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27 September 2021

Generalizations of the Jensen–Mercer Inequality via Fink’s Identity

Faculty of Electrical Engineering, Mechanical Engineering and Naval Architecture, University of Split, Ruđera Boškovića 32, 21000 Split, Croatia

Abstract

We generalize an integral Jensen–Mercer inequality to the class of n-convex functions using Fink’s identity and Green’s functions. We study the monotonicity of some linear functionals constructed from the obtained inequalities using the definition of n-convex functions at a point.

1. Introduction

Jensen’s inequality,
f 1 W n i = 1 n w i x i 1 W n i = 1 n w i f x i ,
for a convex function f : I R , real numbers x 1 , , x n I and positive real numbers w 1 , , w n , where W n = i = 1 n w i , is one of the most important inequalities in many areas of mathematics and other areas of science. Many other inequalities can be derived from it and there are numerous of its variants, generalizations and refinements (see, for example [1,2]). One of these variants is the so-called Jensen–Mercer inequality,
f α + β 1 W n i = 1 n w i x i f α + f β 1 W n i = 1 n w i f x i ,
for a convex function f : α , β R , real numbers x 1 , , x n α , β and positive real numbers w 1 , , w n , which was introduced in [3] by A. McD. Mercer. It has been a main topic of our research (see, e.g., [4,5,6,7]) in different settings and for different classes of functions.
In the paper [8], we proved the following integral version.
Theorem 1.
Let g : a , b R be a continuous and monotonic function and α , β be an interval such that g a , b α , β . Let the function λ : a , b R be either continuous or of bounded variation, and satisfying
λ a λ t λ b f o r a l l t α , β , λ b λ a > 0 .
Then, for every continuous convex function φ : α , β R the inequality
φ α + β a b g x d λ x a b d λ x φ α + φ β a b φ g x d λ x a b d λ x
holds. If φ is concave, then the reversed inequality (4) holds.
Remark 1.
Theorem 1 is also valid when the condition (3) is replaced with the more strict condition that λ is a nondecreasing function such that λ a λ b .
The main goal of this paper is to present generalizations of inequality (4) to the class of n-convex functions. We achieve this by means of Fink’s identity and Green’s functions, which we introduce below.
A real-valued function φ defined on an interval α , β is called n-convex if its nth order divided differences are nonnegative for all choices of n + 1 distinct points in α , β . Thus, 0-convex functions are nonnegative functions, 1-convex functions are increasing functions and 2-convex functions are convex functions. An n-convex function need not be n-times differentiable, however, if φ n exists then φ is n-convex if and only if φ n 0 . For more information about n-convex functions, see [9] and also [2].
Fink’s identity [10],
φ s = n β α α β φ t d t k = 1 n 1 n k k ! · φ k 1 α s α k φ k 1 β s β k β α + 1 n 1 ! β α α β s t n 1 K t , s φ n t d t ,
with
K t , s = t α for   α t s β , t β for   α s < t β ,
holds for every function φ : α , β R such that φ n 1 is absolutely continuous on α , β for some n 1 . For n = 1 , we take the sum in (5) to be zero.
We consider Green’s functions G i , i = 1 , , 5 defined on α , β × α , β by
G 1 t , s = α s for   s t , α t for   t s ,
G 2 t , s = t β for   s t , s β for   t s ,
G 3 t , s = t α for   s t , s α for   t s ,
G 4 t , s = β s for   s t , β t for   t s ,
and
G 5 t , s = t β s α β α for   s t , s β t α β α for   t s .
All five Green’s functions are continuous, symmetric and convex with respect to both the variables s and t.
It can be easily shown by integrating by parts that every function φ : α , β R , φ C 2 α , β can be represented in the following five forms. If x α , β , then
φ x = φ α + x α φ β + α β G 1 x , s φ s d s ,
φ x = φ β + x β φ α + α β G 2 x , s φ s d s ,
φ x = φ β β α φ β + x α φ α + α β G 3 x , s φ s d s ,
φ x = φ α + β α φ α β x φ β + α β G 4 x , s φ s d s ,
φ x = β x β α φ α + x α β α φ β + α β G 5 x , s φ s d s .
By easy calculation (see [11,12]), using representations (12)–(16), we can obtain the identity
φ α + φ β a b φ g x d λ x a b d λ x φ α + β a b g x d λ x a b d λ x = α β G i α , s + G i β , s a b G i g x , s d λ x a b d λ x G i α + β a b g x d λ x a b d λ x , s φ s d s ,
for all i = 1 , , 5 . In the rest of the paper, for the sake of simplicity, let us denote
x ¯ = a b g x d λ x a b d λ x , y ¯ = a b φ g x d λ x a b d λ x , z ¯ i s = a b G i g x , s d λ x a b d λ x ,
G i s = G i α , s + G i β , s z ¯ i s G i α + β x ¯ , s , i = 1 , , 5 .
Since all five Green’s functions are continuous and convex, by Theorem 1, G i s 0 for all i = 1 , , 5 .

