Abstract
Consider a free boundary problem of compressible-incompressible two-phase flows with surface tension and phase transition in bounded domains , , where the domains are separated by a sharp compact interface . We prove a global in time unique existence theorem for such free boundary problem under the assumption that the initial data are sufficiently small and the initial domain of the incompressible fluid is close to a ball. In particular, we obtain the solution in the maximal -regularity class with  and  and exponential stability of the corresponding analytic semigroup on the infinite time interval.
    Keywords:
                                                                    free boundary problem;                    phase transtion;                    two-phase problem;                    global solvability;                    maximal regularity        MSC:
                Primary: 35Q30; Secondary: 76T10
            1. Introduction
The purpose of this paper is to prove the global solvability of the free boundary problem of compressible–incompressible two-phase flows with phase transitions in bounded domains. Two fluids are separated by a free boundary  and a surface tension and phase transitions are taken into account. Our problem is formulated as follows: Let  be a bounded domain in N-dimensional Euclidean space , , surrounded by a smooth boundary . For , the hypersurface  represents a sharp moving interface that separates  into  and  such that . Through this article, we suppose that the two fluids are immiscible and no boundary contact occurs. Let  and for any function f defined on , we write . We consider the following Cauchy problem:
      
        
      
      
      
      
    
	  with the interfacial boundary conditions on :
        
      
        
      
      
      
      
    
      and the homogeneous Dirichlet boundary conditions on :
      
        
      
      
      
      
    
      and the initial conditions:
      
        
      
      
      
      
    
      where  and  are the densities,  the velocity fields,  the Helmholtz free energy functions, and  are positive constants,  the -times mean curvature of ,  a positive constant describing the coefficient of the surface tension,  the velocity of evolution of  with respect to ,  the interfacial velocity,  the outer unit normal to  pointed from  to , and  the outer unit normal to . Here,  is the phase flux and  are the Stress tensors defined by
      
      
        
      
      
      
      
    
      where  are the pressure fields. Here, for any vector fields , the deformation tensor  is defined by  whose th components are given by . Besides,
      
      
        
      
      
      
      
    
      is called the Korteweg tensor, which essentially ensures an additional smoothing for the density. In this article, the coefficients , , , and  are assumed to be constants satisfying , , , . Notice that if phase transitions occur on the moving interface , the phase flux j should be taken arbitrary. Furthermore, the jump of a quantity  defined on  across the interface  is defined by
      
      
        
      
      
      
      
    
      for all , where  is the outer unit normal to  at . In addition, we adopt the notations  for all .
Prüss et al. [,,,] and Shimizu and Yagi [,] studied the thermodynamically consistent model of the incompressible and incompressible two-phase flows with phase transitions. In particular, Prüss, Shimizu, and Wilke [] proved the stability of the equilibria of the problem. On the other hand, the compressible and incompressible two-phase flows with phase transitions was studied by Shibata []. However, his result includes the derivative loss in the nonlinear term with respect to  due to the kinetic equation: . Namely, we can not prove the local solvability of the problem based on his result. To overcome this difficulty, the new model using the Navier–Stokes–Korteweg equations was proposed by the author []. The new model is an extension of the Navier–Stokes–Fourier equations, and the physical consistency was discussed in Section 2 of []. Here, the second and third conditions of (2) stand for the conservation laws of mass and momentum on , respectively. Besides, the condition  not only guarantees the generalized Gibbs-Thomson law
      
      
        
      
      
      
      
    
      but also implies the interstitial working:  vanishes in the normal direction of the interface . Recently, the local solvability of the problem was showed in the previous paper []. For further historical review or physical backgrounds of our model, the readers may consult the introduction in [,,,] and references therein.
Now, let us formulate the problem. Let  and . In this paper, we suppose the following.
Assumption 1. 
Let  denote the Lebesgue measure of a Lebesgue measurable set D in . We assume the following conditions:
- 1.
- It holds , where is the area of .
- 2.
- The barycenter point of is suited at the origin, i.e.,
- 3.
- The initial free surface is a normal perturbation of given bywith given small function defined on .
Let the free boundary  be given by
      
