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Article

Existence Result for Coupled Random First-Order Impulsive Differential Equations with Infinite Delay

1
Department of Mathematics, College of Science, University of Ha’il, Ha’il 55473, Saudi Arabia
2
Department of Exact Sciences, Higher Training Teacher’s School of Oran Ammour Ahmed (ENSO), Oran 31000, Algeria
3
Department of Mathematics, Faculty of Mathematics and Informatics, University of Science and Technology of Oran Mohamed-Boudiaf (USTOMB), El Mnaouar, BP 1505, Bir El Djir, Oran 31000, Algeria
4
Department of Mathematics, College of Science, King Khalid University, P.O. Box 9004, Abha 61413, Saudi Arabia
5
Department of Mathematics, College of Sciences and Arts, Qassim University, Ar-Rass 51921, Saudi Arabia
*
Author to whom correspondence should be addressed.
Fractal Fract. 2024, 8(1), 10; https://doi.org/10.3390/fractalfract8010010
Submission received: 4 November 2023 / Revised: 9 December 2023 / Accepted: 14 December 2023 / Published: 21 December 2023
(This article belongs to the Special Issue Advances in Nonlinear Dynamics: Theory, Methods and Applications)

Abstract

:
In this paper, we consider a system of random impulsive differential equations with infinite delay. When utilizing the nonlinear variation of Leray–Schauder’s fixed-point principles together with a technique based on separable vector-valued metrics to establish sufficient conditions for the existence of solutions, under suitable assumptions on Y 1 , Y 2 and ϖ 1 , ϖ 2 , which greatly enriched the existence literature on this system, there is, however, no hope to discuss the uniqueness result in a convex case. In the present study, we analyzed the influence of the impulsive and infinite delay on the solutions to our system. In addition, to the best of our acknowledge, there is no result concerning coupled random system in the presence of impulsive and infinite delay.

1. Introduction and Position of Problem

1.1. Results and Discussion

Nowadays, mathematics contains many references related to impulsive differential equations. We mention here the development of some of them in this area. Impulsive differential equations is considered in [1], where the authors obtained results related to oscillation and the behaviour of solutions of the system
v ( s ) + r ( s ) v ( s τ ) = 0 , s ϕ k , s s 0 , v ( ϕ k + ) v ( ϕ k ) = I k ( v ( ϕ k + ) ) , k N .
Impulsive infinite delay differential equations is considered in [2] as a system
x ( r ) = f ( r , x ( r ) , x ( r s ( r ) ) ) , r r 0 , r s k , x ( r ) x ( r ) = I k ( x ( r ) ) , r = s k , k = 1 , 2 . . .
By using the Lyapunov functions together with the Razumikhin technique, new results related to the existence and behavior of solution were obtained.
In [3], the authors proposed a random impulsive differential equations for k = 1 , . . . , m
y ( r , t ) = f ( t , y ( t , r ) , r ) , t t k , y ( r , t k + ) y ( r , t k ) = I k ( y ( r , t k ) , r ) , y ( r , a ) = ν ( r ) ,
here, the function ν C 0 ( Ω R n ) is a random variable. Under appropriate conditions in the parameters f , k , I , the existence and uniqueness is established owing to the generalized Schaefer’s type random fixed-point theorem. Numerous processes in physics, biology, medicine, population dynamics, and other fields may experience rapid changes like shocks or perturbations (for examples, see [4,5] and the references therein). While this is going on, several models of genuine processes and phenomena explored in physics, chemical technology, population dynamics, biotechnology, and economics are described by delayed impulsive differential systems and evolution differential systems. That is why, in recent years, they have been the object of investigations by many mathematicians [6,7]. We cite the work of Samoilenko and Perestyuk [8], Lakshmikantham et al. [9], and Bainov and Simeonov [10] as sources, where a thorough bibliography is provided and several features of their solutions are investigated. Many studies have been carried out on functional differential equations and inclusions with or without impulses. See the books by Dejabli et al. [11] and Graef et al. [12] for more information on how existence and uniqueness are derived. The boundary value problem on infinite intervals can be found in a variety of real-world models, such as foundation engineering, nonlinear fluid flow problem, and difficulties involving linear elasticity (see [13,14,15,16,17,18,19]) and the references therein. Recent years have seen a significant increase in research into impulsive ordinary differential equations and functional differential equations under various conditions; for examples, see the works by Aubin [20] and Benchohra et al. [6] and the references therein. The presence of a delay in the system being studied often turns out to be the cause of phenomena that significantly influence the course of the process. Differential equations with delay argument are differential equations in which an unknown function and its derivatives appear at different values where the time derivatives at the current time depend on the solution and possibly its derivatives at previous times. The most natural methods for solving this type of problem are so-called iterative methods; for more details, please see [21,22,23,24]. Motivated by the previous works, in the present paper it is interesting to analyze the influence of the impulsive and infinite delay on the solutions to system (4) under suitable assumptions on Y 1 , Y 2 and ϖ 1 , ϖ 2 with the presence of new random properties.

