1. Introduction
The concept of cone metric space was introduced by Huang and Zhang [
1] as a generalization of a metric space, proving that Banach’s contraction theorem remains valid in this context. Afterwards, many authors have obtained fixed point results on cone metric spaces: Radenović and Rhoades [
2], Rezapour and Hamlbarani [
3], Kadelburg et al. [
4], Du [
5] and the references therein. Further, Liu and Xu [
6] introduced the concept of cone metric space over a Banach algebra and proved some fixed point theorems for Lipschitz mappings. Later on, Xu and Radenović [
7] extended the results of Liu and Xu [
6], without the assumption of normality of the cone involved. Also, generalizations of Banach’s theorem have been obtained in other directions. Wardowski [
8] defined the class of 
F-contractions and proved a fixed point result as a extension of Banach contraction principle. After this, Wardowski and Van Dung [
9] introduced the concept of 
F-weak contraction and obtained a new fixed point theorem. Cosentino and Vetro [
10] obtained new fixed point theorems of Hardy-Rogers type for 
F-contractions in ordered metric spaces. Other results concerning 
F-contractions have been obtained by: Piri and Kumam [
11], Minak et al. [
12], Ahmad et al. [
13], Kadelburg and Radenović [
14], Dey et al. [
15], Wardowski [
16], Alfaqih et al. [
17], Karapinar et al. [
18] and the references therein.
Regarding the fractional differentiation and integration, many models have been proposed in the literature: the Riemann–Liouville fractional model [
19], the Caputo model [
20], the Atangana–Baleanu (or AB) fractional model [
21,
22], the generalised proportional fractional (or GPF) model [
23], the Prabhakar fractional model [
24,
25], and others. Fernandez et al. [
26] proposed a unified model of fractional calculus by using a general operator which includes many types of fractional operators. They consider some fractional differential equations and solve a general Cauchy problem in this new framework. Important results on nonlinear fractional differential equations were obtained by Agarwal et al. [
27,
28], Soradi-Zeid et al. [
29], Almeida [
30], Khan et al. [
31], Keten et al. [
32] and the references therein.
In this article, we generalize the notion of cone metric space for topological left module and we define the concept of F-contraction on this new space. Next, we obtain some fixed point results for self-mappings satisfying a contractive condition of this type. In the last part of the article, some applications of the main result to the study of the existence and uniqueness of the solutions for integral equations were presented, one of them being an integral equation of fractional type.
  2. Methods
We will start by presenting some notions relating to ordered topological rings and topological left modules. For more details see the papers Warner [
33].
Definition 1. A ring  is called a topological ring if the set  is endowed with a topology  such that the mappings , ,  are continuous, where  is considered with respect to the product topology.
We denote by  a topological ring.
 Definition 2. Let  be a ring and let ⪯ be a partial order relation on .  is called a partially ordered ring if it fulfills the following conditions:
- (i) 
- if , , then ; 
- (ii) 
- if , , , then . 
We denote by  a partially ordered ring.
The set  is named the positive cone of .
A partially ordered topological ring and is denoted by .
 Definition 3. Let  be a ring. A left -module consists of an abelian group  and a mapping  satisfying the following properties:
- (1) 
- if , , then ; 
- (2) 
- if , , then ; 
- (3) 
- if , , then ; 
- (4) 
- if , then . 
A left -module is denoted by .
 Definition 4. Let  be a topological ring. A left A-module  is called a topological left A-module if on E is specified a topology  such that the mappings , ,  are continuous, where  and  are considered with respect to the product topologies, respectively.
A topological left -module is denoted by .
A topological left -module, , where  is a Hausdorff topology, is called a Hausdorff topological left -module.
   3. Results
Definition 5. Let  be a partially ordered topological ring and  a topological left -module. A cone is a non-empty subset P of E satisfying the conditions:
- (1) 
-  and ; 
- (2) 
- P is closed; 
- (3)
-  for all , . 
The cone P is solid if .
We define the set .
 Lemma 1. Let  be a partially ordered topological ring, with ,  a topological left -module and P a solid cone of E. Then, the following statements are valid:
- (i) 
- ; 
- (ii) 
- the relation  over E, defined by  if and only if , is a partial order relation on E; 
- (iii) 
- if  and , then , for all ; 
- (iv) 
- if  and , then , for all . 
 Lemma 2. Let  be a partially ordered topological ring,  a topological left -module and P a solid cone of E. Then, the following statements are valid:
- (i) 
- (ii) 
- ; 
- (iii) 
- assuming that  is a Hausdorff topology,  is an accumulation point of  and  for all , if  for all , then ; 
- (iv) 
- if , , , , and there is a number  such that  for all , then . 
 Definition 6. Let  be a partially ordered topological ring,  a topological left -module, P a solid cone of E and X a non-empty set. A cone metric on X is an application  which fulfills the conditions:
- (1) 
-  for all ; 
- (2) 
-  if and only if ; 
- (3) 
-  for all ; 
- (4) 
-  for all . 
 is called a cone metric space over the topological left -module.
 Definition 7. Let  be a partially ordered topological ring,  a topological left -module, P a solid cone of E and  a cone metric space over the topological left -module.
- (1) 
- A sequence  is called convergent to a point  if it has the property: for every  there is a number  such that for all  we have ; we also say that  converges to  and we denote by ; 
- (2) 
- A sequence  is named a Cauchy sequence if it satisfies the condition: for every  there is a number  such that for all  we have ; 
- (3) 
- The cone metric space  is called complete if: any Cauchy sequence of points in X is convergent in X. 
 Lemma 3. Let  be a partially ordered Hausdorff topological ring, with ,  an accumulation point of ,  a topological left -module, P a solid cone of E, with  for all , and  a cone metric space over the topological left -module. If the sequence  is convergent in X, then it has a unique limit.
 Definition 8. Let  be a topological space. A subset S of E is called sequentially compact if any sequence in S has a convergent subsequence in S.
 Lemma 4. Let  be a partially ordered topological ring, with ,  a Hausdorff topological left -module, P a solid cone of E and  a cone metric space over the topological left -module. If  is not a Cauchy sequence and there is a sequentially compact subset  having the property , then the following statements are valid:
- (i) 
- there exist  and two subsequences , , where  are strictly increasing functions, with  for all , such that 
- (ii) 
- moreover, if , there exists a point  such that 
 Proof.  (i) Since 
 is not a Cauchy sequence, we deduce that there is 
 and two subsequences 
, 
, where 
 are strictly increasing functions, with 
 for all 
, such that 
 for all 
. For every 
 we choose 
 to be the smallest integer 
 which verifies 
 and 
, thus 
. Hence, there exist 
 and two subsequences 
, 
, where 
 are strictly increasing functions, with 
 for all 
, such that
        