      
        
      
      
      
      
    
      where  is an unknown function such that  for . Here,  denotes the barycenter point of the incompressible domain  defined by
      
      
        
      
      
      
      
    
      which is also an unknown function. Here, we have  due to Assumption 1 (2). Since it holds  in , the transport theorem implies
      
      
        
      
      
      
      
    
      which means that  is independent of t, i.e., it holds . Hence, from the transport theorem, we have
      
      
        
      
      
      
      
    
	  Furthermore, the transport theorem also yields an important formula
      
      
        
      
      
      
      
    
      because  and  are independent of t so that  is independent of t as well. For given function , let  be a solution to the Dirichlet problem:  in ,  on . From the K-method in real interpolation theory [], we have
      
      
        
      
      
      
      
    
	  We may assume that there exists a small number  such that . Let  be a cutoff function that equals one for  and zero for . Let . Notice that  for . Setting , we assume that
      
      
        
      
      
      
      
    
      with some small constant . In the following, we choose  so small that the map  is bijective from  onto itself. In fact, for any  and , it holds
      
      
        
      
      
      
      
    
      which implies the injectivety of the map  for any  provided that . Furthermore, by the inverse mapping theorem, the map  is surgective from  onto itself since  for . Let
      
      
        
      
      
      
      
    
	  Here,  is the unit outer normal to  for .
If one deals with the global existence issue of the free boundary problem of the Navier–Stokes equations with surface tension in a bounded domain, it is known that spectral analysis of the Stokes operator and the Laplace-Beltrami operator are crucial. To this end, we follow the approach due to Shibata [] in order to fixed the free boundary, where the corresponding transformation is given by . The essential point of his approach is that an eigenvalue of the principal linearization does not appear on , which yields the exponential stability of solutions as follows from the standard semigroup theory. Here, the similar approach was also used for the incompressible-incompressible two-phase flow case [,]. In our case, however, the domain of  is occupied by the compressible fluid so that further dedication is required, where the relation (5) becomes crucial. The details will be explained in Section 2.
Let , where  is a unique solution of the Dirichelt problem:  in  and  on . In the following, we set  and , where  and  are initial data (4). For functions , , and  satisfying the system (1)–(3), we set
      
      
        
      
      
      
      
    
	  Then the fixed boundary system associated with (1), (2), (3), and (4) can be read as the following:
      
        
      
      
      
      
    
      where  denotes the the outer unit normal to  pointed from  into  and we have set
      
      
        
      
      
      
      
    
      with  and . By abuse of notation, here and in the following, we may write
      
      
        
      
      
      
      
    
      and we let  and  be “linearized” stress tensors defined by
      
      
        
      
      
      
      
    
      and  stands for the following interface conditions on :
      
        
      
      
      
      
    
      where , , and  for any N vector . Furthermore,  () denote the spherical harmonics of degree 1 on , where . The right-hand members of (7) and (8) stands for the nonlinear terms that are independent of , which will be explained in the next section.
Before stating our main results, we finally introduce some technical assumptions.
Assumption 2. 
It holds . The coefficients , , , , and  satisfy
      
        
      
      
      
      
    
We further assume the following properties:
- 1.
- The pressure field is a -function defined on such that with some positive constant for any .
- 2.
- The Helmholtz free energy is a -function defined on such that with some positive constant for any . Besides, we assume that .
- 3.
- There exists positive constants such thatwhich stands for the Gibbs-Thomson condition and the Young-Laplace law, respectively. Especially, is given by .
Remark 1. 
The conditions (9) are imposed to avoid multiple roots of the characteristic equation arising in the model problems in the half space and the whole space with flat interface. In fact, in those cases, applying the partial Fourier transform to the generalized resolvent problem yields the ODEs with respect to , and the solution formula is obtained by the inverse partial Fourier transform, see Section 2 of [] and Section 4 of []. The condition (9) expect to be removed by employing the similar argument due to Saito [].
We now state our main result of this article. To this end, we record the necessary compatibility conditions for the given function . According to Assumption 1, it follows that  should satisfy the following conditions:
      