1.2. Position of Problem

To begin with, let Γ be an open domain of R n , n > 1 , J = [ 0 , ) , J 0 = ( , 0 ] , J k = ( t k 1 , t k ] , k = 1 , 2 , , ϖ i = ϖ i ( t , x ) , ϖ i = ϖ i ( t , x ) , ϖ i = ϖ i ( t , x ) , i = 1 , 2 , t [ 0 , ) , x Γ . The following system of impulsive differential equations by random effects (random parameters) with infinite delay is examined in this paper
ϖ 1 = Y 1 ( t , ϖ 1 t ( x ) , ϖ 2 t ( x ) , x ) , a . e t J , t t k , ϖ 2 = Y 2 ( t , ϖ 1 t ( x ) , ϖ 2 t ( x ) , x ) , a . e t J , t t k , Δ ϖ 1 ( t ) = I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t = t k , Δ ϖ 2 ( t ) = I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t = t k , A 1 ϖ 1 ϖ 1 , = ϕ 1 ( t , x ) , t ( , 0 ] , A 2 ϖ 2 ϖ 2 , = ϕ 2 ( t , x ) , t ( , 0 ] ,
where Y i : J × D 0 × D 0 × Γ P ( R n ) , i = 1 , 2 and I k 1 , I k 2 C 0 ( R n × R n , R n ) are given functions satisfying some assumptions that will be specified later and
lim t ( ϖ 1 ( t ) , ϖ 2 ( t ) ) = ( ϖ 1 , , ϖ 2 , ) ,
here ϕ 1 , ϕ 2 D 0 , and D 0 is called a phase space that will be defined later; the fixed times t k satisfies
0 < t 1 < t 2 < < t m < T ,
ϖ 2 ( t k ) and ϖ 2 ( t k + ) denotes the left and right limits of ϖ 2 ( t ) at t = t k and ϕ 1 , ϕ 2 are two random maps. The impulse times t k satisfy
0 = t 0 < t 1 < t 2 < , t m < T .
If T = , t k satisfies
0 = t 0 < t 1 < t 2 < , t m < .
The functional ϖ 1 t , represent the infinite delay and as for ϖ 2 t , we mean the segment solution which is defined in the usual way, that is, if ϖ 2 ( . , . ) C 0 ( ( , ) × Γ , R n ) , then for any t 0 , ϖ 2 t ( . , . ) C 0 ( ( , 0 ] × Γ , R n ) is given by
ϖ 2 t ( α , ω ) = ϖ 2 ( t + α , ω ) , for α ( , 0 ] .
Before going into the characteristics of the operators Y 1 , Y 2 and I k 1 , I k 2 , we first introduce some notation and define certain spaces.
In this study, we will make use of Hale and Kato’s [25] axiomatic description of the phase space D 0 .
Definition 1.
By  D 0 , we mean a linear space containing a family of measurable functions from  ( , 0 ] into  R n and endowed with a norm . D 0 . The following axioms are satisfied:
(A1
If  ϖ 2 C 0 ( ( , T ) , R n ) , T = + , is such that ϖ 2 , 0 D 0 , then for every t J the following conditions hold
(i) 
ϖ 2 t D 0 ,
(ii) 
ϖ 2 ( t ) L ϖ 2 t D 0 ,
(iii) 
ϖ 2 t D 0 K ( t ) sup { ϖ 2 ( s ) : 0 s t } + N ( t ) ϖ 2 , 0 D 0 ,where  L > 0 is a constant;  K , N C 0 ( [ 0 , ) , [ 0 , t ) ) , K is continuous, N is locally bounded and  K , n are independent of  ϖ 2 ( . ) .
(A2
For the function ϖ 2 ( . ) in ( A 1 ) , ϖ 2 t is a D 0 -valued function on [ 0 , t ) .
(A3
The space D 0 is complete.
Denote
K ˜ = sup t J { K ( t ) } and N ˜ = sup t J { N ( t ) } .
Remark 1.
In retarded functional differential equations without impulses, the axioms of the abstract phase space D 0 include the continuity of the function t ϖ 2 t . Due to the impulsive effect, this property is not satisfied in impulsive delay systems, and, for this reason, it has been eliminated in our abstract description of D 0 .
Let
D 0 = ϕ i C 0 ( ( , 0 ] × Ω , R n ) , for any , sup θ 0 ( | ϕ i ( θ ) | ) < .
If D 0 is endowed with the norm
ϕ D 0 = sup θ 0 ( | ϕ i ( θ ) | ) ,
then ( D 0 , · D 0 ) is a Banach space, see [26].
Now, for a given T = + , we define
D = ϖ 2 C 0 ( ( , ) × Γ , R n ) , ϖ 2 , k C ( J k , R n ) , k = 1 , m , ϖ 2 , 0 D 0 , and there exist ϖ 2 ( t k ) and ϖ 2 ( t k + ) with ϖ 2 ( t k ) = ϖ 2 ( t k ) , k 1 , , m and sup t J | ϖ 2 ( t ) | < ,
endowed with the norm
ϖ 2 D = ϕ 2 D 0 + sup s J | ϖ 2 ( s ) | ,
where ϖ 2 , k denotes the restriction of ϖ 2 to J k .
Then we will consider our initial data ϕ 1 , ϕ 2 D 0 . As for the impulse functions, we will assume that I k 1 , I k 2 C 0 ( R n × R n , R n ) and
Δ ϖ 2 ( t ) | t = t k = ϖ 2 ( t k + ) ϖ 2 ( t k ) ,
ϖ 2 ( t k + ) = lim h 0 + ϖ 2 ( t + h ) ,
and
ϖ 2 ( t k ) = lim h 0 ϖ 2 ( t h ) .
We suppose that the multi-function Y i ( x , ϖ 1 t ( x ) , ϖ 2 t ( x ) ) is measurable over the entire paper. Applying a novel random fixed point theorem to a system of impulsive random differential equations is the primary objective of this research. Additionally, we provide a random application of the separable vector-valued Banach space Leray–Schauder fixed point theorem.
This article is structured as follows: We provide notations, definitions and introductory information in Section 2 and state some Lemmas and Theorems in Section 3 that will be helpful throughout the proof. Using a nonlinear variant of the Leray–Schauder type theorem on extended Banach spaces in the convex case as in [27], we demonstrate the existence result in Section 4. To finish the work, we give conclusive comments with a discussion of the novelties and some perspictives.