As 
 is sequentially compact, any sequence in 
 has a convergent subsequence in 
. According to the hypothesis we have 
. Therefore, for the sequence 
 there is a subsequence 
, where 
 is a strictly increasing function, with 
 for all 
, such that
        
Similarly, for the sequence 
 there exists a subsequence 
, where 
 is a strictly increasing function, with 
 for all 
, such that
        
Applying the statement (
1) for 
, 
, it follows that there exist 
 and two subsequences 
, 
, where 
, 
, 
 are strictly increasing functions, with 
 for all 
, such that 
, 
 for all 
.
(ii) As  is a Hausdorff topology, every convergent sequence in E has a unique limit in E.
Considering (i) we get 
 for all 
, hence 
 for all 
. Since 
 represents the sequence 
 which is a subsequence of 
 and taking into account that 
 (according to the relation (
2)), we deduce 
. We find 
. Therefore, 
(
 is an open set, hence 
 is a closed set). Taking into account the properties of the cone metric 
d, the statement (i) and using Lemma 1 (iii) we obtain
        
        thus
        
As  is a subsequence of  and  we deduce ; also, . Therefore, . It follows that , hence . Consequently, there exists a point  such that , thus , so .
The properties of the cone metric 
d leads to
        
        and
        
Since 
 represents the sequence 
 and 
 (according to the relation (
3)), we find 
. Also, 
, 
 are subsequences of 
 and 
, hence 
; moreover, 
. Passing to the limit for the sequences in relations (
4), (
5), we obtain 
 and 
, thus 
, so 
.
As  and , it follows that  (P being a closed set).
Consequently, we proved that there exists a point  such that ,  and .    □
 In the following, we define the operation
      
