 ) i = m n 1 j = 1 i θ ( u j , u n ) k i + i = m n 1 j = 1 i θ ( u j , u n ) i k i .
Let a m = j = 1 m θ ( u j , u n ) k m , S m = i = 1 m j = 1 i θ ( u j , u n ) k i and a m = j = 1 m θ ( u m , u n ) m k m , S m = i = 1 m j = 1 i θ ( u j , u n ) i k i . Then lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) k < 1 , and
lim m a m + 1 a m = lim m , n θ ( u m + 1 , u n ) m + 1 m k = lim m , n θ ( u m + 1 , u n ) 1 + 1 m k = lim m , n θ ( u m + 1 , u n ) k + lim m , n θ ( u m + 1 , u n ) k m < 1 + 0 .
Since lim m , n θ ( u m + 1 , u n ) is finite and lim m k m = 0 , the series i = 1 j = 1 i θ ( u j , u n ) k i and i = 1 j = 1 i θ ( u j , u n ) i k i converge by ratio test for each n N . For n > m , above inequality implies
ρ θ ( u m , u n ) ρ θ ( u 0 , u 1 ) [ S n 1 S m ] + S n 1 S m .
Letting m , we conclude
lim m sup n > m ρ θ ( u m , u n ) = 0 .
From (A19) and (A20), we have
lim m sup n > m ρ θ ( e m , e n ) = 0 .
Also lim n , m θ ( u n , u m ) < 1 k , and lim n , m θ ( e n , e m ) < 1 k . By Lemma 1, the sequence { u n : n { 0 } N } is Cauchy in H and { e n : n { 0 } N } is Cauchy in K .
But since the subsets H and K are closed in the complete space ( U , J θ ) , there is some p in H and q in K such that u n p , e n q where e n = Γ u n n N , Since the contraction mapping Γ : H K is continuous, so Γ u n Γ p which implies e n Γ p . As the limit of a sequence in ( U , ρ θ ) is unique, q = Γ p . Since ρ θ ( u n , e n 1 ) = d s t ( H , K ) and ρ θ is associated with ( H , K ) , because of the continuity of ρ θ (we have chosen ρ θ to be continuous throughout), we deduce that ρ θ ( p , q ) = d s t ( H , K ) . Now,
d s t ( H , K ) = ρ θ ( p , q ) = ρ θ ( p , Γ p )
Hence,
ρ θ ( p , Γ p ) = d s t ( H , K ) .
This completes the proof.

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Khan, A.U.; Samreen, M.; Hussain, A.; Sulami, H.A. Best Proximity Point Results for Multi-Valued Mappings in Generalized Metric Structure. Symmetry 2024, 16, 502. https://doi.org/10.3390/sym16040502

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Khan AU, Samreen M, Hussain A, Sulami HA. Best Proximity Point Results for Multi-Valued Mappings in Generalized Metric Structure. Symmetry. 2024; 16(4):502. https://doi.org/10.3390/sym16040502

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Khan, Asad Ullah, Maria Samreen, Aftab Hussain, and Hamed Al Sulami. 2024. "Best Proximity Point Results for Multi-Valued Mappings in Generalized Metric Structure" Symmetry 16, no. 4: 502. https://doi.org/10.3390/sym16040502

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