2. Preliminaries and Tools

Here, we make some notes, review some definitions, and talk about some background material that will be used later in the article. In fact, we will use quotes from [28,29]. Although we can only refer to this document when we need it, we prefer to include it here to keep our work as independent as possible and to make it easier to read.

Vector Metric Space

Let
ϖ 1 = ( ϖ 1 , 1 , , ϖ 1 , n ) R n ,
and
ϖ 2 = ( ϖ 2 , 1 , , ϖ 2 , n ) R n .
The interval I be in R and c R , we note that I Z = I Z ,
ϖ 1 ϖ 2 implies that ϖ 1 , j ϖ 2 , j , j = 1 , . . . , n ,
ϖ 1 c equivalent that ϖ 1 , j c , j = 1 , . . . , n ,
| ϖ 1 | = ( | ϖ 1 , 1 | , , | ϖ 1 , n | ) , max ( ϖ 1 , ϖ 2 ) = max j = 1 , . . . , n ( max ( ϖ 1 , j , ϖ 2 , j ) ) .
Definition 2.
Let E be a non-empty set and a map d C 0 ( E × E , R n ) , where d = d 1 , . . . , d n , we say that the pair ( E , d ) is said to be a generalized metric space if each pair E , d i i 1 , n Z are metric spaces.
For
a = ( a 1 , , a n ) R + n ,
we will denote by
B ( ϖ 0 , a ) = ϖ E : d ( ϖ 0 , ϖ ) < a } = { ϖ E : d j ( ϖ 0 , ϖ ) < a j , j = 1 , . . . , n } ,
the open ball centered in ϖ 0 with radius a and
B ( ϖ 0 , a ) ¯ = { ϖ E : d ( ϖ 0 , ϖ ) a } = { ϖ E : d j ( ϖ 0 , ϖ ) a j , j 1 , . . . , n } ,
the closed ball with radius a, centered in ϖ 0 . We point out that the notation of open subset, closed set, convergence, Cauchy sequence, and completion in generalized metric space is comparable to that in conventional metric space.