        
      
      
      
      
    
      where  denotes the surface element of . Namely, we have the compatibility condition for  as follows:
      
        
      
      
      
      
    
      where , , are the binomial coefficients. Finally, we set
      
      
        
      
      
      
      
    
      Then, our main result in this article can be read as follows.
Theorem 1. 
Let p and q be real numbers such that , , and . Assume that Assumptions 1 and 2 are valid. Then, there exists a small number  such that for any initial data , , and  satisfying the smallness condition:
      
        
      
      
      
      
    
and the compatibility conditions:
      
        
      
      
      
      
    and (10) the problem (7) with  admits a unique solution  and the estimate
      
        
      
      
      
      
    
with some positive constants C and α independent of ε.
Remark 2. 
Since  is a -diffeomorphism from Ω onto itself, we see that  is the unique solution to the problem (1)–(4) for any . Besides, , , and h possess the regularities
      
        
      
      
      
      
    where  denotes the Banach space of all X-valued bounded uniformly continuous functions and  is the subset of all bounded uniformly continuous functions that has bounded partial derivatives up to order .
The rest of this paper is organized as follows: In the next section, we give brief remarks on the derivation of the Equation (7). Section 3 is concerned with decay estimates for the linearized problem, where exponential stability of continuous analytic semigroup associated with the linearized problem is shown in Section 4. In Section 5, we prove our main result, Theorem 1.
Notation
Let , ,  be the sets of all natural numbers, real numbers, and complex numbers, respectively. Let  be a domain and let  and . Then, , , , and  denote the usual Lebesgue spaces Sobolev spaces, and Besov spaces on D, respectively. In addition, we may write  if . For a Banach space X, the m-product space of X is denoted by  and the norm of  is denoted by  instead of  if there is no confusion. For  and , let  and  be the X-valued Lebesgue spaces on I and the X-valued Sobolev spaces on I, respectively. Let
        
      
        
      
      
      
      
    
        where  is the surface element of  and f denotes the complex conjugate of f. The letter C denotes generic constants. Besides,  denotes a constant depending on the quantities a, b, ⋯ The values of C and  may change from line to line.
2. Remarks on the Derivation of the Equation (7)
Under the assumption (6), we set
      
      
        
      
      
      
      
    
	  Noting that the free boundary  is given by , the kinematic boundary condition reads as
      
      
        
      
      
      
      
    
	  To represent , we introduce the Jacobian of , which is denoted by  with some polynomial  satisfying . Besides, choosing  so small, then by (6) the inverse of the Jacobi matrix of the transformation  exists, i.e., we can write
      
      
        
      
      
      
      
    
      and hence there exists an  matrix  of  functions defined on  such that  and . Hence, it follows that
      
      
        
      
      
      
      
    
	  Employing the similar argument given in Appendix of [], we see that the functions , , , and h satisfy
      
      
        
      
      
      
      
    
      where the right-hand members represent the nonlinear terms. See Appendix of [] for the exact expressions of the nonlinearities. Here, the boundary condition  is given by
      
      
        
      
      
      
      
    
We next show that the solution  to (7) satisfies the system (12). To this end, we recall Assumption 1 and the representation of . By using polar coordinates we have
      
      
        
      
      
      
      
    
      and
      
      
        
      
      
      
      
    
      where  () denote the spherical harmonics of degree 1 on  normalized by . These formulas imply
      
      
        
      
      
      
      
    
	  Especially, it holds
      
      
        
      
      
      
      
    
	  Hence, we can rewrite (13) as follows:
      
        
      
      
      
      
    
      where we have set
      
      
        
      
      
      
      
    
      respectively. Notice that (15) is equivalent to
      
      
        
      
      
      
      
    
It remains to give a representation of the evolution equation for the height function. Let  be the th component of . Then we have
      
      
        
      
      
      
      
    
      and hence the transport theorem (5) can be read as
      
      
        
      
      
      
      
    
	  Thus, the evolution equation of h becomes
      
      
        