Definition 9. Let  be a partially ordered topological ring,  a topological left -module and P a solid cone of E. A sequence  is called:
- (1) 
- an increasing sequence if  for all ; 
- (2) 
- a decreasing sequence if  for all . 
 Definition 10. Let  be a topological space, S a subset of E and  a function.
- (1) 
- F is sequentially continuous at a point  if: for every sequence  convergent to x, the sequence  is convergent to ; 
- (2) 
- F is named sequentially continuous on S if: it is sequentially continuous at every point . 
 Definition 11. Let  be a partially ordered topological ring,  a topological left -module and P a solid cone of E. We consider the set  of all functions  which fulfill the conditions:
- (1) 
- if , , then for every  there is a number  such that for all  we have ; 
- (2) 
- if  is a decreasing sequence and for every  there is a number  such that for all  we have , then ; 
- (3) 
- if , , then ; 
- (4) 
- F is sequentially continuous on . 
 Definition 12. Let  be a partially ordered topological ring,  a topological left -module, P a solid cone of E and  a cone metric space over the topological left -module. An F-contraction corresponding to the function class  is a mapping  for which there exist  and a function  such that  Remark 1. The condition  from the property (6) implies . Hence,  whenever . Therefore, the function  is defined for every  satisfying the condition .  Theorem 1. Let  be a partially ordered Hausdorff topological ring, with ,  an accumulation point of ,  a Hausdorff topological left -module, P a solid cone of E, with  for all , , and  a cone metric space over the topological left -module. We suppose that  is complete,  is an F-contraction corresponding to the function class  and for every  we consider the sequence  defined by  for all . If for any  for which  is not a Cauchy sequence, there is a sequentially compact subset  having the property , then T has a unique fixed point  and for every  the sequence  converges to .
 Proof.  Let us suppose that 
T has two distinct fixed points, so there exist 
 such that 
. Because 
 is an 
F-contraction corresponding to the function class 
 we deduce that there exist 
 and a function 
 such that the property (
6) is verified. Applying this property we get 
, thus 
, so 
, hence 
. It follows that 
. On the other hand, 
 (according to Lemma 2 (i)), consequently 
, which is in contradiction with 
. Therefore, 
T has at most one fixed point.
We choose  be an arbitrary element and let us define the sequence  by the recurrence relation  for all . To prove the existence of a fixed point of the operator T we distinguish the following cases:
I: there is  such that . We deduce , thus  is a fixed point of T. Considering that T has at most one fixed point, we get  is the unique fixed point of T. Moreover,  for all , which means that the sequence  converges to .
II: 
 for all 
. Let us consider 
 be an arbitrary element. Using the property (
6) we find 
, 
, thus 
, 
. Following Lemma 1 (iv) we deduce 
, thus 
. Therefore, we get
        
On the other hand, 
, hence from Definition 11 (1) we obtain for every 
 there is a number 
 such that for all 
 we have 
. Consequently, from the previous affirmation and using the property (
7), via Lemma 1 (iii) we find:
for every 
 there is a number 
 such that for all 
 we have
        
Let us consider 
 be an arbitrary number. Using the property (
6) we get 
, so 
. Since 
 it follows that 
. As 
, from Definition 11 (3) we obtain 
, thus 
 is a decreasing sequence. Considering Definition 11 (2) and the property (
8), we deduce 
, so 
. In the following, we prove that 
 is a Cauchy sequence. Let us suppose that 
 is not a Cauchy sequence. Since for 
 for which 
 is not a Cauchy sequence, there is a sequentially compact subset 
 having the property 
 and considering 
, using Lemma 4 (i), (ii) we deduce there exist 
, two subsequences 
, 
, where 
 are strictly increasing functions, with 
 for all 
, and a point 
 such that
        
As 
, 
 and according to Lemma 2 (ii), 
, we get 
. Considering relation (
9), it follows that there is a number 
 such that 
 for all 
, hence 
 for all 
. Using the property (
6) we find 
 for all 
, hence
        
On the other hand, as 
, from Definition 11 (4) we have 
F is sequentially continuous on 
, hence 
F is sequentially continuous at 
. Considering the property (
9) we obtain
        
Passing to the limit in inequality (
10) and considering the relation (
11), we deduce 
, thus 
, so 
. It follows that 
. On the other hand, 
 (according to Lemma 2 (i)), therefore 
 which is in contradiction with 
. Consequently, 
 is a Cauchy sequence. Since 
 is a complete cone metric space, we deduce that there exists an element 
 such that the sequence 
 converges to 
.
Further, we show that  is a fixed point of T. For this, we consider the set  and we distinguish the following subcases:
II.1: U is an infinite set. We can choose a subsequence  of , where  is a strictly increasing function, with  for all , such that  converges to . However, we show that the sequence  converges to . Considering Lemma 3 we obtain that the sequence  has a unique limit, hence , so  is a fixed point of T.
II.2: 
H is a finite set. We find that there exists a number 
 such that 
 for all 
. Let us consider 
 be an arbitrary element. Using the property (
6) we obtain 
, thus 
. Since 
 it follows that 
. As 
, from Definition 11 (3) we obtain
        
Further, the properties of the cone metric 
d lead to
        
Taking into account the relations (
12), (
13) we get
        
We choose 
 be an arbitrary element. Since 
 converges to 
, we deduce that there is a number 
 such that for all 
 we have 
. It follows that
        
Let us consider 
 to be a natural number. Using the relations (
14), (
15) and taking into account Lemma 1 (iii) we obtain
        