3. Random Variable and Some Selection Theorems

In this section, symbols, definitions, and introductory information from the multivalued analysis and random variables used throughout this article are presented. Let X be a subset of E, and let ( E , d ) be a Banach space or a generalized metric space. Let
P c l ( E ) = { X P ( E ) : X closed } ,
P b ( E ) = { X P ( E ) : X bounded } ,
P c ( E ) = { X P ( E ) : X convex } ,
P c p ( E ) = { X P ( E ) : X compact } .
Definition 3.
Let ( Γ , Σ ) be a measurable space and Y C 0 ( Γ , P ( E ) ) be a multi-valued mapping, Y is called measurable if
Y + ( Q ) = { x Γ : Y ( x ) Q } ,
for every Q P c l ( E ) , equivalently, for every U open set of E, the set
Y ( Q ) = { x Γ : Y ( x ) U } ,
is measurable.
Let E is a metric space, we will use B ( E ) to denote the Borel σ -algebra on E. The Σ × B ( E ) denotes the smallest σ -algebra on Γ × E , which contains all the sets A × S , where Q Σ and S B ( E ) . Let Y C 0 ( E , P ( X ) ) be a multi-valued map. A single-valued map f C 0 ( E , X ) is said to be a selection of G, and we write ( f Y ) whenever f ( ϖ ) Y ( ϖ ) for every ϖ E .
Definition 4.
A mapping Y C 0 ( Γ × E , E ) is called a random operator if any ϖ E , f ( . , ϖ ) is measurable.
Definition 5.
A random fixed point of f is a measurable function ϖ C 0 ( Γ , E ) such that
ϖ ( x ) = f ( x , ϖ ( x ) ) , x Γ .
Equivalently, a measurable selection for the multi-valued map F i x Y : Γ P ( E ) is defined by
F i x Y x ( ϖ ) = { ϖ E : ϖ = f ( x , ϖ ) } .
Theorem 1
([27]). Let ( Γ , Σ ) , X be a separable metric space and Y C 0 ( Γ , P c l ( X ) ) be measurable multi-valued. Then Y has a measurable selection.
The following conclusions can be drawn from Kuratowski–Ryll–Nardzewski and Aumann’s selection Theorems.
Theorem 2
([27]). Let ( Γ , Σ ) , X be a separable generalized metric space and Y C 0 ( Γ , P c l ( X ) ) be measurable multi-valued. Then Y has a measurable selection.
Then, in a separable vector Banach space, we propose a few random fixed-point theorems.
Theorem 3
([27]). Let E be a separable generalized Banach space, and let G C 0 ( Γ × E , P c l , c v E ) be an upper semi-continuous and compact map. Then either of the following holds:
(i
The random equation G ( x , ϖ ) ϖ has a random solution, i.e., there is a measurable function ϖ C 0 ( Γ , E ) such that
G ( x , ϖ ( x ) ) ϖ ( x ) , x Γ .
(ii
The set
M = { ϖ : Γ E : ϖ is measurable and ϖ λ ( x ) G ( x , ϖ ) } ,
is unbounded for some measurable λ C 0 ( Γ , E ) with 0 < λ ( x ) < 1 on Γ.
Definition 6.
The function f C 0 ( [ 0 , b ] × R × Γ , R ) is called random Carathéodory if
(i
The map ( t , x ) f ( t , ϖ , x ) is jointly measurable x R ,
(ii
The map ϖ f ( t , ϖ , x ) is continuous t [ 0 , b ] and x Γ .
Lemma 1
([27]). Let E be a separable generalized metric space and G C 0 ( Γ × E , E ) be a mapping such that G ( . , ϖ ) is measurable ϖ E and G ( x , . ) is continuous x Γ . Then the map ( x , ϖ ) G ( x , ϖ ) is jointly measurable.
Lemma 2
([12]). Let E be a Banach space. Let Y C 0 ( J × E , P c p , c ( E ) ) be an L 1 -Carathéodory multi-valued map with S Y , z and let R be a linear continuous mapping from L 1 ( J , ϖ ) into C ( J , ϖ ) . Then the operator
R S Y : C ( J , ϖ ) P c p , c ( C ( J , ϖ ) ) z ( R S Y ) ( z ) = R ( S Y , z ) ,
is a closed graph operator in C ( J , ϖ ) × C ( J , ϖ ) .

4. Main Result: Existence of Solutions

In this section, we provide adequate conditions for the first order of a random system of functional differential Equation (4), to have solutions. We begin by assuming that Y has values that are convex. We define the problem’s solution prior to declaring and demonstrating our conclusion for this case.