      
      
      
      
    
      where we have set
      
      
        
      
      
      
      
    
3. Decay Estimates for the Linearized Problem
To prove Theorem 1, the crucial ingredient is decay properties of solutions of the Stokes equations:
      
        
      
      
      
      
    
      where . Let  be given by  and  () that denote the spherical harmonics of degree 1 on , where . Then,  forms an orthogonal basis of the space  with respect to the  inner-product . In this section, we will prove the following theorem.
Theorem 2. 
Let , , , and . There exists a constant  such that the following assertion is valid: Let , , and . In addition, let  be functions in the right-hand members of (16) such that
      
        
      
      
      
      
    where the compatibility condition  holds in . Furthermore, we suppose the compatibility conditions:
      
        
      
      
      
      
    provided , while we suppose the compatibility conditions: ,  on  provided . Then the problem (16) has a unique solution  possessing the estimate
      
        
      
      
      
      
    for some constant independent of η and T. Here and in the following, we set
      
        
      
      
      
      
    
To show Theorem 2, we first consider the shifted equations
      
      
        
      
      
      
      
    
      For the shifted Equation (17), the following theorem can be shown.
Theorem 3. 
Let , , , and . Then, there exists a constant  such that if , then the following assertion holds: Let , , and  be the initial data for Equation (17) and let , , , , D,  be given functions on the right-hand side of (17) with
      
        
      
      
      
      
    where the compatibility condition  is valid in . Suppose the compatibility conditions:
      
        
      
      
      
      
    if , while
      
        
      
      
      
      
    if . Then, the problem (17) admits a unique solution  possessing the estimate
      
        
      
      
      
      
    for some constant C independent of T.
Proof.  
Employing the argument in [], we can show the unique existence of  possessing the estimate (18). In fact, we can show the existence of the -bounded solution operators for the generalized resolvent problem that is obtained by the Laplace transform of (17) with respect to time t, and hence the operator valued Fourier multiplier theorem (cf. Weis []) yields the estimate (18). We refer to [] for the detailed proof.    □
For any , we see that  satisfies the equations:
      
        
      
      
      
      
    
	  For given  we choose  such that , from Theorem 3, we obtain the next corollary.
Corollary 1. 
Let , , , , and . Let , , and . In addition, let  be functions in the right-hand members of (17) such that
      
        
      
      
      
      
    where the compatibility condition  holds in . Furthermore, we suppose the compatibility conditions:
      
        
      
      
      
      
    provided , while we suppose the compatibility conditions:
      
        
      
      
      
      
    provided . Then, there exists a constant  such that the problem (17) admits a unique solution  possessing the estimate
      
        
      
      
      
      
    for some constant independent of η and T.
We seek the solution  of (16) of the form: , , , and , where  enjoys the shifted Equation (17). Then, we find that  satisfies
      
      
        
      
      
      
      
    
      For , we define solenoidal spaces  by
      
      
        
      
      
      
      
    
      where  is defined by  with . Since  is bounded, we know that  is dense in , so that the necessary and sufficient condition in order that  is that  in . Define
      
      
        
      
      
      
      
    
      and let  be a solution to the variational equation
      
      
        
      
      
      
      
    
	  Set . Then, it holds  and
      
      
        
      
      
      
      
    
	  Using  and , the Equation (20) can be rewritten as
      
      
        
      
      
      
      
    
	  From this viewpoint, in what follows, we may suppose that
      
      
        
      
      
      
      
    
Notice that the second and third boundary condition of  are equivalent to
      
      
        
      
      
      
      
    
	  Recalling the argument in Section 4.1 in [], we introduce a functional  that is a unique solution to the weak problem
      
      
        
      
      
      
      
    
      for any  subject to
      
      
        
      
      
      
      
    
	  To handle (20) in the semigroup setting, we consider the initial value problem:
      
        
      
      
      
      
    
	  Here, from the definition of , we observe that the boundary condition (22) can be written as
      
      
        
      
      
      
      
    
	  Now, we define , , and  by
      
      
        
      
      
