Abstract
This paper studies a new class of fractional differential inclusions involving two Caputo fractional derivatives of different orders and a Riemann–Liouville type integral nonlinearity, supplemented with a combination of fixed and nonlocal (dual) anti-periodic boundary conditions. The existence results for the given problem are obtained for convex and non-convex cases of the multi-valued map by applying the standard tools of the fixed point theory. Examples illustrating the obtained results are presented.
Keywords:
fractional differential inclusion; caputo derivative; Riemann–Liouville integral; nonlocal boundary conditions; anti-periodic boundary conditions; existence; fixed point theorem MSC:
34A08; 34B10; 34B15; 34A60
1. Introduction
The tools of fractional calculus significantly improved the mathematical modeling of many real world phenomena in viscoelastic materials [1], transport processes [2], economic processes [3,4], etc. Inspired by widespread applications of fractional calculus, many researchers turned to the area of fractional order boundary value problems, for example, see the monograph [5] and the articles [6,7,8,9,10,11,12]. Anti-periodic fractional order boundary value problems also received considerable attention, for instance, see a survey paper [13] and the references cited therein.
Differential inclusions play an important role in the study of dynamical systems and stochastic processes ([14,15,16]). One can find the useful application of this concept in queuing networks, finance, climate control, etc. [17]. Concerning the recent studies on differential inclusions of fractional order, we refer the reader to the articles [18,19,20,21,22,23,24,25,26,27].
Recently, in [28], the authors introduced and studied a new class of boundary value problems involving dual anti-periodic boundary conditions of the form:
where denotes the Caputo fractional differential operator of order , and are real numbers, is the Riemann–Liouville fractional integral, are given continuous functions, and
The objective of this paper is to investigate the inclusions variant of the problem (1) given by
where is a given multivalued map, ( is the family of all nonempty subsets of ) and the other quantities are the same as defined in (1).
Notice that (2) deals with both single-valued map g and multi-valued map On the other hand the boundary conditions (3) describe the anti-periodicity of the unknown function (solution of the problem) at the end points and and at a pair of arbitrary interior points and in the interval . These boundary conditions can be interpreted as a combination of fixed and nonlocal anti-periodic boundary conditions. In case of convex-valued multi-valued map the existence result for the problem (2)–(3) is proved by applying the Leray–Schauder nonlinear alternative for multivalued maps, while the case of non-convex valued multi-valued map is dealt with the aid of Covitz and Nadler fixed point theorem for contractive maps. Though we use the standard fixed point theorems to obtain the main results for the problem at hand, yet their exposition enrich the literature on anti-periodic fractional order nonlinear boundary value problems.
2. Basic Result
Before presenting an auxiliary lemma, let us recall some related definitions of fractional calculus [29].
Definition 1.
The Riemann–Liouville fractional integral of order for a function existing almost everywhere on is defined by
where Γ denotes the Euler gamma function.
Definition 2.
Let Then the Riemann–Liouville fractional derivative of order existing almost everywhere on is defined as
The Caputo fractional derivative of order is defined as
Remark 1.
If then the Caputo fractional derivative of order existing almost everywhere on is defined as
In passing we remark that the fractional integral and derivative operators and are respectively written as and for the sake of convenience.
Now we recall the following known lemma [28] that we need to study the problem (2)–(3).
Lemma 1.
For , the linear fractional integro-differential equation
subject to the boundary conditions (3) is equivalent to the integral equation:
where
and it is assumed that with
3. Existence Results
Let denote the Banach space of all continuous functions from endowed with sup-norm .
Definition 3.
A function is said to be a solution of the problem (2)–(3) if there exists a function with for a.e. such that y satisfies the differential equation on and the boundary conditions (3).
In the forthcoming analysis, we use the following notation:
where , , , .
3.1. The Upper Semicontinuous Case
Let us begin this section by defining some spaces related to our work as follows: and
Our first existence result for the problem (2)–(3) deals with the convex valued multi-valued map and relies on the following Leray–Schauder nonlinear alternative.
Lemma 2
(Nonlinear alternative for Kakutani maps [30]). Let C be a closed convex subset of a Banach space E and U be an open subset of C with Suppose that is an upper semicontinuous compact map. Then either G has a fixed point in or there is an element such that with
Theorem 1.
Assume that:
- has convex, compact values and is -Carathéodory, that is, (i) is measurable for each ; (ii) is upper semicontinuous for almost all (iii) for each , there exists such thatfor all with and for a.e.
- there exists a function and a continuous nondecreasing function such that
- there exists a constant such that
Then there exists at least one solution on for the boundary value problem (2)–(3).
Proof.
We transform the problem (2)–(3) into a fixed point problem by introducing a multi-valued operator as
where In order to establish that the problem (2)–(3) has a solution, we need to show that the operator satisfies the hypothesis of Lemma 2. We first show that is convex for each
Let Then, there exist such that for each , we have
Letting for each , we have
Consequently since has convex values. Next we show that maps in bounded sets into bounded sets. Let be a bounded set in for a positive number Then for each there exists such that
Then, for we have
and consequently
Now we demonstrate that maps bounded sets into equicontinuous sets of For and for each we have
Clearly the right hand of the above inequality tends to zero independently of as . Hence is completely continuous, by Arzelá-Ascoli theorem.