The Convex Case

Now we first define the concept of the solution to our problem.
Lemma 3.
Given ( ϖ 1 , ϖ 2 ) D × D , it is said to be solution of (23) if there exists a functions f 1 ( t , x ) , f 2 ( t , x ) such that
( f 1 , f 2 ) L 1 ( [ 0 , ) × Γ , R n ) × L 1 ( [ 0 , ) × Γ , R n ) ,
and
f 1 , f 2 Y 1 ( t , ϖ 1 t ( x ) , ϖ 2 t ( x ) , x ) , Y 2 ( t , ϖ 1 t ( x ) , ϖ 2 t ( x ) , x ) ,
and ( ϖ 1 , ϖ 2 ) = ( f 1 , f 2 ) , with ( ϖ 1 , ϖ 2 ) be a solution of the problem (23), for x Γ
ϖ 1 ( t ) = ϕ 1 ( 0 , x ) A ( A 1 ) + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) + ϕ 1 A , t ( , 0 ] , ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t [ 0 , ) ,
and
ϖ 2 ( t ) = ϕ 2 ( 0 , x ) A ( A 1 ) + 1 A 1 0 f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) + ϕ 2 A , t ( , 0 ] , ϕ 2 ( 0 , x ) A 1 + 1 A 1 0 f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t [ 0 , ) ,
where
lim t ( ϖ 1 ( t ) , ϖ 2 ( t ) ) = ( ϖ 1 , , ϖ 2 , ) ,
if and only if ( ϖ 1 , ϖ 2 ) is a solution of the impulsive boundary value problem
ϖ 1 = f 1 ( t , x ) , a . e t J , t t k , ϖ 2 = f 2 ( t , x ) , a . e t J , t t k , Δ ϖ 1 = I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t = t k , Δ ϖ 2 = I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , A 1 ϖ 1 ϖ 1 , = ϕ 1 , A 2 ϖ 2 ϖ 2 , = ϕ 2 .
Proof. 
Let ( ϖ 1 , ϖ 2 ) be a solution of the impulsive integral Equations (21) and (22), then for t [ 0 , + ) and t t k , k 1 , Z , we have
ϖ 1 = ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) ,
and
ϖ 2 = ϕ 2 ( 0 , x ) A 1 + 1 A 1 0 f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
Thus
( ϖ 1 , ϖ 2 ) = ( f 1 ( s , x ) , f 2 ( s , x ) ) , t [ 0 , ) , t t k , k 1 , Z .
From the definition of ( ϖ 1 , ϖ 2 ) we can prove that
ϖ 1 ( t k + , x ) ϖ 1 ( t k , x ) = I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , ϖ 2 ( t k + , x ) ϖ 2 ( t k , x ) = I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
Finally we prove that
( A 1 ϖ 1 ϖ 1 , , A 2 ϖ 1 x ) = ( ϕ 1 , ϕ 2 ) .
We have
lim t ϖ 1 = ϕ 1 ( 0 , x ) A 1 + A A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) ,
and
ϖ 1 = ϕ 1 ( 0 , x ) A ( A 1 ) + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + ϕ 1 A .
Hence
A ϖ 1 lim t ϖ 1 = ϕ 1 ( 0 , x ) ( A 1 ) + ϕ 1 ϕ 1 ( 0 , x ) A 1 A A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) A A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) = ϕ 1 , t [ 0 , + ) .
Let ( ϖ 1 , ϖ 2 ) be a solution of the problem (23). Then
ϖ 1 = f 1 ( s , x ) , a . e t [ 0 , t 1 ] , t t k .
An integration from 0 to t (here t ( 0 , t 1 ] ) of both sides of the above equality yields
ϖ 1 = ϖ 1 ( 0 , x ) + 0 t f 1 ( s , x ) d s .
If t ( t 1 , t 2 ] , then we have
ϖ 1 = ϖ 1 ( 0 , x ) + 0 t f 1 ( s , x ) d s + I 1 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
We obtain for t [ 0 , + ) that
ϖ 1 = ϖ 1 ( 0 , x ) + 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
Since
( lim t ( ϖ 1 ( t ) , ϖ 2 ( t ) ) = ( ϖ 1 , , ϖ 2 , ) ,
we obtain
ϖ 1 , = ϖ 1 ( 0 ) + 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
Thus
ϖ 1 ( 0 ) = ϖ 1 , 0 f 1 ( s , x ) d s k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) ,
and
ϖ 1 , = A ϖ 1 ( 0 ) ϕ 1 ( 0 , x ) ,
and hence
ϖ 1 ( t ) = ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
We replace (28) in (27), to obtain
ϖ 1 = ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) .
From (28), we have
ϖ 1 = ϕ 1 A + 1 A ϖ 1 ( 0 , x ) + 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) = ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + ϕ 1 A .
Theorem 4.
Suppose the following hypotheses are satisfied:
(H1
The function
Y C 0 ( [ 0 , ) × D × D , P ( R n ) ) ,
is a nonempty, compact, convex, multi-valued map such that:
(a
( t , . ) Y ( t , . ) is measurable;
(b
ϖ 1 Y ( t , ϖ 1 ) is upper semi-continuous for a.e. t [ 0 , )
(H2
There exist bounded measurable functions
P 1 , P 2 C 0 ( Γ , L 1 ( ( 0 , ) , R + ) ) ,
and non-decreasing continuous functions
ψ 1 , ψ 2 C 0 ( R + , ( 0 , + ) ) ,
such that
| Y 2 ( t , ϖ 1 , ϖ , x ) | = sup f 1 Y 1 ( t , ϖ 1 , ϖ 2 , x ) | f 1 ( t ) | p i , ϖ 1 , ϖ 2 D 0 ,
and
| Y 2 ( t , ϖ 1 , ϖ 2 , x ) | = sup f 2 Y 2 ( t , ϖ 1 , ϖ 2 , x ) | f 2 ( t ) | p i , ϖ 1 , ϖ 2 D 0 .
(H3
There exist positive constants c k , k = 1 , such that
| I k i ( x , ϖ 2 ( t k , x ) ) | c k i , ϖ 1 , ϖ 2 D 0 ,