2. Main Results

We start with two identities which are very useful in obtaining generalizations of inequality (4) to the class of n-convex functions.
Lemma 1.
Let the functions g and λ be as in Theorem 1, and let the function K be defined by (6). Then, for every function φ : α , β R such that φ n 1 is absolutely continuous on α , β for some n 1 , the identity
φ α + φ β y ¯ φ α + β x ¯ = 1 β α k = 2 n 1 n k k ! φ k 1 β α β k a b g x β k d λ x a b d λ x α x ¯ k 1 β α k = 2 n 1 n k k ! φ k 1 α β α k a b g x α k d λ x a b d λ x β x ¯ k + 1 n 1 ! β α α β α t n 1 K t , α + β t n 1 K t , β a b g x t n 1 K t , g x d λ x a b d λ x α + β x ¯ t n 1 K t , α + β x ¯ φ n t d t
holds.
Proof. 
Using (5) in the left hand of equality (19), we obtain
φ α + φ β y ¯ φ α + β x ¯ = k = 1 n 1 n k k ! α β k 1 φ k 1 β + 1 n 1 ! β α α β α t n 1 K t , α φ n t d t k = 1 n 1 n k k ! β α k 1 φ k 1 α + 1 n 1 ! β α α β β t n 1 K t , β φ n t d t + 1 β α k = 1 n 1 n k k ! φ k 1 α a b g x α k d λ x φ k 1 β a b g x β k d λ x a b d λ x 1 n 1 ! β α α β a b g x t n 1 K t , g x d λ x a b d λ x φ n t d t + 1 β α k = 1 n 1 n k k ! φ k 1 α β x ¯ k φ k 1 β α x ¯ k 1 n 1 ! β α α β α + β x ¯ t n 1 K t , α + β x ¯ φ n t d t .
By regrouping and calculating all the first members in the above sums, we obtain (19). □
Lemma 2.
Let the functions g and λ be as in Theorem 1, and let the functions G i , i = 1 , , 5 , and K be defined by (7)(11) and (6), respectively. Then, for every function φ : α , β R such that φ n 1 is absolutely continuous on α , β for some n 3 , the identity
φ α + φ β y ¯ φ α + β x ¯ = 1 β α k = 0 n 3 n k 2 k ! α β G i s φ k + 1 β s β k φ k + 1 α s α k d s + 1 n 3 ! β α α β φ n t α β G i s s t n 3 K t , s d s d t
holds.
Proof. 
From (5), we have
φ s = k = 0 n 3 n k 2 k ! · φ k + 1 α s α k + φ k + 1 β s β k β α + 1 n 3 ! β α α β s t n 3 K t , s φ n t d t .
Using (21) in (17) and applying Fubini’s theorem, we easily obtain (20). □
The following generalizations of inequality (4) for n-convex functions hold.
Theorem 2.
Let the functions g and λ be as in Theorem 1, and let the function K be defined by (6). Let φ : α , β R be a n-convex function such that φ n 1 is absolutely continuous on α , β for some n 1 .
(i) 
If
α t n 1 K t , α + β t n 1 K t , β a b g x t n 1 K t , g x d λ x a b d λ x α + β x ¯ t n 1 K t , α + β x ¯ 0 , α t β ,
then
φ α + φ β y ¯ φ α + β x ¯ 1 β α k = 2 n 1 n k k ! φ k 1 β α β k a b g x β k d λ x a b d λ x α x ¯ k 1 β α k = 2 n 1 n k k ! φ k 1 α β α k a b g x α k d λ x a b d λ x β x ¯ k .
(ii) 
If n is even then (23) holds. Moreover, if φ k 1 α 0 for k = 2 , 3 , , n 1 , φ k 1 β 0 for k = 2 , 4 , , n 2 and φ k 1 β 0 for k = 3 , 5 , , n 1 then the right-hand side of (23) is nonnegative and (4) holds.
Proof. 
i Since φ n 1 is absolutely continuous on α , β and φ is n-convex, φ n exist almost everywhere on α , β and φ n 0 . This fact and assumption (22) show that the third member on the right-hand side of (19) is nonnegative, so inequality (23) immediately follows from identity (19).
i i For a fixed t α , β consider the function ψ : α , β R defined by
ψ s = s t n 1 K t , s = s t n 1 t α for   α t s β , s t n 1 t β for   α s < t β .
It is continuous for n 2 and, since
ψ s = n 1 n 2 s t n 3 t α for   α t s β , n 1 n 2 s t n 3 t β for   α s < t β ,
it is convex on α , β for even n. Therefore, by Theorem 1,
ψ α + ψ β a b ψ g x d λ x a b d λ x ψ α + β x ¯ 0 ,
