A graph with
n vertices is called an
n-graph. A spanning tree with at most
k leaves is referred to as a spanning
k-ended tree. Spanning
k-ended trees are important in various fields such as network design, graph theory, and
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A graph with
n vertices is called an
n-graph. A spanning tree with at most
k leaves is referred to as a spanning
k-ended tree. Spanning
k-ended trees are important in various fields such as network design, graph theory, and communication networks. They provide a structured way to connect all the nodes in a network while ensuring efficient communication and minimizing unnecessary connections. In addition, they serve as fundamental components for algorithms in routing, broadcasting, and spanning tree protocols. However, determining whether a connected graph has a spanning
k-ended tree or not is NP-complete. Therefore, it is important to identify sufficient conditions for the existence of such trees. The implicit-degree proposed by Zhu, Li, and Deng is an important indicator for the Hamiltonian problem and the spanning
k-ended tree problem. In this article, we provide two sufficient conditions for
K1,4-free connected graphs to have spanning
k-ended trees for
k = 2, 3. We prove the following: Let
G be a
K1,4-free connected
n-graph. For
k = 2, 3, if the implicit-degree sum of any
k + 1 independent vertices of
G is at least
n −
k + 2, then
G has a spanning
k-ended tree. Moreover, we give two examples to show that the lower bounds
n and
n − 1 are the best possible.
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