and
k = 1 c k i < ,
for each i 1 , 2 , then problem (4) has a unique random solution on ( , + ) .
Proof. 
Consider the operator
T C 0 ( D × D × Γ , P ( D × D ) ) ,
defined by
T ( x , ϖ 1 , ϖ 2 ) = ( T 1 ( x , ϖ 1 , ϖ 2 ) , t 2 ( x , ϖ 1 , ϖ 2 ) ) , ( ϖ 1 , ϖ 2 ) D × D ,
and
T ( x , ϖ 1 , ϖ 2 ) = { ( h 1 , h 2 ) D × D } ,
given by
h 1 = ϕ 1 ( 0 , x ) A ( A 1 ) + ϕ 1 A + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k ) , x ) , t ( , 0 ] , ϕ 1 ( 0 , x ) A 1 + 1 A 1 0 f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) , t [ 0 , ) ,
and
h 2 = ϕ 2 ( 0 , x ) A ( A 1 ) + 1 A 1 0 f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k ) , x ) + ϕ 2 A , t ( , 0 ] , ϕ 2 ( 0 , x ) A 1 + 1 A 1 0 f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) , x ) ) + 0 t f 2 ( s , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) , x ) ) , t [ 0 , ) ,
where
f i S Y i , u = { f i L 1 ( [ 0 , + ) × Γ , R n ) : f i Y i ( t , ϖ 1 , ϖ 2 , x ) , t J , ϖ 1 , ϖ 2 D } .
Clearly fixed points of the operator T are random solutions of problem (4). For x Γ fixed ( ϖ 1 , ϖ 2 ) D × D , consider
T x C 0 ( D × D , P ( D × D ) ) ,
defined by
T x ( ϖ 1 , ϖ 2 ) = ( T 1 ( x , ϖ 1 , ϖ 2 ) , t 2 ( x , ϖ 1 , ϖ 2 ) ) .
We will prove that T has a fixed point. Let α 1 ( . , . ) , α 2 ( . , . ) D 0 be a functions defined by
α 1 = ϕ 1 ( 0 , x ) , if t [ 0 , + ) ϕ 1 ( t , x ) , if t ( , 0 ] ,
and
α 2 = ϕ 2 ( 0 , x ) , if t [ 0 , + ) ϕ 2 ( t , x ) , if t ( , 0 ] .
Then, it is not difficult to see that ( α 1 , α 2 ) is an element of D × D . Set
( ϖ 1 , ϖ 2 ) = ( z 1 ( t , x ) + α 1 ( t , x ) , z 2 ( t , x ) + α 2 ( t , x ) ) , t ( , + ) .
It is not hard to see that z 1 , z 2 satisfy
z 1 ( t , w ) = z 2 ( t , w ) = 0 , t ( , 0 ] .
If ( ϖ 1 ( . , x ) , ϖ 2 ( . , x ) ) satisfies the integral equation
ϖ 1 ( x , t ) = ϕ 1 ( 0 , x ) A 1 + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) , x ) , x ) ) + 0 t f 1 ( s , ϖ 1 s ( x ) , ϖ 2 s ( x ) , x ) d s + 1 A 1 0 f 1 ( s , ϖ 1 s ( x ) , ϖ 2 s ( x ) , x ) d s + k = 1 I k 1 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) , x ) ) ,
and
ϖ 2 ( x , t ) = ϕ 2 ( 0 , x ) A 1 + 1 A 1 0 f 2 ( s , ϖ 1 s ( x ) , ϖ 2 s ( x ) , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) + 0 t f 2 ( s , ϖ 1 s ( x ) , ϖ 2 s ( x ) , x ) d s + k = 1 I k 2 ( ϖ 1 ( t k , x ) , ϖ 2 ( t k , x ) ) ,
we can decompose ( ϖ 1 ( . , x ) , ϖ 2 ( . , x ) ) ) as
( ϖ 1 , ϖ 2 ) = ( z 1 + α 1 , z 2 + α 2 ) , t [ 0 , + ) ,
which implies that
( ϖ 1 t ( x ) , ϖ 2 t ( x ) ) = ( z 1 ( x ) + α 1 ( x ) , z 2 ( x ) + α 2 ( x ) ) , t [ 0 , + ) ,
and the function z 1 ( . , x ) , z 2 ( . , x ) satisfies
z 1 ( x , t ) = 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) , x ) ) , z 2 ( x , t ) = 0 t f 2 ( s , x ) d s + k = 1 I k 2 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) , x ) ) ,
where
f i Y i ( t , z 1 ( x ) + α 1 ( x ) , z 2 ( x ) + α 2 ( x ) , x ) , a . e t [ 0 , + ) .
Set
D = { z 1 , z 2 D : ( z 1 ( 0 , x ) , z 2 ( 0 , x ) ) = ( 0 , 0 ) } .
Let the operator
P C 0 ( D × D × Γ , P ( D × D ) ) ,
we have, then
( z 1 , z 2 ) ( P 1 ( x , z 1 , z 2 ) , P 2 ( x , z 1 , z 2 ) ) , ( z 1 , z 2 ) D × D ,
with
P ( t , z 1 , z 2 ) ) = { ( ρ 1 , ρ 1 ) D × D } ,
where
ρ 1 = 0 , t ( , 0 ] 0 t f 1 ( s , x ) d s + + k = 1 I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) , t [ 0 , + )
and
ρ 2 = 0 t ( , 0 ] 0 t f 2 ( s , x ) d s + k = 1 I k 2 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) . t [ 0 , + )
Clearly fixed points of the operator P are random solutions of problem (4). For x Γ fixed, consider
P x C 0 ( D × D , P ( D × D ) ) ,
for
( z 1 , z 2 ) D × D ,
by
P x ( z 1 , z 2 ) = ( P 1 ( x , z 1 , z 2 ) , P 2 ( x , z 1 , z 2 ) ) .
Obviously, that the operator T x has a fixed point is equivalent to P x has a fixed point. We will prove that T x verifies the claims of Theorem 3. The proof will be carried out in several steps. First we should prove that P x is completely continuous.
Claim 1.
P x ( z 1 , z 2 ) is convex for each ( z 1 , z 2 ) D 0 × D 0 . Indeed, if ρ 1 1 , ρ 1 2 belong to P 1 ( z 1 , z 2 ) , then there exist
f 1 1 , f 1 2 S Y 1 , z 1 + α 1 , z 2 + α 2 ,
such that, for each t J , we have
ρ 1 i ( t ) = 0 t f 1 i ( s , x ) d s + k = 1 I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) .
Let 0 δ 1 . Then, for each ( J , Γ ) , we have