Therefore,  and  for all . Applying Lemma 2 (iii) it follows that , thus , hence  is a fixed point of T.
Consequently, in both subcases II.1 and II.2 we showed that  is a fixed point of T. Considering that T has at most one fixed point, we obtain that  is the unique fixed point of T. Also, we proved that  converges to .    □
 Corollary 1. Let  be a partially ordered Hausdorff topological ring, with ,  an accumulation point of ,  a Hausdorff topological left -module, P a solid cone of E, with  for all , , and  a cone metric space over the topological left -module. We suppose that  is complete,  is an F-contraction corresponding to the function class  and for every  we consider the sequence  defined by  for all . If there is a sequentially compact subset  having the property , then T has a unique fixed point  and for every  the sequence  converges to .
 Proof.  Let  for which  is not a Cauchy sequence, be an arbitrary element. Because for every , we have , it follows that . According to the hypothesis, there is a sequentially compact subset  having the property , hence . Therefore, for any  for which  is not a Cauchy sequence, there is a sequentially compact subset  having the property . Consequently, the hypotheses of Theorem 1 are fulfilled, hence T has a unique fixed point  and for every  the sequence  converges to .    □
 In the following, we determine some conditions for the existence and uniqueness of a solution of the following integral equation
      
      where 
, 
, 
, by using Corollary 1.
Theorem 2. If the functions ,  are continuous and there is  such thatfor all , , , then the integral Equation (16) has a unique solution in .  Proof.  Let 
 be the partially ordered Hausdorff topological ring and 
 the Hausdorff topological left 
-module, where 
 is the Euclidean topology. We consider the solid cone 
, with 
. We define the set 
 and the mapping
        
        where 
, 
. We remark that 
 is a complete cone metric space over the topological left 
-module. Next, we consider the function
        
        which belongs to the class 
.
Since the functions 
 and 
 are continuous, we can define the operator 
,
        
A function 
 is a solution of the integral Equation (
16) if and only if it is a fixed point of the operator 
T.
Let , , , be arbitrary elements.
The definition of the operator 
T leads to
        
Considering the hypothesis we find
        
        thus
        
From the previous relations we deduce that
        
        hence
        
        so
        
        thus
        
        i.e.,
        
It follows that, for every 
, 
, we have
        
        thus
        
Considering the relation (
19), we find
        
        hence the operator 
 is an 
F-contraction corresponding to the function class 
.
Moreover, from the relation (
21) we deduce
        
        thus there is a sequentially compact subset 
 having the property 
.
Consequently, the hypotheses of Corollary 1 are satisfied, hence the operator 
T has a unique fixed point 
. Further, for every 
 the sequence 
, defined by 
 for all 
, converges to 
. It follows that the integral Equation (
16) has a unique solution in 
.    □
 In the sequel, we will apply Corollary 1 to a fractional integral equation. Following the study of Fernandez et al. [
26] we consider 
 a real interval, 
, 
, 
 satisfying 
 and 
A a real analytic function on the interval 
, defined by the locally uniformly convergent power series
      
      where 
, 
, are real coefficients.
Next, we determine some conditions for the existence and uniqueness of a solution of the following fractional integral equation
      
      where 
, 
, 
, 
, by using Corollary 1.
Considering the fractional integral operator 
,
      
      defined by Fernandez et al. [
26], the above fractional integral equation can be rewritten as
      
Theorem 3. If the functions ,  are continuous and there is  such thatfor all , , then the fractional integral Equation (23) has a unique solution in .  Proof.  We consider 
 the partially ordered Hausdorff topological ring and 
 the Hausdorff topological left 
-module, where 
 is the Euclidean topology. Let 
 be the solid cone, with 
. We define the set 
 and the mapping
        
We remark that 
 is a complete cone metric space over the topological left 
-module. Moreover, the function
        
        belongs to the class 
.
As the functions 
 and 
 are continuous, we can define the operator 
,
        
A function 
 is a solution of the integral Equation (
23) if and only if it is a fixed point of the operator 
T.
Considering the relation (
26) we can easily prove that
        
Therefore,
        
        and taking into account the relation (
28) we deduce
        
        hence the operator 
 is an 
F-contraction corresponding to the function class 
.
Moreover, from the relation (
30) we obtain
        
        thus there exists a sequentially compact subset 
 having the property 
.
Consequently, the hypotheses of Corollary 1 are satisfied, hence the operator 
T has a unique fixed point 
. Further, for every 
 the sequence 
, defined by 
 for all 
, converges to 
. It follows that, the integral Equation (
23) has a unique solution in 
.    □
 Remark 2. A sufficient condition for fulfilling the inequality (26) isfor all , , where .  Example 1. For , , the fractional integral operator  becomes the original Riemann–Liouville fractional integral operator (RL integral operator)If the functions ,  are continuous and there is  such thatfor all , , then the fractional integral equationhas a unique solution in . A sufficient condition for fulfilling the inequality (33) isfor all , .  Example 2. For , , the fractional integral operator  becomes the generalized proportional fractional integral operator (GPF integral operator)If the functions ,  are continuous and there is  such thatfor all , , then the fractional integral equationhas a unique solution in . A sufficient condition for fulfilling the inequality (37) isfor all , .