Next we show that the operator is upper semicontinuous. It is enough to establish that has a closed graph, because from (Proposition 1.2 [31]) we know that if an operator is completely continuous and has a closed graph, then it is upper semi-continuous.
Let , and . We need to show that . Now implies that there exists such that for each ,
Hence it is enough to prove that there exists such that for each ,
Consider the linear operator given by
Observe that as and thus, it follows from a closed graph lemma [32], that is a closed graph operator. Moreover, we have
Since , the closed graph lemma [32] implies that
for some
In the final step we demonstrate that there exists an open set with for any and all Let for some Let and Then there exists with such that, for , we have
Following the computation above, when proving that maps bounded sets into bounded sets, we have for each
or
Consequently, we have
By , there exists such that . Let us set
Notice that the operator is a compact, upper semicontunuous multi-valued map with convex closed values. There is no such that for some , by the choice of Consequently, we deduce that has a fixed point by the nonlinear alternative of Leray–Schauder type (Lemma 2), which is a solution of the boundary value problem (2)–(3). The proof is completed. □
Theorem 2.
Assume that and hold. In addition, we suppose that:
- There exists a positive constant L such that
- there exists a constant such thatwhere
Then there exists at least one solution on for the boundary value problem (2)–(3).
Proof.
Note that implies
The rest of the proof is similar to that of Theorem 1 and is omitted. □
3.2. The Lipschitz Case
An existence result for the boundary value problem (2)–(3) is proved in this subsection, in the case when has nonconvex values, by applying a fixed point theorem for multivalued contractive maps due to Covitz and Nadler [33].
Let be a metric space induced from the normed space . Consider given by
where and . Then is a metric space (see [34]).
Definition 4.
A multivalued operator is called
- Lipschitz if and only if there exists such that
- a contraction if and only if it is Lipschitz with .
In the next lemma we denote by the fixed point set of the multivalued operator
Lemma 3
(Covitz and Nadler [33]). Let be a complete metric space. If is a contraction, then .
Theorem 3.
Assume that and the following conditions hold:
- is such that is measurable for each .
- for almost all and with and for almost all .
Then the boundary value problem (2)–(3) has at least one solution on if
Proof.
Consider the operator defined in Theorem 1 at the beginning of the proof. We show that the operator fulfills the assumptions of Lemma 3. Note that since the set-valued map is measurable by the measurable selection theorem (e.g., (Theorem III.6 [35])) and it admits a measurable selection . Moreover, by the assumption we have
i.e., and hence is integrably bounded. Therefore, . Moreover for each .
Let be such that in Then and there exists such that, for each ,
As has compact values, we pass onto a subsequence (if necessary) to obtain that converges to v in Thus and for each , we have
Hence,
Next we show that there exists such that
Let and . Then there exists such that, for each ,
By , we have
Therefore there exists such that
Define by
Since is measurable (Proposition III.4 [35]), there exists a function which is a measurable selection for U. Hence and for each , we have .
For each , let us define
Thus,
Hence
Interchanging the roles of y and , we obtain
Since is a contraction, it follows by Lemma 3 that has a fixed point x which is a solution of (2)–(3). This completes the proof. □
4. Examples
Consider the following boundary value problem:
where As defined in the problem (2)–(3), we take Using the given data, we find that , and . Moreover, . Using the condition , we find that Clearly the hypothesis of Theorem 1 is satisfied. Therefore, there exists at least one solution for the problem (11) on .
In order to illustrate Theorem 3, we take
and as defined in the problem (2)–(3), we choose
Clearly is measurable for all and that
5. Conclusions
We have discussed the existence of solutions for fractional differential inclusions involving two Caputo fractional derivatives of different orders and a Riemann–Liouville type integral nonlinearity, equipped with a new class of anti-periodic boundary conditions. In case of convex-valued case, we make use of the Leray–Schauder nonlinear alternative for multivalued maps to derive the existence result for the problem at hand, while the case of non-convex multi-valued map relies on Covitz and Nadler fixed point theorem for contractive maps. In the given configuration, our results are new and contribute to the existing literature on the topic. Moreover, by taking in the obtained results, we get the ones for the following multi-valued problem:
which are indeed new.
Author Contributions
Conceptualization, B.A.; Formal analysis, A.A., R.P.A., S.K.N. and B.A.; Funding acquisition, A.A.; Methodology, A.A., R.P.A., S.K.N. and B.A. All authors have read and agreed to the published version of the manuscript.
Funding
The Deanship of Scientific Research (DSR) at King Abdulaziz University, Jeddah, Saudi Arabia funded this project, under grant no. FP-17-42.
Acknowledgments
The Deanship of Scientific Research (DSR) at King Abdulaziz University, Jeddah, Saudi Arabia funded this project, under grant no. FP-17-42. The authors, therefore, acknowledge with thanks DSR technical and financial support. We also thank the reviewers for their useful remarks on our work.
Conflicts of Interest
The authors declare no conflict of interest.
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