( δ ρ 1 1 + ( 1 δ ) ρ 1 1 ) = 0 t ( δ f 1 i ( s , x ) + ( 1 δ ) δ ) d s + k = 1 I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) .
Because S Y 1 , z 1 + α 1 , z 2 + α 2 is convex ( Y ( t , z 1 , z 2 ) has convex values), one has
( δ ρ 1 1 + ( 1 δ ) ρ 1 1 ) P 1 ( x , z 1 , z 2 ) .
Similarly, for P 2 , we have
( δ ρ 2 1 + ( 1 δ ) ρ 2 1 ) P 2 ( x , z 1 , z 2 ) .
Claim 2.
P x maps bounded sets into bounded sets in D × D . Indeed, it is enough to show that there exists a positive constant ( l 1 , l 2 ) such that for each ( ρ 1 , ρ 2 ) P x . Let
B p × B q = ( z 1 , z 2 ) D × D : z 1 , z 2 p , q ,
where
z 1 , z 2 = z 1 D , z 2 D .
Let ( z 1 , z 2 ) B p × B q , then for each t [ 0 , ) ,
| ρ 1 | = 0 t f 1 ( s , x ) d s + k = 1 I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) 0 t p 1 ( s , x ) d s + k = 1 c k 1 = l 1 < .
Similarly, for ρ 2 , we have
| ρ 2 | 0 t p 2 ( s , x ) d s + k = 1 c k 2 = l 2 < .
Claim 3.
P x maps bounded sets into equi-continuous sets of D × D . Let B p × B q be a bounded set in D × D as in Step 1 is an equi-continuous set of D × D . Let τ 1 , τ 2 [ 0 , ) such that τ 1 < τ 2 < , and ( z 1 , z 2 ) B p × B q . Then
| ρ i ( τ 2 , x ) ρ i ( τ 1 , x ) | τ 1 τ 2 | f i ( s , z 1 , s ( x ) + α 1 , s ( x ) , z 2 , s ( x ) + α 2 , s ( x ) , x ) | d s + 0 < t < τ 2 τ 1 | I k i ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) | τ 1 τ 2 p i ( s , x ) d s + 0 < t < τ 2 τ 1 c k 1 .
The RHS tends to 0 as τ 2 τ 1 0 . By a similar way we can prove the equi-continuity for N 2 ( B p , B q ) .
As a consequence of Claim 2 and 3, together with the Arzelà–Ascoli theorem, we conclude that
P x : D × D P ( D × D ) ,
is completely continuous.
Claim 4.
P x has a closed graph.
Let ( z 1 n , z 2 n ) be a sequence such that
( z 1 n , z 2 n ) ( z 1 , z 2 ) i n D × D a s n ,
and
ρ i n P 1 ( x , z 1 n , z 2 n ) , ρ i n ρ i a s n .
we shall prove that ρ i P 1 ( x , z 1 , z 2 ) .
Because ρ i n P 1 ( x , z 1 n , z 2 n ) , then there exists f i n S Y i , z 1 n + α 1 , z 2 n + α 2 such that
ρ i n = 0 t f 1 n ( s , x ) d s + k = 1 I k 2 ( z 1 n ( t k , x ) + α 1 ( t k , x ) , z 2 n ( t k , x ) + α 2 ( t k , x ) ) , t J .
We must prove that there exists f i S Y i , z 1 + α 1 , z 2 + α 2 such that
ρ i = 0 t f 1 ( s , x ) d s + k = 1 I k 2 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) , t J .
Consider the linear continuous operator
R : L 1 ( J × Γ , R n ) D × D ,
defined by
R ( f ) ( t ) = 0 t f 1 ( s ) d s , 0 t f 1 ( s ) d s .
From Lemma 2, it follows that R S Y i is a closed graph operator. Moreover, we have that
ρ i n k = 1 I k i ( z 1 n ( t k , x ) + α 1 ( t k , x ) , z 2 n ( t k , x ) + α 2 ( t k , x ) ) R ( S Y i , z 1 + α 1 , z 2 + α 2 ) .
Because ( z 1 n , z 1 n ) ( z 1 , z 1 ) and ρ i n ρ i there is f i S Y i , z 1 + α 1 , z 2 + α 2 such that
ρ i = 0 t f 1 ( s , x ) d s + k = 1 I k 2 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) , t J .
Therefore, P x is completely continuous.
Claim 5.
There exist a priori bounds on solutions
M = { ( z 1 , z 2 ) D × D : ( z 1 , z 2 ) λ ( x ) P x ( z 1 , z 2 ) , λ ( x ) ( 0 , 1 ) } ,
is bounded for some measurable function λ : Γ R . Then
z 1 λ ( x ) P 1 ( x , z 1 , z 2 ) , z 2 λ ( x ) P 2 ( x , z 1 , z 2 ) .
For some 0 < λ ( x ) < 1 , we have
| z 1 | | λ ( x ) | 0 t f 1 ( s , z 1 , s ( x ) + α 1 , s ( x ) , z 2 , s ( x ) + α 2 , s ( x ) , x ) d s + 0 < t k < t I k 1 ( z 1 ( t k , x ) + α 1 ( t k , x ) , z 2 ( t k , x ) + α 2 ( t k , x ) ) 0 t p 1 ( s , x ) d s + k = 1 c k 1 .
Similarly
| z 2 | 0 t p 2 ( s , x ) d s + k = 1 c k 2 .
By (39), we have
| z 1 | + | z 2 | i = 1 2 0 t p i ( s , x ) d s + i = 1 2 k = 1 c k i .
This implies that for each t [ 0 , ) and there exist positive constants β > 0 such that
z 1 D 0 + z 2 D i = 1 2 0 p i ( s , x ) d s + i = 1 2 k = 1 c k i β .
Finally from (40) there exists a constant β 1 , β 2 > 0 such that
z 1 D β 1 and z 2 D β 2 .
Set
U = { ( z 1 , z 2 ) D × D : ( z 1 D , z 1 D ) < ( β 1 + 1 , β 2 + 1 ) } ,
P x : U ¯ P ( D × D ) is completely continuous. From the choice of U, there is no z 1 , z 2 U such that ( z 1 , z 2 ) λ ( x ) P x ( z 1 , z 2 ) , for some λ ( x ) ( 0 , 1 ) . Thus by Theorem 3 the operator P x has at least one fixed ( z 1 , z 2 ) in U. Hence T x has a fixed point ( ϖ 1 , ϖ 2 ) , which is a random solution to problem (4).