      
      
    
      and
      
      
        
      
      
      
      
    
      respectively. Then, (22) is formulated by
      
      
        
      
      
      
      
    
      with  for  and . According to ([] Thm. 6.3), the operator  generates a -analytic semigroup  on . As usual, the resolvent of  is denoted by . Furthermore, for some  and , the set
      
      
        
      
      
      
      
    
      is included in the resolvent set of . We define
      
      
        
      
      
      
      
    
	  To address some exponential decay property of (22), we here record some simple but important fact that the closed subspace  is -invariant, i.e.,  for any .
Lemma 1. 
Let  be given in (25). Then the subspace  is -invariant for every . Namely, for given , the solution  to
      
        
      
      
      
      
    belongs to .
Proof.  
It suffices to prove that . Integrating (26), we have  since . Noting that , we obtain . This completes the proof.    □
According to Lemma 1, the restriction operator  with its domain given by  is the generator of the induced -semigroup , which is analytic. Since  is bounded, we can show that  is included in the resolvent set of , which implies that the induced -semigroup  is exponentially stable on .
Theorem 4. 
Let . Then, the induced -semigroup  is exponentially stable on , that is,
      
        
      
      
      
      
    for any  and  with some positive constants C and . Here, we have set
      
        
      
      
      
      
    
We will give the proof of Theorem 4 in the next section and we now continue the proof of Theorem 2. Set . Notice that it holds . Let
      
      
        
      
      
      
      
    
      and then by the Duhamel principle, we see that  satisfies
      
      
        
      
      
      
      
    
	  From Theorem 4, we have
      
      
        
      
      
      
      
    
	  Choosing  suitably small if necessary, we may suppose that  without loss of generality. Hence, for any  it holds
      
      
        
      
      
      
      
    
	  Combined with (19), we have
      
      
        
      
      
      
      
    
      for any . If  satisfies the shifted equations:
      
        
      
      
      
      
    
      we have
      
      
        
      
      
      
      
    
      as follows from (19) and (28). Recalling that  solves (27), we have , , and  for . Hence, we obtain the estimate
      
      
        
      
      
      
      
    
	  Now, we let
      
      
        
      
      
      
      
    
	  In this case, the pressure term  is given by
      
      
        
      
      
      
      
    
	  In fact, it holds
      
      
        
      
      
      
      
    
      and thus we have
      
      
        
      
      
      
      
    
      where we abbreviate
      
      
        
      
      
      
      
    
	  Notice that we have
      
      
        
      
      
      
      
    
      for any  since  is a constant, i.e., . Since  satisfies (27), we see that  satisfies (20). Besides, by (29) we obtain the estimate
      
      
        
      
      
      
      
    
      for any . To estimate , we use the following lemma.
Lemma 2. 
Let . Let , , , and  satisfy
      
        
      
      
      
      
    with . Then, it holds
      
        
      
      
      
      
    with some constant C.
We will give the proof of Lemma 2 in the next section and we continue to show Theorem 2. From (20), we see that  satisfies the elliptic equations:
      
        
      
      
      
      
    
	  According to Lemma 2 and (30), we obtain
      
      
        
      
      
      
      
    
	  Finally, we find that , , , and  satisfy (16). Especially, from the estimate
      
      
        
      
      
      
      
    
      which follows from (19), we see that  satisfies the required estimate. This completes the proof of Theorem 2.
4. Exponential Stability of Continuous Analytic Semigroup
In this section, we shall prove Theorems 4 and 2 given in the previous section. To prove Theorem 4, we consider the resolvent problem associated to (24):
      
        
      
      
      
      
    
      for  and . According to ([] Sec. 6.1), there exists  and  such that for any  and , the resolvent estimate
      
      
        
      
      
      
      
    
      holds. To prove Theorem 4, we shall prove that the resolvent set of  contains .
Theorem 5. 
Recalling Lemma 1, we obtain the following lemma.
Lemma 3. 
In view of Lemma 3, it suffices to show the next theorem.
Theorem 6. 
Let  and  be the same number as in Lemma 3. For any  and , the Equation (33) admits a unique solution  that enjoys the estimate  with some constant C independent of λ.
In the following, we shall prove Lemma 6. We first observe that
      