i.e., inequality (22) holds and, by i , inequality (23) holds.
Further, the function t t α k is convex on α , β for any k, and the function t t β k is convex (concave) on α , β for even (odd) k. Hence, by Theorem 1,
β α k a b g x α k d λ x a b d λ x β x ¯ k 0 ,
for all k = 2 , , n 1 ,
α β k a b g x β k d λ x a b d λ x α x ¯ k 0 ,
for k = 2 , 4 , , n 2 and the reversed inequality (25) holds for k = 3 , 5 , , n 1 . Hence, the second claim in i i immediately follows. □
Remark 2.
Under the assumptions of Theorem 2, the right-hand side of (23) can be written in the form
Ψ α + Ψ β a b Ψ g x d λ x a b d λ x Ψ α + β x ¯
where the function Ψ : α , β R is defined by
Ψ t = 1 β α k = 2 n 1 n k k ! φ k 1 β t β k φ k 1 α t α k .
Therefore, if n is even and the function Ψ is convex on α , β then, by Theorem 1, the right-hand side of (23) is nonnegative and (4) holds.
Theorem 3.
Let the functions g and λ be as in Theorem 1, and let the functions G i , i = 1 , , 5 , and K be defined by (7)(11) and (6), respectively. Let φ : α , β R be an n-convex function such that φ n 1 is absolutely continuous on α , β for some n 3 . Then, for all i = 1 , , 5 :
(i) 
If
α β G i s s t n 3 K t , s d s 0 , α t β
then
φ α + φ β y ¯ φ α + β x ¯ 1 β α k = 0 n 3 n k 2 k ! α β G i s φ k + 1 β s β k φ k + 1 α s α k d s
holds.
(ii) 
If n is even, then (27) holds. Moreover, if φ k + 1 α 0 for k = 0 , 1 , , n 3 , φ k 1 β 0 for k = 0 , 2 , , n 4 and φ k 1 β 0 for k = 1 , 3 , , n 3 then the right-hand side of (27) is nonnegative and (4) holds.
Proof. 
i Similarly as in the proof of Theorem 2, we can assume that φ is n-times differentiable and φ n 0 . Hence, assumption (26) gives that the second member on the right-hand side of (20) is nonnegative, so inequality (27) immediately follows from identity (20).
i i Since G i s 0 , for α s t β (26) holds when n is even, and the reversed (26) holds when n is odd, while for α t s β (26) always holds. Therefore, i i immediately follows from i . □
Remark 3.
Under the assumptions of Theorem 3, the right-hand side of (27) can be written in the form
Ψ ^ i α + Ψ ^ i β a b Ψ ^ i g x d λ x a b d λ x Ψ ^ i α + β x ¯ , i = 1 , , 5
where the functions Ψ ^ i : α , β R , i = 1 , , 5 are defined by
Ψ ^ i t = 1 β α k = 0 n 3 n k 2 k ! α β G i t , s φ k + 1 β s β k φ k + 1 α s α k d s .
Therefore, if n is even and the functions Ψ ^ i , i = 1 , , 5 are convex on α , β then, by Theorem 1, the right-hand side of (27) is nonnegative for all i = 1 , , 5 and (4) holds.

4. Conclusions

In the papers [11,12], we generalized the Jensen–Mercer inequality to the class of n-convex functions by using the Taylor polynomial and Green’s functions. Here, we do so using Fink’s identity and use these generalizations to obtain some related results for n-convex functions at a point. In a similar way as in [11], we can obtain Grüss and Ostrowski type inequalities in terms of Čebyšev functionals. Using the main ideas from [14], we can also generate new families of n-exponentially convex and exponentially convex functions by considering the linear functionals defined above.

Funding

This research was supported by the University of Split, FESB.

Acknowledgments

We would like to thank the reviewers for their effort to read the paper thoroughly and give us very useful suggestions on how to improve it.

Conflicts of Interest

The author declares no conflict of interest.

References

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