5. Conclusions

This work falls within a series of related research carried out by the same authors, and many results were achieved using new recent methods related to iterative theory and developing some techniques to ensure the solutions exist according to different requirements imposed by the random action and delay.
We sought to give as complete and objective studies as possible of the main result in coupled random first-order impulsive differential equations with infinite delay. However, it is surely true that the works that lies in the field of scientific interests of this model can be covered in somewhat more detail. Examples of genuine processes and phenomena explored in physics, chemical technology, population dynamics, biotechnology, and economics are described by delayed impulsive differential systems with the presence of new random properties. The novelties of our contribution are follows:
1.
Applying a novel random fixed-point theorem to a system of impulsive random differential equations was our primary objective.
2.
We provided a random application of the separable vector-valued Banach space Leray–Schauder fixed-point theorem in nonlinear case.
Extending these results to consider the question of stability (qualitative studies) will make it possible to advance the study in this direction, which will be our next project, see [30,31,32,33,34].

Author Contributions

Conceptualization, A.M., F.Z.L., M.F., A.B.C. and K.B.; Methodology, A.M., F.Z.L., M.F., A.B.C. and K.B.; Writing—original draft, A.M., F.Z.L., M.F., A.B.C. and K.B.; Writing—review & editing, A.M., F.Z.L., M.F., A.B.C., M.B. and K.B.; project administration, A.M. and M.B. All authors have read and agreed to the published version of the manuscript.

Funding

This research was funded by King Khalid University through large research project under grant number R.G.P.2/252/44.

Data Availability Statement

No new data were created or analyzed in this study. Data sharing is not applicable to this article.

Acknowledgments

The authors extend their appreciation to the Deanship of Scientific Research at King Khalid University for funding this work.

Conflicts of Interest

Authors declare that they have no conflict of interest.

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Moumen, A.; Ladrani, F.Z.; Ferhat, M.; Benaissa Cherif, A.; Bouye, M.; Bouhali, K. Existence Result for Coupled Random First-Order Impulsive Differential Equations with Infinite Delay. Fractal Fract. 2024, 8, 10. https://doi.org/10.3390/fractalfract8010010

AMA Style

Moumen A, Ladrani FZ, Ferhat M, Benaissa Cherif A, Bouye M, Bouhali K. Existence Result for Coupled Random First-Order Impulsive Differential Equations with Infinite Delay. Fractal and Fractional. 2024; 8(1):10. https://doi.org/10.3390/fractalfract8010010

Chicago/Turabian Style

Moumen, Abdelkader, Fatima Zohra Ladrani, Mohamed Ferhat, Amin Benaissa Cherif, Mohamed Bouye, and Keltoum Bouhali. 2024. "Existence Result for Coupled Random First-Order Impulsive Differential Equations with Infinite Delay" Fractal and Fractional 8, no. 1: 10. https://doi.org/10.3390/fractalfract8010010

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