      
        
      
      
      
      
    
	  In fact, for  we set , i.e.,
      
      
        
      
      
      
      
    
	  For any , by (21), we have
      
      
        
      
      
      
      
    
      which implies . From (36) and the divergence theorem, it holds  due to  in . Hence, we obtain (35).
In view of Lemma 3, the inverse  exists as a bounded linear operator from  onto . Then, the Equation (33) is rewritten as
      
      
        
      
      
      
      
    
	  If the inverse of  exists as a bounded linear operator from  onto itself, it holds
      
      
        
      
      
      
      
    
	  Hence, it remains to prove the existence of the operator . Here,  is a compact operator from  onto itself due to the Rellich compact embedding theorem. Hence, in view of the Riesz-Schauder theory, it suffices to show that the kernel of the map  is trivial, i.e., if  satisfies
      
      
        
      
      
      
      
    
      then . From (37), it holds
      
      
        
      
      
      
      
    
      so that we observe , i.e., . This equivalents to the fact that  satisfies the homogeneous equations:
      
        
      
      
      
      
    
	  We first notice that the spectrum of  is independent of q, so that we may let , cf., []. Taking the inner product of the problem for  with  and , an integration by parts infers
      
      
        
      
      
      
      
    
	  On the other hand, the inner product of the equations for  with  by an integration by parts leads to
      
      
        
      
      
      
      
    
	  Since we have
      
      
        
      
      
      
      
    
      it holds
      
      
        
      
      
      
      
    
	  Furthermore, by
      
      
        
      
      
      
      
    
      the equation of h implies
      
      
        
      
      
      
      
    
	  Since the components of  are eigenfunctions of the Laplace-Beltrami operator , it holds , , so that
      
      
        
      
      
      
      
    
      From (39) and (41), we see that (40) can be rewritten as
      
      
        
      
      
      
      
    
      Hence, taking the real part of (42), it follows that
      
      
        
      
      
      
      
    
      To handle , we introduce the following lemma essentially proved in [] (Lem. 4.5).
Lemma 4. 
Let  be defined on  with domain . Then the following holds.
- 1.
- is self-adjoint. The spectrum of consists entirely of eigenvalues of finite algebraic multiplicity and is given by .
- 2.
- There is precisely one negative eigenvalue with eigenfunction , which is simple.
- 3.
- The kernel of is spanned by , .
- 4.
- is positive semi-definite on and positive definite on
From the equation of h and the divergence theorem of Gauss, we have
      
      
        
      
      
      
      
    
      where  denotes the area of . Since  in , we have
      
      
        
      
      
      
      
    
      provided that  with . Hence, it follows from Lemma 4 that  is positive semi-definite. Besides, noting that , we have
      
      
        
      
      
      
      
    
      for all  such that , . Since , we have  when  and . Hence, from the equation of h, we obtain  if . If , the inequality (45) yields  in  and  in . Recalling (43), we find that  in . Using the Korn inequality, we observe  due to the no-slip boundary condition on  and the boundary condition  on , see also [] (Lem. 1.2.1). Then, from the equation of , we find that  because . Besides, by the equation of h, we also obtain  due to . This investigation shows that  is not an eigenvalue of  if  and . We now show that  belongs to a resolvent set of  as well. As we discussed above, we easily observe that . By (38), we see that  is a constant in . Here, by the interface condition for the stress tensor, we have
      
      
        
      
      
      
      
    
      Integrating this formula on  and using (44), we arrive at  on , i.e.,
      
      
        
      
      
      
      
    
      Taking the inner product of this identity with , we observe  due to Lemma 4. Hence, we see that  on , which implies  on . Now, from (38), it holds  in , where we have  on . Taking the inner product of this elliptic problem with , we have
      
      
        
      
      
      
      
    
      This gives that  is a constant. However, recalling  on  and the stress boundary condition, we obtain  in . Since , we deduce that  in . This completes the proof of Theorem 6. Finally, we give the proof of Theorem 2. Let . Then, it holds
      
      
        
      
      
      
      
    
      for any  subject to
      
      
        
      
      
      
      
    
      Namely, we have
      
      
        
      
      
      
      
    
      Noting that  is a constant, i.e., , we observe that  satisfies (31) with . Hence, by (35) and Theorem 6 with , it holds . Therefore, combined with the estimate:
      
        
      
      
      
      
    
      we obtain (32). This completes the proof of Lemma 2.
5. Nonlinear Well-Posedness
5.1. Local Well-Posedness
Before we prove Theorem 1, we state the local well-posedness result of (7).
Theorem 7. 
Let , , . Besides, let . Suppose that Assumptions 1 and 2 hold. Then, there exists a number  depending on T such that if initial data , , and  satisfies the smallness condition:
      
        
      
      
      
      
    and the compatibility conditions:
      
        
      
      
      
      
    the problem (7) has a unique solution  and the estimate
      
        
      
      
      
      
    
Moving the lower-order terms  and  to the right-hand side and employing the similar argument to that in the proof of [] (Thm. 3.7), we can prove Theorem 7, and so we may omit the details. Here, by  it holds , so that the condition (6) holds if  is so small.
5.2. Global Well-Posedness
Finally, we prove Theorem 1. Assume that the initial data , , and  satisfy the smallness condition
        
      
        
      
      
      
      
    
        with small constant  as well as the compatibility conditions (10) and (11). In the following, we write
        
      
        
      
      
      
      
    
        for short. From the proof of [] (Lem. 5.4) (cf., [] ((3.212), (3.213)), there exists a constant C independent of T such that the estimate
        
      
        
      
      
      
      
    
        holds. Hence, we see that
        
      
        
      
      
      
      
    
        where C is a constant independent of T. Since we choose  small enough eventually, we may suppose that .
Let  be a given number. From Theorem 7, there exists a small number  such that the system (7) admits a unique solution  with  provided that . Assume the existence of a unique solution  of (7) satisfying
        
      
        
      
      
      
      
    
		In the following, we shall show that the solution to (7) can be prolonged beyond T keeping the estimates (48) provided that  is small enough. To this end, it suffices to show the inequality
        
      
        
      
      
      
      
    
        for any  with some constant  independent of , T, and , where  is the same constant as in Theorem 2. In fact, if , we may deuce that  for any . Especially, setting , we obtain
        
      
        
      
      
      
      
    
		Thus, choosing  small enough and employing the same argument as that in proving Theorem 7, we find that there exists a unique solution  of the following system: 
      
        
      
      
      
      
    
        which satisfies
        
      
        
      
      
      
      
    
		Here,  is given by  with the time interval  instead of . Let
        
      
        
      
      
      
      
    
        and then  belongs to  that satisfies
        
      
        
      
      
      
      
    
        and the system (7) in the time interval  instead of . Since , repeating the above argument, we can prolong the solution to time interval . This completes the proof of Theorem 1.
Below, we show the a priori estimate (49). Since we will choose  small enough eventually, we may assume that . We extend the right-hand members
        
      
        
      
      
      
      
    
        of (7) to  that are denoted by
        
      
        
      
      
      
      
    
		Here, we refer to Section 7.2 of [] for the suitable extension operators. Then, employing the same argument as in Section 7.2 of [], we have
        
      
        
      
      
      
      
    
		Hence, by Theorem 2, we obtain
        
      
        
      
      
      
      
    
		Noting that
        
      
        
      
      
      
      
    
        it holds
        
      
        
      
      
      
      
    
        instead of (47). Hence, it follows that
        
      
        
      
      
      
      
    
		Recalling (14), we have
        
      
        
      
      
      
      
    
        so that we arrive at the estimate (49). This completes the proof of Theorem 1.
Funding
This research was partly supported by JSPS Grant-in-aid for Research Activity Start-up Grant Number 20K22311 and Waseda University Grant for Special Research Projects.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Conflicts of Interest
The author declares no conflict of interest.
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